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8
Which equation could be used to solve for mº?
49⁰
32°
A 49° +32° + m² = 180°
B 49° +32° + m² = 90°
c) 49° +32° = mᵒ
(D) 49 = 32° +m
mº

The probability that the next person will purchase more than one costume as a percent to the nearest whole number is 3%

.Out of the total 80 + 32 + 3 = 115 visitors, 80 did not purchase any costumes and 32 purchased exactly one costume. This means that the remaining 3 visitors purchased more than one costume.

Therefore, the probability that the next person will purchase more than one costume is 3/115, which is approximately 0.0261.

To express this as a percentage to the nearest whole number, we need to multiply by 100 and round to the nearest integer. Thus, the answer is:

0.0261 × 100 ≈ 3%

Therefore, the probability that the next person will purchase more than one costume is approximately 3%.

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Answer:

( x - 5 )

Hope this helps!

Step-by-step explanation:

[tex]2x^{2} -7x-15[/tex] can factor into ( 2x + 3 ) ( x - 5 ).

( 2x + 3 ) ( x - 5 ) = ( cross multiply ) : [tex]2x^{2} -10x + 3x - 15[/tex] = [tex]2x^{2} -7x-15[/tex].

We have shown that P(F) is the direct sum of W1 and W2.

What is a polynomial?

a polynomial is an expression consisting of variables (also called indeterminates) and coefficients, that involves only the operations of addition, subtraction, multiplication, and non-negative integer exponentiation of variables.

To prove that P(F) is the direct sum of W1 and W2, we need to show two things: first, that every polynomial in P(F) can be written as a sum of a polynomial in W1 and a polynomial in W2, and second, that this decomposition is unique.

Let's begin by showing that P(F) can be written as the direct sum of W1 and W2. Consider an arbitrary polynomial f(x) in P(F). We can write it as a sum of even and odd terms as follows:

f(x) = [f(x) + f(-x)]/2 + [f(x) - f(-x)]/2

The first term on the right-hand side is even, while the second term is odd. Let's define g(x) = [f(x) - f(-x)]/2 and h(x) = [f(x) + f(-x)]/2. Note that g(x) is odd and h(x) is even. Thus, we have expressed f(x) as a sum of an even polynomial h(x) and an odd polynomial g(x).

To show that this decomposition is unique, suppose that f(x) can be written in two ways as a sum of an even polynomial and an odd polynomial:

f(x) = h1(x) + g1(x) = h2(x) + g2(x)

where h1(x) and h2(x) are even polynomials, and g1(x) and g2(x) are odd polynomials. Then we have:

[h1(x) - h2(x)] = [g2(x) - g1(x)]

Since h1(x) - h2(x) is even, and g2(x) - g1(x) is odd, we have:

[h1(x) - h2(x)] = 0 and [g2(x) - g1(x)] = 0

This implies that h1(x) = h2(x) and g1(x) = g2(x), so the decomposition is unique.

Therefore, we have shown that P(F) is the direct sum of W1 and W2.

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Answer: 4y^2y-80+y^2/4y

Step-by-step explanation:

The correct statements are:

Explanation:

The function f(x) represents the total amount of money that Mailani has saved after x years. The first term 500 represents the initial amount she saved in the box under her bed, and the second term (1+0.04)^x represents the amount she deposited into the savings account, which earns an interest rate of 4% compounded annually. The third term +200 represents the additional amount she deposited every year into the savings account.

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Full question:

Mailani saves some money in a box under her bed. She deposits an additional amount into a savings account where it earns interest compounded annually. . This situation can be modeled by the function  

[tex]f(x)= 500(1+0.04)^x+200[/tex]

Which statements are true? Select all that apply.

After answering the presented question, we can conclude that As a result, the average monthly rate of change in price during the housing bubble was $2,000.

The term "average rate" can have different meanings depending on the context in which it is used. In general, it refers to the amount of change that occurs over a certain period of time, divided by the length of that time period. Here are a few examples of how the term might be used in different fields.

The average monthly rate of change in price can be estimated by dividing the total price change by the number of months:

(final price - beginning price) / number of months = average rate of change

The beginning price was $240,000, the final price was $276,000, and the time duration was 18 months in this example. Hence, using these data, we can calculate the average rate of change as:

(276000 - 240000) / 18 = 36000 / 18 = 2000 Average rate of change

As a result, the average monthly rate of change in price during the housing bubble was $2,000.

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Answer: 44.64ft^2

Step-by-step explanation:

Triangle 1:
A = 1/2 x 5.3 x 7.2
A = 19.08

Triangle 2:
A = 1/2 x 7.1 x 7.2
A = 25.56

25.56 + 19.08 = 44.64
Total area of triangles = 44.64ft^2

Step-by-step explanation:

using Pythagoras theorem

Answer:

4² + r² = (2+ r)²

16 + r² = 4 + 4r + r²

12 = 4r

r = 3

The actual selling price of the camera after the 25% discount is $345.

The amount received by the buyer is the selling price of a product or service. Although the seller sets the price, a number of variables affect how the seller arrives at that particular figure. Depending on the seller's discretion, different customers may pay different prices for the same good or service.

If the normal price of the camera is $460, a 25% reduction in price would be:

25% of $460 = 0.25 x $460 = $115

This means the reduction in price when buying the camera duty-free is $115.

So the actual selling price of the camera after the discount is:

$460 - $115 = $345

Therefore, the actual selling price of the camera after the 25% discount is $345.

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Answer:

To find the estimated standard error for the sample mean, we need to use the formula:

SE = s/√n

where s is the sample standard deviation and n is the sample size.

However, we are not given the sample standard deviation, but we are given the sum of squares (SS). We can use this to find the sample variance (s^2) and then take the square root to find the sample standard deviation.

For a sample size of n = 9, the degrees of freedom (df) are:

df = n - 1 = 9 - 1 = 8

Using the formula for the sample variance:

s^2 = SS/df = 1152/8 = 144

Taking the square root, we find the sample standard deviation:

s = √144 = 12

Now we can find the estimated standard error:

SE = s/√n = 12/√9 = 4

Therefore, the estimated standard error for the sample mean is 4.

Answer:

To find the estimated standard error for the sample mean, we need to divide the sample standard deviation by the square root of the sample size. However, we are given the sum of squares (SS), not the sample standard deviation, so we first need to calculate the sample variance. The formula for the sample variance is: s^2 = SS / (n - 1) where s^2 is the sample variance, SS is the sum of squares, and n is the sample size. Using the given values, we have: s^2 = 1152 / (9 - 1) = 144 Now we can find the estimated standard error: SE = s / sqrt(n) where SE is the estimated standard error, s is the sample standard deviation, and n is the sample size. Since s = sqrt(s^2), we have: SE = sqrt(s^2

The quadratic function's equation, when given the numbers in the table, can be found to be f(x) = x^2 - 5x + 6.

We are given a table of values and need to find the quadratic function in standard form: f(x) = ax^2 + bx + c. Let's use the points (-6, 72), (-4, 42), and (-3, 30).

For point (-6, 72):

72 = a(-6)^2 + b(-6) + c

For point (-4, 42):

42 = a(-4)^2 + b(-4) + c

For point (-3, 30):

30 = a(-3)^2 + b(-3) + c

Let's use the elimination method.

1 - 3) 42 = 27a - 3b

2 - 3) 12 = 7a - b

b = 7a - 12

Substitute this expression for b into the first equation:

42 = 27a - 3(7a - 12)

42 = 27a - 21a + 36

6 = 6a

a = 1

Now that we know a = 1, let's find b:

b = 7(1) - 12

b = -5

Finally, let's find c by substituting a and b into any of the original equations. We'll use the first one:

72 = 36(1) - 6(-5) + c

72 = 36 + 30 + c

6 = c

So, the quadratic function in standard form is:

f(x) = x^2 - 5x + 6

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Answer:

Step-by-step explanation:

[tex]\frac{275}{8}=34,375[/tex]

Answer: (D) 12 to 4

Step-by-step explanation:

        First, we will find the number of people waiting in line for each activity.

➜ Bumper cars is 12

➜ Slingshot is 4

        Next, we will create our ratio. This is asking for Bumper cars to Slingshot, so Bumper cars is first with Slingshot second.

➜ 12 to 4

Answer: To find the value of f(x) for a given value of x, you need to substitute that value of x into the equation and simplify.

For example, if you want to find f(2), you would substitute x=2 into the equation:

f(x) = 6 + 3x

f(2) = 6 + 3(2)

f(2) = 6 + 6

f(2) = 12

Therefore, f(2) = 12.

Step-by-step explanation:

The value of f(x) is 18 given that the value of x is substituted as 4. The expression is usually solved with substitution method.

To find the value of f(x) for a given value of x, you need to substitute that value of x into the equation for f(x) and solve for f(x).

For example, if you want to find the value of f(x) when x = 4, you would substitute x = 4 into the equation for f(x) as follows:

f(4) = 6 + 3(4)

Simplifying the expression on the right-hand side:

f(4) = 6 + 12

f(4) = 18

Therefore, the value of f(x) when x = 4 is 18.

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Answer: First one (top left)

Step-by-step explanation:

Answer:

One in the top left corner

Hope this helps!

Step-by-step explanation:

Answer:

4

Step-by-step explanation:

2+2 = 4

The answer is 2+2 = 4.

The missing amounts for Work in Process - Blending Department are: 25,700 units, and $70,944 for direct materials.

Cost of Production Report

Bavarian Chocolate Company processes chocolate into candy bars.

The process begins by placing direct materials (raw chocolate, milk, and sugar) into the Blending Department.

All materials are placed into production at the beginning of the blending process.

After blending, the milk chocolate is then transferred to the Molding Department, where the milk chocolate is formed into candy bars.

The following is a partial work in process account of the Blending Department at October 31:

ACCOUNT Work in Process—Blending Department ACCOUNT NO.

Date Item Debit Credit Balance

Debit Balance

Credit

October 1 Bal., 2,300 units, 3/5 completed 46,368

31 Direct materials, 26,000 units 429,000 475,368

31 Direct labor 100,560 575,928

31 Factory overhead 48,480 624,408

31 Goods transferred, 25,700 units.

1. Prepare a cost of production report, and identify the missing amounts for Work in Process—Blending Department. If an amount is zero enter "0". If required, round your cost per equivalent unit answers to the nearest cent.

Bavarian Chocolate Company

Cost of Production Report—Blending Department

For the Month Ended March 31

Bavarian Chocolate Company

Cost of Production Report—Blending Department

For the Month Ended October 31

Equivalent Units Schedule

Direct Materials Conversion Costs

Units to be accounted for:

Work in process, October 1 (3/5 completed) 2,300 2,300

Units started in October 26,000 26,000

Total units to be accounted for 28,300 28,300

Units accounted for:

Goods transferred to the Molding Department (25,700 units × 100%) 25,700 25,700

Work in process, October 31 (1/5 completed):

Total units accounted for:

Costs to be accounted for:

Direct materials cost $429,000

Direct labor cost $100,560

Factory overhead cost $48,480

Total costs to be accounted for $578,040

Costs accounted for:

Direct materials cost (26,000 units × $15 per unit) $390,000

Direct labor cost (2,300 units × $44 per unit) 101,200

Factory overhead cost (2,300 units × $21.12 per unit) 48,576

Total costs accounted for $539,776

Cost per Equivalent Unit:

Direct materials cost ($429,000 ÷ 28,300 units) $15.16

Direct labor cost ($100,560 ÷ 2,300 units) $43.74

Factory overhead cost ($48,480 ÷ 2,300 units) $21.12

Total cost per equivalent unit $80.02

Work in Process—Blending Department

Direct Materials Conversion Costs Total

Balance, October 1 $27,820 $18,548 $46,368

Current costs $352,380 $222,548 $574,928

Total cost $380,200 $241,096 $621,296

Less: Goods transferred to the Molding Department (25,700 units × $80.02 per unit) (2) $2,048 $2,048

Balance, October 31 (2) $378,152 (2) $239,048 (2) $617,200

(1) Equivalent units of direct materials and conversion costs have been calculated based on the weighted-average method.

(2) The missing amounts for Work in Process—Blending Department are:

Units, October 31: 2,600 units (28,300 total units – 25,700 transferred units).

Direct Materials, October 31: $352,380 (current costs) - $390,000 (costs accounted for) = -$37,620 (overallocated)

Conversion Costs, October 31: $222,548 (current costs) - $241,096 (costs accounted for) = -$18,548 (overallocated).

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The solutions to the equation are x = a and x = a/2.

We can simplify the left-hand side of the equation using the common denominator of x^3:

(x-a)x/x^3 + (x-a)(-1)/(3a^2 x^3) + (x-a)(-2)/(3a x^3) + (x-a)(1)/(x^3)

= [(x-a)x^2 - (x-a)/(3a^2) - 2(x-a)/(3a) + (x-a)x]/x^3

= [(x^3 - a^3)/x^2 - (1/(3a^2))(x-a) - (2/(3a))(x-a)]/x

= [(x^2 + ax + a^2)(x-a)/(x^2 a^2) - (x-a)/(3a^2) - (2/3)(x-a)/a]/x

= (x^2 + ax + a^2)/(x^2 a^2) - 1/(3a^2) - 2/(3a)/x

= (3x^2 + 3ax + 3a^2 - x^2 a - ax^2 - a^3)/(3a^2 x^2)/x

= (2x^2 + 3ax + 3a^2 - ax^2 - a^3)/(3a^2 x^2)/x

= (x^2 + 3ax + 3a^2 - a^3)/(3a^2 x^2)/x

Now, we can see that the expression on the right-hand side is:

(x-a)/(x^3)

Multiplying both sides by x^3, we get:

(x-a)x = (x^2 + 3ax + 3a^2 - a^3)/3a^2

Multiplying both sides by 3a^2, we get:

(x-a)3a^2x = x^2 + 3ax + 3a^2 - a^3

Expanding (x-a)(3a^2)x, we get:

3a^2x^2 - 3a^3x = x^2 + 3ax + 3a^2 - a^3

Moving all terms to one side, we get:

2x^2 - 3ax + 2a^2 = 0

This is a quadratic equation, and we can solve for x using the quadratic formula:

x = [3a ± sqrt((9a^2 - 8a^2)/4)]/4

x = [3a ± a]/4

x = a or x = 2a/4 = a/2

Therefore, the solutions to the equation are x = a and x = a/2.

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To add 2/5 and 3/6, we need to find a common denominator for the two fractions. The smallest number that both 5 and 6 divide into evenly is 30. So, we can convert the two fractions to have a denominator of 30:

2/5 = 12/30 3/6 = 15/30

Now, we can add the two fractions by simply adding their numerators (since they have the same denominator):

12/30 + 15/30 = 27/30

We can simplify the fraction by reducing it to the lowest terms. Both the numerator and denominator have 3 as a factor, so we can divide them both by 3:

27/30 = (3 x 9) / (3 x 10) = 9/10

Therefore, the sum 2/5 + 3/6 is equal to 9/10.

The function has the maximum revenue of $348,480 with the increasing rate of $33.

The highest and smallest values of a function, respectively, can either be found inside a specific range or distributed throughout the entire domain. They are also sometimes referred to collectively as the function's extrema. The plural forms of a function's maximum and minimum are called maxima and minima, accordingly.

Given data:

The overall revenue is thus:

y = (36 - 0.50x)(9600 + 160x)

Differentiate with respect to x.

y ' = (-0.50)(9600 + 160x) + 160(36 - 0.50x)

y' = -4800 - 80x + 5760 - 80x

y' = 960 - 160x

To find x, put y' = 0

960 - 160x = 0

x = 960/160 = 6 (critical point)

Function is decreasing in interval - [6, +∞)

Increasing Function in interval - (-∞, 6]

Thus, the function has the maximum value at x = 6.

maximum revenue f(6):

f(6) = (36 - 0.50x)(9600 + 160x)

f(6) = (36 - 0.50(6))(9600 + 160(6))

f(6) = $348,480

Rate : 36 - 0.50(6) = $33

The function has the maximum revenue of $348,480 with the increasing rate of $33.

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The correct order will be:

Length of the blue segment.   - 12 units

Length of the green segment (circumference of the base) - 18 units

Length of the orange segment. - 24 units

Area of one base.                - 452.4 unit²

Area of the rectangle.        -  2,261.9 unit².

A cylinder is a three-dimensional shape that consists of two parallel circular bases that are connected by a curved surface. The bases are usually identical in size and shape and are located on opposite ends of the cylinder. The curved surface that connects the bases is in the form of a rectangle that has been wrapped around the cylinder, creating a tube-like shape.

Area of one base =   r² = 3.142 × 12 × 12 = 452.448 = 452.4 unit².

Area of the rectangle = 2πr (h + r) = 2 × 3.142 × 12 (18 + 12) = 2,261.9 unit².

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1. H × (3/7) and 2. H - (4/7)H are two different numerical expressions to model the height of the British telecom tower.

What are the expressions?

Let H be the height of the Empire State Building. Then, the height of the British Telecom Tower can be modeled using the following expressions:

1. H × (3/7)

This expression finds 3/7 of the height of the Empire State Building, which represents the height of the British Telecom Tower.

2. H - (4/7)H

This expression finds the remaining height after taking away 3/7 of the height of the Empire State Building.

Simplifying, we get (3/7)H, so subtracting this from H gives (4/7)H, which represents the height of the Empire State Building above the height of the British Telecom Tower.

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En resumen, al dividir Sea=4x⁵-x³+7 entre b(x)=2x⁵+x², obtenemos un cociente de 2x³-x² y un residuo de -2x²+7.

Para encontrar los cocientes y el residuo al dividir Sea=4x⁵-x³+7 entre b(x)=2x⁵+x², debemos realizar la división larga de polinomios. El procedimiento es similar a la división larga de números enteros:

        2x³    -x²    +0x   +0
   ---------------------------------
2x⁵ |  4x⁵   +0x⁴  -x³   +0x²  +0x  +7
        4x⁵   +0x⁴
       -------------
            0x⁴  -x³
            0x⁴  +0x³
           -------------
                   -x³   +0x²
                   -x³   +0x²
                   -------------
                            0x²  +0x
                            0x²  +0x
                            ------------
                                      7
                                      2x⁵  +x²
                                      --------
                                         -2x²  +7

Por lo tanto, el cociente de la división es 2x³-x², y el residuo es -2x²+7. Es importante notar que el grado del residuo (grado 2) es menor que el grado del divisor b(x) (grado 5), como se requiere en la definición de la división de polinomios.

La respuesta a la pregunta "cuál es la conciente de que (x)" no es clara, ya que no está claro lo que se está pidiendo. Podría ser una pregunta incompleta o una cuestión mal redactada.

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When we enter x = 3 into the first equation, we obtain: y = 2 log 3 y = 32     y = 9 .Hence, x=3 and y=9.

A log is a mathematical function used to calculate how many times the base, or initial value, must be increased by itself to produce the target value. In other terms, a logarithm is an exponent's negative action.

The base-10 logarithm is the most widely used type of logarithm, though there are other types as well. Some many mathematical and scientific tasks include the usage of logarithms, such as estimating the pH of a solution, gauging the volume of sound, and estimating population growth rates.

given

As we are aware that log x of y = 2, x2 = y.

We also understand that xy = 27.

When we change y in the second equation to x2, we obtain:

[tex]xx^{2} =7^{2} \\x^{3} = 27\\[/tex]

x = 3

When we enter x = 3 into the first equation, we obtain: y = 2 log 3 y = 32     y = 9 .Hence, x=3 and y=9.

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The total surface area must be calculated by adding the areas of all five faces, the four triangular faces, and the square base.

The term "square pyramid" refers to a three-dimensional geometric form with a square base and four triangular faces or sides that meet at a single point (known as a vertex). Because it has five faces, it is referred to as a pentahedron.

Given :

Let s represent the square base's side length and h represent the slant height of each triangle face. The area of a single triangle is then determined by:

A = (1/2) * s * h

The areas of all five face the four triangular faces and the square base must be added up in order to determine the overall surface area of the pyramid.

The overall surface area is: since the square base has a simple area of s2.

When we replace A with the expression, we obtain:

We require further details regarding the pyramid in order to determine the values of s and h.

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Each product of the fractions are

Part1. =17.33

Part2.= 0.73

Part3.=45.93

Multiplication is a mathematical operation that involves combining two or more numbers to obtain a product or result. Multiplication is a fundamental arithmetic operation that is used in a wide range of mathematical applications, from simple calculations such as calculating the area of a rectangle, to more complex problems in algebra, geometry, and calculus.

⅔×26

Multiplying 2 and 26, we get

52/3

Now, dividing it with3, we get

17.33

⅞×5/6

Multiplying 7 and 5 and 8 and 6, we get

35/48

Now, dividing 35 and 48, we get

.73

5 ⅕× 8 ×⅚

Solving the improper fractions;

26/5×53/6

Multiplying 26 and 53 and 5  and 6, we get

1378/30

Now, dividing 35 and 48, we get

45.93.

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1. The picture depicts the circle theorem

2. I wonder how the circle theorem fully apply to the image

3. The informed is that the angle between a radius and a tangent at the point of contact is a right angle.

The angle between a radius and a tangent at the point of contact is a right angle.

Suppose FGC

Then FC is the hypothenuse of triangle FGC

So, FC greater than FG

FC greater than FB+BG

FC greater than FC+BG (impossible)

This is the case on either side of C along the tangent

So, the shortest distance between F and the tangent is FC

When the distance between a point and a line is minimum, the angle between them is right angled.

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The assertion is accurate. This mean option that is selected should be true

The formula c = √(a 2 + b 2), where a and b are the lengths of the semi-major and semi-minor axes, respectively, yields the foci of a hyperbola.

. A hyperbola is a particular kind of conic section that resembles two slightly mirrored parabolic curves. It is described as the collection of all points in a plane where the difference between the locations of two fixed points (referred to as foci) is always constant.

Each of the two branches of a hyperbola resembles a parabola. In relation to the hyperbola's centre, the branches are symmetric. The semi-major axis is the distance between the centre and each vertex, whereas the semi-minor axis is the distance between the centre and each terminal of the transverse axis.

When a² = 25 and b² = 9,

the hyperbola (x-1)2/25 - (y+3)2/9=1 can be calculated.

In light of this, c = √(25 + 9) = √ (34).

The hyperbola's center is located at (1, -3).

The foci are at (1 + √(34), -3) and (1 - √(34), -3), respectively.

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