Answers
a) The mean of the data-set is of 2.
b) The range of the data-set is of 4 units, which is of around 4.3 MADs.
How to obtain the mean of a data-set?The mean of a data-set is obtained as the sum of all observations in the data-set divided by the number of observations in the data-set, which is also called the cardinality of the data-set.
The dot plot shows how often each observation appears in the data-set, hence the mean of the data-set is obtained as follows:
Mean = (1 x 0 + 5 x 1 + 3 x 2 + 5 x 3 + 1 x 4)/(1 + 5 + 3 + 5 + 1)
Mean = 2.
The range is the difference between the largest observation and the smallest, hence:
4 - 0 = 4.
4/0.93 = 4.3 MADs.
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Related Questions
A sixth-grade class recorded the number of letters in each student's first name.
The results are shown in the dot plot.
A dot plot titled lengths of student names show the number of students with a certain number of letters in their name. The data is as follows. 1 dot above 3, 2 dots above 4, 4 dots above 5, 7 dots above 6 and 7, 3 dots above 8, 1 dot above 9, 2 dots above 10, and 3 dots above 11.
Which is the best representation of the center of this data set?
A. 8
B. 5
C. 7
D. 6
Answers
Consider a graph of the function y = x² in xy-plane. The minimum distance between point (0, 4) on the y-axis and points on the graph is [1-2] You should rationalize the denominator in the answer. PLEASE HELP ME
Answers
The minimum distance between the point (0, 4) on the y-axis and points on the graph is 4.
To find the minimum distance between the point (0, 4) on the y-axis and points on the graph of the function y = x², we can use the concept of perpendicular distance.
The distance between a point (x, y) on the graph and the point (0, 4) is given by the formula:
distance = √((x - 0)² + (y - 4)²) = √(x² + (y - 4)²)
Substituting the function y = x² into the distance formula, we get:
distance = √(x² + (x² - 4)²) = √(x² + (x⁴ - 8x² + 16))
Simplifying further, we have:
distance = √(x⁴ + x² - 8x² + 16) = √(x⁴ - 7x² + 16)
To find the minimum distance, we need to minimize the expression x⁴ - 7x² + 16. Since this is a quadratic-like expression, we can use calculus to find the minimum.
Taking the derivative of x⁴ - 7x² + 16 with respect to x, we get:
d/dx (x⁴ - 7x² + 16) = 4x³ - 14x
Setting the derivative equal to zero to find critical points:
4x³ - 14x = 0
Factorizing, we have:
2x(2x² - 7) = 0
This gives us two critical points: x = 0 and x = ±√(7/2).
Next, we evaluate the expression x⁴ - 7x² + 16 at these critical points and the endpoints of the interval:
f(0) = 0⁴ - 7(0)² + 16 = 16
f(±√(7/2)) = (√(7/2))⁴ - 7(√(7/2))² + 16 ≈ 4.157
Comparing these values, we find that the minimum distance occurs at x = 0, giving us a minimum distance of √(0⁴ - 7(0)² + 16) = √16 = 4.
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Tamika practiced oboe for 1/4 hour in the morning and 5/6 hour in the afternoon how long did she practice in all write your answer as a mixed number
Answers
Morning practice: 1/4 hour
Afternoon practice: 5/6 hour
To add these fractions, we need to find a common denominator. In this case, the least common multiple (LCM) of 4 and 6 is 12. Let's convert the fractions to have a common denominator of 12:
Morning practice: 1/4 hour = 3/12 hour
Afternoon practice: 5/6 hour = 10/12 hour
Now we can add the fractions:
Total practice time = 3/12 hour + 10/12 hour = 13/12 hour
The total practice time is 13/12 hour. Since this fraction is improper (the numerator is greater than the denominator), we can simplify it as a mixed number:
13/12 hour = 1 and 1/12 hours
Therefore, Tamika practiced for a total of 1 and 1/12 hours.
What is the graph of f(x) = 0.5(4)x (x is an exponent)
Answers
It should be a positive graph .
Solve |5x - 1| < 1
please help
Answers
Answer:
|5x - 1| < 1
-1 < 5x - 1 < 1
0 < 5x < 2
0 < x < 2/5
6/7 .r = 3/4 write it as a fraction or as a whole or a mixed number
Answers
The solution for "r" is 21/24, which can be simplified to 7/8. The answer can be written as a fraction of 7/8.
To solve for "r" in the given equation, we can use algebraic manipulation.
First, we can multiply both sides of the equation by the reciprocal of 6/7, which is:
7/6: 6/7 · r = 3/4
7/6 · 6/7 · r = 7/6 · 3/4
r = 21/24.
Thus, the solution for "r" is 21/24, which can be simplified to 7/8.
Therefore, the answer can be written as a fraction of 7/8.
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Circle 1 is centered at (−4,−2) and has a radius of 3 centimeters. Circle 2 is centered at (5,3) and has a radius of 6 centimeters.
What transformations can be applied to Circle 1 to prove that the circles are similar?
Enter your answers in the boxes.
The circles are similar because you can translate Circle 1 using the transformation rule ( , ) and then dilate it using a scale factor of .
Answers
The circles are similar because you can translate Circle 1 using the transformation rule (9, 5) and then dilate it using a scale factor of 2.
To prove that Circle 1 and Circle 2 are similar, we need to identify the transformations that can be applied to Circle 1 to obtain Circle 2.
First, let's consider the translation of Circle 1. The translation rule is given by (a, b), where a represents the horizontal shift and b represents the vertical shift.
In this case, to translate Circle 1 to align with Circle 2, we need to shift it 9 units to the right and 5 units up. Therefore, the translation rule for Circle 1 is (9, 5).
Next, let's consider the dilation. A dilation is a transformation that changes the size of the figure but preserves its shape. The scale factor, denoted by k, determines the amount of scaling. In this case, Circle 1 needs to be dilated to match the size of Circle 2.
The scale factor can be determined by comparing the radii of the two circles. The radius of Circle 1 is 3 centimeters, while the radius of Circle 2 is 6 centimeters. The scale factor is obtained by dividing the radius of Circle 2 by the radius of Circle 1: 6/3 = 2.
Therefore, the transformation applied to Circle 1 to prove that the circles are similar is a translation by (9, 5) followed by a dilation with a scale factor of 2.
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21. An RSTU rectangle is drawn on the coordinate plane with coordinates R(-1, 5), S(4, 5), T(4, 9) and then translated by T(2,-3), then the image coordinates of point U are
Answers
The image coordinates of point U, after translating the RSTU rectangle by T(2,-3), would be U(6, 6).
To find the image coordinates of U, we need to apply the translation vector T(2,-3) to each of the original coordinates.
The translation vector represents the horizontal and vertical distances by which each point is moved.
Starting with the original coordinates of point U, which are (4, 9), we add the horizontal distance of 2 to the x-coordinate and subtract the vertical distance of 3 from the y-coordinate.
Therefore, the new x-coordinate of U is 4 + 2 = 6, and the new y-coordinate is 9 - 3 = 6.
Thus, the image coordinates of point U after the translation are (6, 6). This means that U has been moved 2 units to the right and 3 units downward from its original position.
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5 whole numbers are written in order. 5,8,x,y,12 The mean and median of the five numbers are the same. Work out the values of x and y.
Answers
5 whole numbers are written in order. 5,8,x,y,12 The mean and median of the five numbers are the same then the values of x and y are:[tex]$$\boxed{x=8, \ y=3}$$[/tex] OR [tex]$$\boxed{x=12, \ y=53}$$[/tex].
let's first calculate the median of the given numbers.
Median of the given numbers is the middle number of the ordered set.
As there are five numbers in the ordered set, the median will be the third number.
Thus, the median of the numbers = x.
The mean of a set of numbers is the sum of all the numbers in the set divided by the total number of items in the set.
Let the mean of the given set be 'm'.
Then,[tex]$$m = \frac{5+8+x+y+12}{5}$$$$\Rightarrow 5m = 5+8+x+y+12$$$$\Rightarrow 5m = x+y+35$$[/tex]
As per the given statement, the median of the given set is the same as the mean.
Therefore, we have,[tex]$$m = \text{median} = x$$[/tex]
Substituting this value of 'm' in the above equation, we get:[tex]$$x= \frac{x+y+35}{5}$$$$\Rightarrow 5x = x+y+35$$$$\Rightarrow 4x = y+35$$[/tex]
Also, as x is the median of the given numbers, it lies in between 8 and y.
Thus, we have:[tex]$$8 \leq x \leq y$$[/tex]
Substituting x = y - 4x in the above inequality, we get:[tex]$$8 \leq y - 4x \leq y$$[/tex]
Simplifying the above inequality, we get:[tex]$$4x \geq y - 8$$ $$(5/4) y \geq x+35$$[/tex]
As x and y are both whole numbers, the minimum value that y can take is 9.
Substituting this value in the above inequality, we get:[tex]$$11.25 \geq x + 35$$[/tex]
This is not possible.
Therefore, the minimum value that y can take is 10.
Substituting y = 10 in the above inequality, we get:[tex]$$12.5 \geq x+35$$[/tex]
Thus, x can take a value of 22 or less.
As x is the median of the given numbers, it is a whole number.
Therefore, the maximum value of x can be 12.
Thus, the possible values of x are:[tex]$$\boxed{x = 8} \text{ or } \boxed{x = 12}$$[/tex]
Now, we can use the equation 4x = y + 35 to find the value of y.
Putting x = 8, we get:
[tex]$$y = 4x-35$$$$\Rightarrow y = 4 \times 8 - 35$$$$\Rightarrow y = 3$$[/tex]
Therefore, the values of x and y are:[tex]$$\boxed{x=8, \ y=3}$$[/tex] OR [tex]$$\boxed{x=12, \ y=53}$$[/tex]
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Statement: Reasons:
DF=EG.
DE
Prove: DE=FG
Statements
DF=EG
DF=DE+EF.
EG=EF+FG
DE+EF=EF+ FG
FL
G
Answers
Answer:
az
Step-by-step explanation:
Statements:
1. DF = EG
2. DF = DE + EF
3. EG = EF + FG
Reasons:
1. Given
2. Definition of segment addition postulate
3. Definition of segment addition postulate
To prove: DE = FG
To proceed with the proof, we can use the transitive property:
DE + EF = EF + FG
Next, we can subtract EF from both sides:
DE = FG
Therefore, we have shown that DE is equal to FG.
!! Will give brainlist !!
Determine the surface area and volume Note: The base is a square.
Answers
The surface area and volume of the square pyramid is 96 squared centimeter and 48 cubic centimeters respectively.
What is the surface area and volume of the square pyramid?The surface area of a square pyramid is expressed as:
SA = [tex]a^2 + 2a \sqrt{\frac{a^2}{4}+h^2 }[/tex]
The volume of a square pyramid is expressed as:
Volume = [tex]a^2*\frac{h}{3}[/tex]
Where a is the base edge and h is the height.
From the figure a = 6cm
First, we determine the h, using pythagorean theorem:
h² = 5² - (6/2)²
h² = 5² - 3²
h² = 25 - 9
h² = 16
h = √16
h = 4 cm
Solving for surface area:
SA = [tex]a^2 + 2a \sqrt{\frac{a^2}{4}+h^2 }[/tex]
[tex]= a^2 + 2a \sqrt{\frac{a^2}{4}+h^2 }\\\\= 6^2 + 2*6 \sqrt{\frac{6^2}{4}+4^2 }\\\\= 36 + 12 \sqrt{\frac{36}{4}+16 }\\\\= 36 + 12 (5)\\\\= 36 + 60\\\\= 96 cm^2[/tex]
Solving for the volume:
Volume = [tex]a^2*\frac{h}{3}[/tex]
[tex]= a^2*\frac{h}{3}\\\\= 6^2*\frac{4}{3}\\\\= 36*\frac{4}{3}\\\\=\frac{144}{3}\\\\= 48 cm^3[/tex]
Therefore, the volume is 48 cubic centimeters.
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Of the books in a personal library, 4/7 are fiction. Of these books, 1/3 are paperback. What fraction of the books in the library are fiction and paperbacks?
Answers
4/21 of the books in the library are both fiction and paperbacks.
To determine the fraction of books in the library that are both fiction and paperback, we need to multiply the fractions representing each condition.
Let's start with the fraction of books in the library that are fiction. If 4/7 of the books are fiction, then this fraction represents the number of fiction books.
Next, we want to find the fraction of fiction books that are also paperbacks. Since 1/3 of the fiction books are paperbacks, we multiply 4/7 (fiction books) by 1/3 (paperback fraction).
Multiplying fractions is done by multiplying the numerators together to get the new numerator and multiplying the denominators together to get the new denominator.
Thus, the fraction of books in the library that are both fiction and paperbacks is:
(4/7) * (1/3) = (4 * 1) / (7 * 3) = 4/21
Therefore, 4/21 of the books in the library are both fiction and paperbacks.
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What is the distance between points R (5, 7) and S(-2,3)?
Answers
Answer:
d ≈ 8.1
Step-by-step explanation:
calculate the distance d using the distance formula
d = [tex]\sqrt{(x_{2}-x_{1})^2+(y_{2}-y_{1})^2 }[/tex]
with (x₁, y₁ ) = R (5, 7 ) and (x₂, y₂ ) = S (- 2, 3 )
d = [tex]\sqrt{(-2-5)^2+(3-7)^2}[/tex]
= [tex]\sqrt{(-7)^2+(-4)^2}[/tex]
= [tex]\sqrt{49+16}[/tex]
= [tex]\sqrt{65}[/tex]
≈ 8.1 ( to 1 decimal place )
Solve a triangle with a = 4. b = 5, and c = 7."
a. A=42.3°; B = 42.5⁰; C = 101.5⁰
b. A= 34.1°; B = 44.4°; C= 99.5⁰
C.
d.
OA
OB
C
OD
A = 34.1°: B=42.5°: C= 101.5°
A = 34.1°: B= 44.4°: C= 101.5°
Please select the best answer from the choices provided
Answers
Angle C can be found by subtracting the sum of angles A and B from 180 degrees:
b. A = 34.1°; B = 44.4°; C = 101.5°
To solve a triangle with side lengths a = 4, b = 5, and c = 7, we can use the law of cosines and the law of sines.
First, let's find angle A using the law of cosines:
[tex]cos(A) = (b^2 + c^2 - a^2) / (2\times b \times c)[/tex]
[tex]cos(A) = (5^2 + 7^2 - 4^2) / (2 \times 5 \times 7)[/tex]
cos(A) = (25 + 49 - 16) / 70
cos(A) = 58 / 70
cos(A) ≈ 0.829
A ≈ arccos(0.829)
A ≈ 34.1°
Next, let's find angle B using the law of sines:
sin(B) / b = sin(A) / a
sin(B) = (sin(A) [tex]\times[/tex] b) / a
sin(B) = (sin(34.1°) [tex]\times[/tex] 5) / 4
sin(B) ≈ 0.822
B ≈ arcsin(0.822)
B ≈ 53.4°
Finally, angle C can be found by subtracting the sum of angles A and B from 180 degrees:
C = 180° - A - B
C = 180° - 34.1° - 53.4°
C ≈ 92.5°.
b. A = 34.1°; B = 44.4°; C = 101.5°
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In December 2016 the average price of unleaded
Answers
please help me asap with this it's getting late
Answers
The system B is gotten from system A by operation (d)
How to derive the system B from system AFrom the question, we have the following parameters that can be used in our computation:
x + y = 8
4x - 6y = 2
Also, we have the solution to be (5, 3)
Recall that
x + y = 8
4x - 6y = 2
Multiply the first equation by 6
So, we have
6x + 6y = 48
4x - 6y = 2
Add the equations
10x = 50
This means that the system B from system A is (d)
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Calculate:
1+2-3+4+5-6+7+8-9+…+97+98-99
Answers
The value of the given expression is 1370.
To calculate the given expression, we can group the terms in pairs and simplify them.
We have the following pattern:
1 + 2 - 3 + 4 + 5 - 6 + 7 + 8 - 9 + ... + 97 + 98 - 99
Grouping the terms in pairs, we can see that each pair consists of a positive and a negative term. The positive term increases by 1 each time, and the negative term decreases by 1 each time. Therefore, we can rewrite the expression as:
(1 - 3) + (2 + 4) + (5 - 6) + (7 + 8) + ... + (97 + 98) - 99
The sum of each pair in parentheses simplifies to a single term:
-2 + 6 - 1 + 15 + ... + 195 - 99
Now, we can add up all the terms:
-2 + 6 - 1 + 15 + ... + 195 - 99 = 1370
As a result, the supplied expression has a value of 1370.
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Algebra
Solve for k: 10-10|-8k+4|=10
Write your answer in set notation.
Answers
The solution for k in the equation 10 - 10|-8k + 4| = 10, expressed in set notation, is {1/2}.
1. Start with the equation: 10 - 10|-8k + 4| = 10.
2. Simplify the expression inside the absolute value brackets: -8k + 4.
3. Remove the absolute value brackets by considering two cases:
Case 1: -8k + 4 ≥ 0 (positive case):
-8k + 4 = -(-8k + 4) [Removing the absolute value]
-8k + 4 = 8k - 4 [Distributive property]
-8k - 8k = -4 + 4 [Group like terms]
-16k = 0 [Combine like terms]
k = 0 [Divide both sides by -16]
Case 2: -8k + 4 < 0 (negative case):
-8k + 4 = -(-8k + 4) [Removing the absolute value and changing the sign]
-8k + 4 = -8k + 4 [Simplifying the expression]
0 = 0 [True statement]
4. Combine the solutions from both cases: {0}.
5. Check if the solution satisfies the original equation:
For k = 0: 10 - 10|-8(0) + 4| = 10
10 - 10|4| = 10
10 - 10(4) = 10
10 - 40 = 10
-30 = 10 [False statement]
6. Since k = 0 does not satisfy the equation, it is not a valid solution.
7. Therefore, the final solution expressed in set notation is {1/2}.
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You own a portfolio that has $3,000 invested in Stock A and $4,100 invested in Stock B. Assume the expected returns on these stocks are 10 percent and 16 percent, respectively. What is the expected return on the portfolio?
Answers
The expected return on the portfolio is approximately 13.465%.
To calculate the expected return on the portfolio, we need to consider the weights of each stock in the portfolio.
Let's denote the weight of Stock A as wA and the weight of Stock B as wB. The weight of a stock is the proportion of the total portfolio value that is invested in that stock.
Given that $3,000 is invested in Stock A and $4,100 is invested in Stock B, we can calculate the weights as follows:
wA = $3,000 / ($3,000 + $4,100) = $3,000 / $7,100
wB = $4,100 / ($3,000 + $4,100) = $4,100 / $7,100
Next, we need to calculate the weighted average of the expected returns of the two stocks using their respective weights:
Expected return on the portfolio = (wA * Return on Stock A) + (wB * Return on Stock B)
Expected return on the portfolio = (wA * 10%) + (wB * 16%)
Substituting the calculated weights into the equation:
Expected return on the portfolio = ($3,000 / $7,100 * 10%) + ($4,100 / $7,100 * 16%)
Simplifying the equation:
Expected return on the portfolio = (0.4225 * 10%) + (0.5775 * 16%)
Expected return on the portfolio = 0.04225 + 0.0924
Expected return on the portfolio = 0.13465 or 13.465%
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Hcf of two expressions is (x + 1) and lcm is (x^3+ x^2 – x – 1). if one expression is (x^2 - 1), then what is the second expression?
Answers
After solving by formula the second expression is y = [tex](x^2 + 1)[/tex].
We know that the product of the HCF and LCM of two numbers is equal to the product of the numbers themselves. In this case, we can apply the same principle to expressions:
HCF * LCM = (x + 1) * [tex](x^3+ x^2 - x - 1)[/tex]
the first number is [tex]x^{2} -1\\[/tex] and let the second number is y
Therefore, we can set up the equation:
(x + 1) * [tex](x^3+ x^2 - x - 1)[/tex] = [tex]x^{2} -1\\[/tex] * y
[tex]x^4 + x^3 + x^2 - x^3 - x^2 + x - x - 1 = x^2 - 1 * y[/tex]
Simplifying:
[tex]x^4 - 1 = (x^2 - 1) * y[/tex]
Now, we can divide both sides by [tex](x^2 - 1)[/tex]:
[tex](x^4 - 1) / (x^2 - 1) = y[/tex]
Notice that [tex](x^2 - 1)[/tex]can be factored as (x + 1)(x - 1). Therefore, we can simplify further:
[tex](x^4 - 1) / ((x + 1)(x - 1)) = y[/tex]
The expression [tex](x^4 - 1)[/tex] can be factored using the difference of squares:
[tex](x^4 - 1) = (x^2 + 1)(x^2 - 1)[/tex]
[tex][(x^2 + 1)(x^2 - 1)] / ((x + 1)(x - 1)) = y[/tex]
Now, we can cancel out the common factor [tex](x^2 - 1)[/tex] from the numerator and denominator:
[tex]y =(x^2 + 1)[/tex]
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Given the piecewise functions shown below, select all of the statements that are true.
Answers
The true statements are:
a. f(-1) = 2
c. f(1) = 0
Let's evaluate each statement using the given piecewise function f(x):
a. f(-1) = -(-1) + 1 = 2
b. f(-2) = -(-2) + 1 = 3 (Not 0, so this statement is false)
c. f(1) = (1)^2 - 1 = 0
d. f(4) = (4)^2 - 1 = 16 - 1 = 15 (Not 7, so this statement is false)
Therefore, the correct statements are:
a. f(-1) = 2
c. f(1) = 0
Statement a is true because when x = -1, we use the first piece of the piecewise function, which gives us -(-1) + 1 = 2.
Statement c is true because when x = 1, we use the third piece of the piecewise function, which gives us (1)^2 - 1 = 0.
Statements b and d are false because they do not match the corresponding values obtained from evaluating the piecewise function at the given inputs.
Therefore, the true statements are:
a. f(-1) = 2
c. f(1) = 0
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Which exponential equation is e
quivalent to the logarithmic equation below? log=200 a
A. 200 = 10
B. 200¹0 = a
C. a¹0 = 200
D. 10 = 200 SUBMIT
Answers
The exponential equation a¹⁰ = 200 is equivalent to the logarithmic equation Log = 200 a.
Which rule of logarithms should we use here?The rule of logarithms that we should use here is given below:
[tex]\log \text{x} = \text{a} \iff 10^{\text{a}} = \text{x}[/tex]
We can find the equivalent exponential equation below:The given expression is Log = 200 a.
We can follow the rule log x = a ⇔ 10^a = x to convert this logarithmic equation to an exponential one.
Log = 200 a can be rewritten as a¹⁰ = 200
Therefore, we have found that the exponential equation a¹⁰ = 200 is equivalent to the logarithmic equation Log = 200 a.
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You just inherited a sum of money from a distant uncle. The only stipulation is that you need to save it for 10 years and then you can do whatever you want with it. The amount of the inheritance is $25,000.
Option one: You can put it into a saving account that earns 6% compounded quarterly.
Option two: You can put it into a checking account that earns 4% compounded monthly.
Option three: You can place it into a money market account that earns 3% compounded daily.
Which option is best for you? Why?
Submit a report detailing the reasons you have for the decision you make.
Answers
This flexibility of a money market account makes it an ideal option for people who need to save money without risking their inheritance.
After inheriting $25,000 from a distant uncle, you would like to save it for ten years before doing anything with it. Since you want to save the money, there are several options for keeping it safe and earning interest, including a savings account, a certificate of deposit (CD), and a money market account.
Money market accounts, in my opinion, would be the best place to keep the inheritance. The money market account is a low-risk account with high-interest rates, making it an attractive option for someone who wants to save their money. As a result, it would be reasonable to place the inheritance into a money market account that pays a daily compounded rate of 3%.There are several reasons for choosing this option.
Firstly, the daily compounded interest will generate a higher return over the ten-year period than the simple interest or monthly compounded interest offered by other accounts. Second, the account is FDIC-insured, which means that the account holder is guaranteed to receive their money in the event of a bank failure.
Furthermore, the money market account provides easy access to the account holder's money while still earning interest. Most money market accounts have a limit on the number of withdrawals a person can make per month. Still, the account holder can easily transfer funds into a checking account or withdraw money from an ATM if needed.
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NO LINKS!! URGENT HELP PLEASE!!
25. Use the relationship in the diagrams below to solve for the given variable.
Justify your solution with a definition or theorem.
Answers
Answer:
x = 110°
Step-by-step explanation:
The opposite angles are equal in a parallelogram
3x - 60 = 2x + 50
⇒ 3x - 2x = 60 + 50
⇒ x = 110°
Answer:
x = 110°
Step-by-step explanation:
As the top and bottom line segments of the given shape are the same length and parallel (indicated by the tick marks and arrows), the shape is a parallelogram.
As the opposite angles of a parallelogram are equal, to find the value of the variable x, equate the two angle expressions and solve for x:
[tex]\begin{aligned}3x-60^{\circ}&=2x+50^{\circ}\\3x-60^{\circ}-2x&=2x+50^{\circ}-2x\\x-60^{\circ}&=50^{\circ}\\x-60^{\circ}+60^{\circ}&=50^{\circ}+60^{\circ}\\x&=110^{\circ}\end{aligned}[/tex]
Therefore, the value of x is 110°.
Note: There must be an error in the question. If x = 110°, each angle measures 270°, which is impossible since the sum of the interior angles of a quadrilateral is 360°.
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Prove that the two circles shown below are similar. (10 points)
Circle X is shown with a center at negative 2, 8 and a radius of 6. Circle Y is shown with a center of 4, 2 and a radius of 3.
Answers
In this case, Circle X has a center at (-2, 8) and a radius of 6. Circle Y has a center at (4, 2) and a radius of 3. To show that these two circles are similar, we need to show that the ratio of their radii is the same as the ratio of their corresponding diameters 1.
The distance between the centers of Circle X and Circle Y is:
d = sqrt((4 - (-2))^2 + (2 - 8)^2) = sqrt(6^2 + (-6)^2) = sqrt(72)
The ratio of the radii of Circle X and Circle Y is:
r1/r2 = 6/3 = 2
The ratio of their corresponding diameters is:
d1/d2 = (2 * r1)/(2 * r2) = r1/r2 = 2
Since the ratio of their radii is the same as the ratio of their corresponding diameters, we can conclude that Circle X and Circle Y are similar 1.
Todd noticed that the gym he runs seems less crowded during the summer. He decided to look at customer data to see if his impression was correct.
Week
5/27 to 6/2
6/3 to 6/9
6/10 to 6/16
6/17 to 6/23
6/24 to 6/30
7/1 to 7/7
Use
618 people
624 people
618 people
600 people
570 people
528 people
A: What is the quadratic equation that models this data? Write the equation in vertex form.
B: Use your model to predict how many people Todd should expect at his gym during the week of July 15.
Todd should expect_______people.
Answers
Todd should expect approximately 624 people at his gym during the week of July 15.
A: To find the quadratic equation that models the data, we can use the vertex form of a quadratic equation:
[tex]y = a(x - h)^2 + k[/tex] where (h, k) represents the vertex of the parabola.
Let's analyze the data to determine the vertex. We observe that the number of people is highest during the first week and gradually decreases over the following weeks.
This suggests a downward-opening parabola.
From the data, the highest point occurs during the week of 6/3 to 6/9 with 624 people.
Therefore, the vertex is located at (6/3 to 6/9, 624).
Using the vertex form, we have:
[tex]y = a(x - 6/3 to 6/9)^2 + 624[/tex]
Now, we need to find the value of 'a.'
To do this, we can substitute any other point and solve for 'a.' Let's use the data from the week of 5/27 to 6/2:
[tex]618 = a(5/27 to 6/2 - 6/3 to 6/9)^2 + 624[/tex]
Simplifying the equation and solving for 'a,' we find:
[tex]618 - 624 = a(-6/3)^2[/tex]
-6 = 4a
a = -3/2
Therefore, the quadratic equation in vertex form that models the data is:
[tex]y = (-3/2)(x - 6/3 to 6/9)^2 + 624[/tex]
B: To predict the number of people Todd should expect during the week of July 15, we substitute x = 7/15 into the equation and solve for y:
[tex]y = (-3/2)(7/15 - 6/3 to 6/9)^2 + 624[/tex]
Simplifying the equation, we find:
[tex]y = (-3/2)(1/15)^2 + 624[/tex]
y = (-3/2)(1/225) + 624
y = -3/450 + 624
y = -1/150 + 624
y = 623.993
For similar question on quadratic equation.
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help please its due in 50 minutes ill mark brainliest answer too and no need to show work
Answers
The output value f(3) in the functions f( x ) = 3x + 5, f( x ) = [tex]\frac{1}{2}x^2-1.5[/tex] and f( x ) = [tex]\frac{3}{2x}[/tex] is 14, 3 and 1/2 respectively.
What is the output value of f(3) in the given functions?Given the functions in the question:
f( x ) = 3x + 5
f( x ) = [tex]\frac{1}{2}x^2-1.5[/tex]
f( x ) = [tex]\frac{3}{2x}[/tex]
To evaluate each function at f(3), we simply replace the variable x with 3 and simplify.
a)
f( x ) = 3x + 5
Replace x with 3:
f( 3 ) = 3(3) + 5
f( 3 ) = 9 + 5
f( 3 ) = 14
b)
f( x ) = [tex]\frac{1}{2}x^2-1.5[/tex]
Replace x with 3:
[tex]f(3) = \frac{1}{2}(3)^2 - 1.5\\\\f(3) = \frac{1}{2}(9) - 1.5\\\\f(3) = 4.5 - 1.5\\\\f(3) = 3[/tex]
b)
f( x ) = [tex]\frac{3}{2x}[/tex]
Replace x with 3:
[tex]f(3) = \frac{3}{2(3)} \\\\f(3) = \frac{3}{6} \\\\f(3) = \frac{1}{2}[/tex]
Therefore, the output value of f(3) is 1/2.
Learn more about functions here: brainly.com/question/2541698
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how do you find out how many positive zeros and negative zeros are in a polynomial based on a graph?
Answers
In this context, the term "zeros" refers to the roots or x-intercepts.
You're looking for where the graph either,
a) touches the x axis, or,b) crosses the x axisSee the diagram below. That example shows two positive roots, because each root is to the right of the vertical y axis.
Please answer ASAP I will brainlist
Answers
Answer:
A) The y-intercept(s) is/are 2
Step-by-step explanation:
Y-intercepts are where the graph of a function cross over the y-axis. In this case, the line passes through y=2, which is the y-intercept.
prove that the lim x→−3 (10 − 2x) = 16
Answers
Answer:
Proving that the limit of the equation 10 - 2x as x approaches -3 is 16 involves using the definition of a limit.
Here's how you would approach it:
Let epsilon be a small positive number. We want to find a value of delta such that if x is within a distance of delta from -3, then 10 - 2x is within a distance of epsilon from 16.
So, we start with:
|10 - 2x - 16| < epsilon
Simplifying,
|-2x - 6| < epsilon
And using the reverse triangle inequality,
|2x + 6| > ||2x| - |6||
Now, we can choose a value for delta such that if x is within delta of -3, then |2x + 6| is within delta + 6 of |-6| = 6.
So,
||2x| - |6|| < epsilon
and therefore:
|2x - 6| < epsilon
Choosing delta = epsilon/2, we can prove that:
0 < |x + 3| < delta -> |2x - 6| < epsilon
Therefore, we have proved that the limit of 10 - 2x as x approaches -3 is 16 using the definition of a limit.
Step-by-step explanation:
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