PLEASE I NEEDHELP !!!!!!!!!!


In the diagram, q1 and q2 are both
+5.00*10^-8 C. What is the electric field
at point P? Include a + or - sign to
indicate the direction.
91
P
92
0.636 m
+ 0.424 m-**
(Remember, E points away from + charges,
and toward - charges.)
(Unit = N/C)

PLEASE I NEEDHELP !!!!!!!!!!In The Diagram, Q1 And Q2 Are Both+5.00*10^-8 C. What Is The Electric Fieldat

Answers

Answer 1

Answer:

1389.1

For Acellus

Explanation:

Answer 2

The electric field equals the force exerted by the unit positive charge. The electric field at point P is 3.615×10⁶  N/C. Its unit is N/C.

What is an electric field?

When a charged particle is got influenced by another charged particle when bring near to it, a field is created by an electric charge. This field is called the electric field.

The electric field is obtained by taking the ratio between Force and unit positive charge. Force in a charge is because of attraction and repulsion. The SI unit of force is Newton (N).

The unit positive charge is the test charge used to analyze the other charges present in the field. The SI unit of charge is Coloumb (C). The charge is responsible for the creation of an electric field.

From the givens,

The charge  q₁ = q₂ = 5×10⁻⁸ C,

The distance of charges from point P, r₁ = 0.424 m; r₂ = 0.636 m.

The net electric field E = E₁ + E₂

Electric field E = F / q

 E₁ = kq₁ / r₁²          (k = 9×10⁹ Nm²/C²)

     =  9×10⁹× 5×10⁻⁸ / (0.424)²

  E₁   = 2.503×10³ N/C.

E₂ = kq₂ / r₂²

    = 9×10⁹× 5×10⁻⁸ / (0.636)²

E₂ = 1.112×10³ N/C

E = E₁ + E₂

  =2.503×10³ + 1.112×10³

  = 3.615×10³ N/C

Hence, the net electric field is 3.615×10³ N/C.

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Answers

Answer:

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Answers

Answer :-

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[tex] \underline {\rule {180pt}{4pt}} [/tex]

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Answers

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Answers

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Answers

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[tex]39m[/tex]

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Answers

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Due to the cylindrical symmetry of this problem, the induced electric field E⃗ (R,t) can depend only on the distance R from the z axis, where R is restricted to the region outside the iron rod. Find this field. Express E⃗ (R,t) in terms of quantities given in the introduction (and constants), using the unit vectors in the cylindrical coordinate system, θ^, r^, and k^

Answers

It is to be noted that the electric field that has been induced is (-B₁ A/2[tex]\pi[/tex]R)θ. This is obtained by using the vector units in the Cylindrical Coordinate System.

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Cylindrical Coordinates are simply defined as a component of a coordinate system that is used to locate a location in space using its polar coordinates and vertical distance from the polar plane.

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The formula for Induced Electric Field is given as:

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∫ E · dl = -B₁A. Thus, we can state that

E∫ dl  = -B₁A

Replacing or substituting 2[tex]\pi[/tex]R for ∫ dl ·E(2πR)  = - B₁A

We can thus rearrange the equation to read:

E · E = ([tex]\frac{-B1A}{2\pi R}[/tex])θ


It is to be noted that the circumference of a circle is the integral of the length of the element. While θ, which in this case is the unit vector refers to the Cylindrical Coordinate and the direction of the electric field.

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A force of 900 N is applied to a 9kg object. How fast will it accelerate?

Answers

Given :

Force = 900 N

Mass = 9kg

[tex] \\ [/tex]

To find :

Acceleration = ?

[tex] \\ [/tex]

We know :

[tex] \boxed{ \rm Force=Mass\times Acceleration}[/tex]

By using this formula we can find acceleration.

[tex] \dashrightarrow \sf Force=Mass\times Acceleration \\ [/tex]

[tex] \\ [/tex]

[tex] \dashrightarrow \sf900=9\times Acceleration \\ [/tex]

[tex] \\ [/tex]

[tex] \dashrightarrow \sf900 \times \dfrac{1}{9} =Acceleration \\ [/tex]

[tex] \\ [/tex]

[tex] \dashrightarrow \sf \cancel9 \times 100 \times \dfrac{1}{ \cancel9} =Acceleration \\ [/tex]

[tex] \\ [/tex]

[tex] \dashrightarrow \sf \dfrac{100}{1} =Acceleration \\ [/tex]

[tex] \\ [/tex]

[tex] \dashrightarrow \sf Acceleration = \dfrac{100}{1} \\ [/tex]

[tex] \\ [/tex]

[tex] \dashrightarrow \bf Acceleration = 100\: ms^{-2}[/tex]

━━━━━━━━━━━━━━━━━━━━━━━━━━━━━━━

Related Concept :

Define Acceleration:

Acceleration is the rate by which velocity changes with respect to time

Main formula :-

a = (Vf - Vi)/t

where :-

Vf is final velocityVi is initial velocityt is time

Define Force :

Force is a push or pull that changes or may tends to change an object from rest to motion or from motion to rest.

Main formula:

f = m × a

where :-

m is massa is accelerationf is force

Define Mass :

The amount of matter present in body

Main formula:

m = v × d

where:-

m is massv is volumed is density
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