how might an enzyme speed up a certain chemical reaction? 1 point by binding to the substrate(s) in the active site in an optimal orientation by creating an environment suitable for catalysis (e.g. acidic / basic residues) by stabilising the highest energy part of the reaction (transition state) by expelling water/unwanted reactants from the active site all of the above

Answer:

please provide more información or a photo

Explanation:

Of you want me to hwlp you please have more infor like a picture

The number of grams of oxygen required is 94.9 g, under the condition that it is used to  burn 28. 8 g of ammonia (NH₃)

NH₃ + 7O₂ → 4NO₂ + 6H₂O,

then the correct answer for the required question is Option B.

Now, the balanced chemical equation for the reaction of ammonia (NH₃) and oxygen (O₂) to create nitrogen dioxide (NO₂) and water (H₂O) is

4NH₃ + 7O₂ → 4NO₂ + 6H₂O

The given molar mass of NH₃ is 17.0305 g/mol and that of O₂ is 31.998 g/mol.
In order to  find out how many grams of O₂ are required to burn 28.8 g of NH₃, we have to first balance the equation:

4 NH₃+ 7O₂ → 4NO₂ + 6H₂O
Then there are  4 moles of NH₃, we need 7 moles of O₂.
Hence, molar mass of NH₃ is 17.0305 g/mol, so we can change 28.8 g of NH₃ to moles

28.8 g NH₃ × (1 mol NH₃/17.0305 g NH₃)
= 1.69 mol NH₃

Now we have to apply  stoichiometry to evaluate  how many moles of O₂ are required

1.69 mol NH₃ × (7 mol O₂/4 mol NH₃)
= 2.95 mol O₂

Therefore, we can convert moles of O₂ to grams:

2.95 mol O₂ × (31.998 g O₂/1 mol O₂)
= 94.9 g
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The complete question is
How many grams of oxygen (O2) is required to burn 28. 8 g of ammonia (NH3)?4NH3 + 7O2 → 4NO2 + 6H2O
Molar Mass
NH3=17. 0305 g/mol
O2=31. 998 g/mol
NO2=46. 0055 g/mol
H2O=18. 0153 g/mol
a)15. 3 g
b)94. 9 g
c)54. 1 g
d)108 g

The diagram illustrates the relationship between energy and temperature in a sample of water.

It shows that as energy is added, the temperature of the water increases until it reaches a point where the water changes state, demonstrating the importance of understanding the thermal properties of water in various scientific fields.

The diagram that shows the temperature of a sample of water as heat is added is an illustration of the thermal properties of water. As energy is added to the system, the temperature of the water increases until it reaches a point where it begins to change state.
The process of adding energy to the water is called heating, and the energy that is added is called heat. The amount of heat required to raise the temperature of water depends on its mass, specific heat capacity, and the temperature difference between the initial and final temperatures.
In the diagram, the temperature of the water increases gradually as heat is added until it reaches a point where the water begins to boil. At this point, the temperature of the water remains constant even as more heat is added, and the energy is used to break the bonds between the water molecules, resulting in the conversion of liquid water to steam.

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This indicates that the system's energy drops while the energy of the environment grows. As a result, the ultimate temperature is projected to be greater than the beginning temperature of 28 degrees Celsius.

The process sends heat into the environment since it is exothermic. The heat produced by the reaction is transferred to the surrounding environment, raising the temperature.

This is due to the fundamental rule of thermodynamics, which states that energy cannot be created or destroyed, but only moved from one form to another. In this case, the energy released by the reaction is transferred to the surrounding environment as heat energy, causing the temperature to rise.

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It would take 0.0252 moles of HCl to neutralize the sodium hydroxide produced.

The balanced equation for the reaction of sodium with water is:

[tex]2Na(s) + 2H2O(l) → 2NaOH(aq) + H2(g)[/tex]

From this equation, we can see that 2 moles of NaOH are produced for every mole of Na that reacts.

The molar mass of Na is 22.99 g/mol. Therefore, 0.29 g of Na represents:

0.29 g / 22.99 g/mol = 0.0126 mol Na

So, this amount of sodium will produce:

2 x 0.0126 mol NaOH = 0.0252 mol NaOH

Since NaOH is a strong base, it will completely react with HCl in a 1:1 ratio according to the equation:

[tex]NaOH(aq) + HCl(aq) → NaCl(aq) + H2O(l)[/tex]

So, 0.0252 mol of NaOH will react with 0.0252 mol of HCl.

Therefore, it would take 0.0252 moles of HCl to neutralize the sodium hydroxide produced.

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Answer:

Activation Energy

Explanation:

I know you dont need this

Answer:

only student B

Explanation:

five electrons int eh valence shell of nitrogen atoms

The reaction is a decomposition reaction

The given reaction is not a redox (oxidation-reduction) reaction because there is no change in oxidation number of any of the atoms in the reaction.

Also, it is not a double replacement reaction as there are no ions or compounds being exchanged between the reactants.

This is a decomposition reaction, where one compound (CF4) is breaking down into two simpler substances (C and F2).

A decomposition reaction is a type of chemical reaction where a single compound breaks down into two or more simpler substances. In a decomposition reaction, a compound is broken down into its constituent elements or simpler compounds.

The reaction can be represented by a chemical equation where the reactant is the compound that is breaking down, and the products are the simpler substances formed as a result of the reaction.

The general formula for a decomposition reaction is:

AB → A + B

where AB is the compound that is decomposing, and A and B are the simpler substances formed as a result of the reaction.

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The covalent radius of atom X in an XY molecule with a bond length of 212 and covalent radius of Y atom being 93 is 119.

To find the covalent radius of atom X, we need to understand that the bond length of an XY molecule is equal to the sum of the covalent radii of atoms X and Y. We can represent this relationship using the formula: bond length = covalent radius of X + covalent radius of Y.

Given that the bond length of the XY molecule is 212, and the covalent radius of Y is 93, we can use the formula to find the covalent radius of X:

212 = covalent radius of X + 93

To find the covalent radius of X, we can simply subtract the covalent radius of Y from the bond length:

covalent radius of X = 212 - 93

covalent radius of X = 119

So, the covalent radius of atom X is 119.

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7.65 moles of gas at STP would occupy a volume of approximately 171.36 liters.

To find out how many liters are in 7.65 moles of a gas, you will need to use the Ideal Gas Law equation, which is:

PV = nRT

In this equation:
P = pressure of the gas
V = volume of the gas in liters
n = number of moles of the gas
R = ideal gas constant (0.0821 L atm/mol K)
T = temperature in Kelvin

However, since we are not given the values for pressure (P) and temperature (T), we cannot calculate the exact volume (V) in liters for 7.65 moles of a gas.

If we assume standard temperature and pressure (STP) conditions, which are 0°C (273.15 K) and 1 atm, we can use the molar volume of a gas at STP, which is 22.4 liters/mol.

To calculate the volume in liters at STP, you can use the following formula:

V = n × molar volume at STP

Now, plug in the values:

V = 7.65 moles × 22.4 liters/mol

V ≈ 171.36 liters

So, under STP conditions, 7.65 moles of gas would be approximately 171.36 liters.

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The mass (in grams) of quick lime, CaO that can be produced from the reaction is 560 g

First, we shall write the balanced equation for the reaction. This is given below:

CaCO₃ -> CaO + CO₂

Now, we shall obtain the mass of quick lime, CaO produced from the reaction can be obtain as illustrated below:

CaCO₃ -> CaO + CO₂

From the balanced equation above,

100 g of limestone, CaCO₃ decomposed to produce 56 g of quick lime, CaO

Therefore,

1 Kg (i.e 1000 g) of limestone, CaCO₃ will decompose to produce = (1000 × 56) / 100 = 560 g of quick lime, CaO

Thus, the mass of quick lime, CaO produced is 560 g

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Answer: it's an integral component of steel

Explanation: it's also an economic essential to US growth and is used for transportation, energy, and construction

if the unknown solution is mixed with potassium carbonate, the reaction will proceed differently depending on whether the unknown solution is strontium nitrate or magnesium nitrate.

Mixing the unknown solution with potassium sulfate will not provide any useful information to identify whether the unknown solution is strontium nitrate or magnesium nitrate. This is because neither strontium nor magnesium sulfate has distinctive properties that allow them to be easily distinguished from one another.

However, When mixed with strontium nitrate, potassium carbonate will form a white precipitate of strontium carbonate, while no reaction will occur when mixed with magnesium nitrate. Therefore, the presence of a white precipitate after mixing with potassium carbonate indicates that the unknown solution is strontium nitrate.

In summary, to identify whether the unknown solution is strontium nitrate or magnesium nitrate, the solution should be mixed with potassium carbonate. If a white precipitate forms, the solution is strontium nitrate. If no reaction occurs, the solution is magnesium nitrate. Mixing the unknown solution with potassium sulfate will not provide any useful information.

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The mass of iron(III) sulfate comes out to be 899.73 g, the calculations are shown below.

Considering, the moles of Fe₂(SO₄)₃ to be 2.25 moles.

Molar mass of Fe₂(SO₄)₃ = 399.88 g/mol.

To calculate the number of moles, the below formula is used-

Number of moles = Mass/molar mass

Substituting the known values in the above equation as follows-

2.25 moles = Mass / 399.88 g/mol

Mass = 2.25 moles  x 399.88 g/mol

         = 899.73 g

Therefore, the mass of iron(III) sulfate comes out to be 899.73 g.

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Answer:

7.250 x 1094 atoms of Magnesium, Mg is equal to 0.008038 grams.

I hope this helps you

a. The empirical formula of the compound is [tex]CH_2O.[/tex] b. Moles of oxygen is 3.344 mol and c. The molecular formula of the compound is [tex]C_6H_12O_6[/tex].

To determine the empirical formula of the compound:

Convert the mass of each element to moles using its molar mass:

Moles of carbon = 48.38 g / 12.011 g/mol = 4.030 mol

Moles of hydrogen = 6.74 g / 1.008 g/mol = 6.690 mol

Moles of oxygen = 53.5 g / 15.999 g/mol = 3.344 mol

Divide each number of moles by the smallest number of moles to get the simplest whole-number ratio of atoms:

Carbon: 4.030 mol / 3.344 mol = 1.205 ≈ 1

Hydrogen: 6.690 mol / 3.344 mol = 1.999 ≈ 2

Oxygen: 3.344 mol / 3.344 mol = 1

Therefore, the empirical formula of the compound is [tex]CH_2O.[/tex]

To determine the molecular formula of the compound:

Calculate the empirical formula mass:

Mass of  [tex]CH_2O.[/tex] = 12.011 g/mol + 2(1.008 g/mol) + 15.999 g/mol = 30.026 g/mol

Empirical formula mass x n = Molar mass

n = Molar mass / Empirical formula mass = 180.15 g/mol / 30.026 g/mol = 6.000

Multiply each subscript in the empirical formula by n to get the molecular formula:

Molecular formula = [tex](CH_2O)_6[/tex] =  [tex]C_6H_12O_6[/tex]

Therefore, the molecular formula of the compound is  [tex]C_6H_12O_6[/tex]

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For example, the chemical formula for water is H₂O. This tells us that there are two hydrogen atoms (H) and one oxygen atom (O) in each molecule of water. To count the number of atoms in a chemical formula, we can use the subscripts (the numbers that come after each element symbol) to determine how many atoms of each element are present. For example, in the chemical formula NaCl (which represents salt), there is one sodium (Na) atom and one chlorine (Cl) atom in each molecule.

Let us discuss this in detail. To count atoms and elements in a chemical formula, you need to understand the following terms:

- Atoms: The basic unit of a chemical element, consisting of protons, neutrons, and electrons.
- Elements: A substance that cannot be broken down into simpler substances, consisting of only one type of atom.
- Chemical Formula: A representation of a substance using symbols for its constituent elements and numbers to indicate the ratio of atoms in the compound.

Now, let's count the atoms and elements in a given chemical formula, for example, H₂O (water):

1. Identify the elements in the formula: In this case, we have two elements - Hydrogen (H) and Oxygen (O).
2. Count the atoms of each element: The subscript number next to each element symbol indicates the number of atoms of that element in the compound. For Hydrogen (H), the subscript is 2, meaning there are 2 Hydrogen atoms. For Oxygen (O), there is no subscript, which means there is only 1 Oxygen atom (when no subscript is present, it is understood to be 1).

So, in the chemical formula H₂O, there are 2 Hydrogen atoms and 1 Oxygen atom, for a total of 3 atoms.

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The method used to find the volume of acid that reacts with a known volume of alkali is called acid-base titration.

In this method, a solution of known concentration (the titrant) is slowly added to a solution of unknown concentration (the analyte) until the reaction between the two is complete.

The point at which the reaction is complete is determined using an indicator or by measuring the pH of the solution. The volume of titrant required to reach this point is used to calculate the concentration of the analyte solution.

The method is widely used in analytical chemistry to determine the concentration of acids, bases, and other reactive substances in solution.

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The ice cream activity of integration is that it demonstrates how integration can be used to find the area under a curve or the total quantity of a certain variable, such as the amount of ice cream consumed.

This activity involves plotting the ice cream consumption over time on a graph, with the x-axis representing time and the y-axis representing the amount of ice cream consumed. The curve formed by the data points represents the rate of ice cream consumption.

The goal of this activity is to find the total amount of ice cream consumed during a specific time interval. To do this, you can use integration, which is a mathematical technique for finding the area under a curve.

By integrating the function that describes the curve, you can determine the total ice cream consumed during the given time period. This activity helps to illustrate the concept and application of integration in real-life situations.

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The pH of a 6.3 x [tex]10^{-8[/tex]M solution of H₃O+ is approximately 7.20.

A 0.25 M solution of H₃O+ is not a strong acid, since it is not a single acid that completely dissociates in water.

A 6.3 x [tex]10^{-8[/tex] M solution of H₃O+  is not a strong acid, since it is a very weak acid with a very low concentration of H₃O+ ions.

The pH of a 0.25 M solution of H₃O+ can be calculated using the formula:

pH = -log[H₃O+]

where [H₃O+] is the concentration of H₃O+ ions in moles per liter (M).

In this case, [H3O+] = 0.25 M,

pH = -log(0.25) = 0.602

Therefore, the pH of a 0.25 M solution of H₃O+ is approximately 0.602.

The pH of a 6.3 x [tex]10^{-8[/tex] M solution of H₃O+ can be calculated using the same formula:

pH = -log[H₃O+]

In this case, [H₃O+] = 6.3 x [tex]10^{-8[/tex]M, so we have:

pH = -log(6.3 x [tex]10^{-8[/tex]) = 7.20

Therefore, the pH of a 6.3 x [tex]10^{-8[/tex] M solution of H₃O+ is approximately 7.20.

There is no information given for question 3.

A strong acid is an acid that completely dissociates in water to produce H₃O+  ions. The most common example of a strong acid is hydrochloric acid (HCl).

Looking at the given solutions:

A 0.25 M solution of H₃O+  is not a strong acid, since it is not a single acid that completely dissociates in water.

A 6.3 x [tex]10^{-8[/tex] M solution of H₃O+  is not a strong acid, since it is a very weak acid with a very low concentration of H₃O+  ions.

Therefore, neither of the given solutions is a strong acid.

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During a solar eclipse, the Moon is blocking the light from the Sun so a shadow appears on the Earth.

What is Solar eclipse?

A solar eclipse occurs when the Moon passes between the Sun and the Earth, and as a result, the Moon casts a shadow on the Earth's surface. This happens only during a New Moon phase, when the Moon is on the same side of the Earth as the Sun and its shadow falls on the Earth's surface.

There are two types of shadows that the Moon casts on the Earth during a solar eclipse: the umbra and the penumbra. The umbra is the darker central region of the shadow where the Sun is completely blocked by the Moon, while the penumbra is the lighter outer region where the Sun is only partially blocked by the Moon.

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An expert might question the proposed mechanism step due to:
1. Lack of reaction conditions
2. Lack of experimental evidence
3. Thermodynamic feasibility
4. Kinetic feasibility
5. Stereochemical considerations.

an expert might question the proposed step of the mechanism:

1. Lack of reaction conditions: The expert may question the proposed mechanism step because there is no mention of the reaction conditions. Without knowing the reaction conditions, it is impossible to predict whether the proposed mechanism step is feasible or not.

2. Lack of experimental evidence: The expert may question the proposed mechanism step if there is no experimental evidence to support it. Experimental evidence is necessary to validate any proposed mechanism step.

3. Thermodynamic feasibility: The expert may question the proposed mechanism step if it violates the laws of thermodynamics. The proposed step should be energetically favorable and should not require a large input of energy.

4. Kinetic feasibility: The expert may question the proposed mechanism step if it violates the laws of kinetics. The proposed step should be consistent with the rate of the overall reaction.

5. Stereochemical considerations: The expert may question the proposed mechanism step if it violates stereochemical considerations. The proposed step should be consistent with the observed stereochemistry of the reaction products.

These are just a few possible reasons why an expert might question the proposed step of the mechanism.
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The increase in temperature of the steam if it absorbs 800 kJ of heat energy is 653.6°C

The specific heat capacity is the amount of thermal energy required to raise the temperature of a system by one temperature unit. The increase in temperature of a metal can be calculated using the following expression;

Q = mc∆T

Where;

800,000 = 720 × 1.7 × ∆T

800000 = 1,224∆T

∆T = 653.6°C

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The mass in grams of 3.12 moles of [tex]Ca(NO_3)_2[/tex] is approximately 511.52 g.

The molar mass of [tex]Ca(NO_3)_2[/tex] can be calculated by adding up the atomic masses of its constituent atoms. Ca has a molar mass of 40.08 g/mol, N has a molar mass of 14.01 g/mol, and O has a molar mass of 16.00 g/mol. Therefore, the molar mass of [tex]Ca(NO_3)_2[/tex] can be calculated as:

Molar mass = 1(40.08 g/mol) + 2(14.01 g/mol) + 6(16.00 g/mol)

Molar mass = 164.09 g/mol

To find the mass in grams of 3.12 moles of [tex]Ca(NO_3)_2[/tex], we can use the following equation:

Mass = moles × molar mass

Substituting the given values, we get:

Mass = 3.12 mol × 164.09 g/mol

Mass = 511.5168 g

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Start with 2-methylpropene ([tex]CH_3CHCH_2CH_3[/tex]) and perform an acid-catalyzed hydration reaction to form 3-methyl-2-butanol ([tex]CH_3CHCH(OH)CH_3[/tex]).

Hydration is the process of providing water to the body and replenishing the fluids lost through physical activity, sweating, or illness. Hydration is essential for our bodies to function properly and also to maintain a healthy lifestyle. Hydration helps our bodies regulate temperature, lubricate and cushion joints, protect organs and tissues, and help to rid our bodies of waste. It is important to stay hydrated by drinking plenty of water throughout the day, especially when out in the heat, exercising, or sick. Additionally, increasing your intake of fruits and vegetables can help to boost hydration, as they contain high amounts of water and electrolytes.

Then perform a nucleophilic substitution reaction with ammonia to form 3-amino-2-methylbutyl alcohol ([tex]CH_3CHCH(NH_2)CH_3[/tex]). Finally, perform a dehydration reaction to form 3-amino-2-methylbut-2-ene [tex](CH_3CHCH(NH_2)CH=CH_2).[/tex]

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1.5 mole of Ca(OH)[tex]_2[/tex]  are needed to neutralize 2 moles of HCI.  The mole idea is a useful way to indicate how much of a substance there is.

The mole idea is a useful way to indicate how much of a substance there is. Any measurement can be divided into two components: the magnitude in numbers and the units in which the magnitude is expressed. For instance, the magnitude is "2" and the unit is "kilogramme" when a ball's mass is determined to be 2 kilogrammes.

Ca(OH)[tex]_2[/tex] + 2HCl → CaCl[tex]_2[/tex] + 2H[tex]_2[/tex]O

1 mole of Ca(OH)[tex]_2[/tex]  are needed to neutralize 2 moles of HCI.

so, 1.5 mole of Ca(OH)[tex]_2[/tex]  are needed to neutralize 2 moles of HCI.

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The number of moles in 1.16 × 10³g of Fe₂O₃ is 7.26 moles.

The number of moles in a substance can be calculated by dividing the mass of the substance by its molar mass as follows:

no of moles = mass ÷ molar mass

According to this question, 1.16 × 10³ grams of iron (II) oxide is given. The molar mass of this compound is 159.69 g/mol.

no of moles in Fe₂O₃ = 1160g ÷ 159.69g/mol = 7.26 moles.

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The weight/volume percent concentration of the diluted solution is 15%.

The initial solution is a 30.0% (w/v) solution, which means that 30.0 grams of vitamin C is dissolved in 100 mL of the solution. Therefore, the amount of vitamin C in the initial solution is:

30.0% (w/v) = 30.0 g / 100 mL = 0.3 g/mL

The initial solution is then diluted to a final volume of 200 mL. Since the amount of vitamin C in the solution remains constant, we can use the following equation to calculate the final concentration:

CiVi = CfVf

where Ci and Vi are the initial concentration and volume, and Cf and Vf are the final concentration and volume.

We can rearrange the equation to solve for the final concentration:

Cf = (CiVi) / Vf

Substituting the values, we get:

Cf = (0.3 g/mL x 100 mL) / 200 mL

Cf = 0.15 g/mL

Finally, we can convert the concentration to weight/volume percent by multiplying by 100:

weight/volume percent = Cf x 100%

weight/volume percent = 0.15 g/mL x 100%

weight/volume percent = 15%

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An endothermic reaction is one that absorbs heat from its surroundings, resulting in an increase in the system's internal energy.

Therefore, the enthalpy change associated with an endothermic reaction is positive. The energy required to break the bonds in the reactants is greater than the energy released when new bonds are formed in the products, resulting in a net absorption of energy.

The enthalpy change is a measure of the heat energy released or absorbed during a chemical reaction, and it is often used to determine whether a reaction is exothermic or endothermic.

In the case of an endothermic reaction, the products have more internal energy than the reactants, and the enthalpy change is positive.

Some examples of endothermic reactions include melting ice, evaporating water, and photosynthesis. In all of these reactions, heat is absorbed from the surroundings, resulting in a positive enthalpy change.

Understanding the enthalpy change associated with a reaction is important in fields such as thermodynamics, chemical engineering, and materials science.

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To solve for the specific heat capacity of aluminum, we can use the formula:
q = m × c × ΔT, Where q is the heat transferred, m is the mass, c is the specific heat capacity, and ΔT is the change in temperature.

First, we need to calculate the heat transferred from the aluminum to the water:

q = mAl × cAl × ΔTAl
q = (3.90 g) × cAl × (28.6°C - 99.3°C)
q = -978 J

Note that we get a negative value for q because heat is transferred from the aluminum to the water, so the aluminum loses heat.

Next, we can calculate the heat gained by the water:

q = mwater × cwater × ΔTwater

q = (10.0 g) × cw × (28.6°C - 22.6°C)
q = 240 J

Setting these two equations equal to each other, we can solve for the specific heat capacity of aluminum:

mAl × cAl × ΔTAl = mwater × cwater × ΔTwater
cAl = (mwater × cw × ΔTwater) / (mAl × ΔTAl)
cAl = (10.0 g) × (4.184 J/g·°C) × (28.6°C - 22.6°C) / [(3.90 g) × (99.3°C - 28.6°C)]
cAl = 0.900 J/g·°C

Therefore, the specific heat capacity of aluminum is 0.900 J/g·°C.

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