Rewrite the expression in the form a^na


n


a, start superscript, n, end superscript.


\dfrac{a^{-13}}{a^{-6}}=


a


−6



a


−13



​


=start fraction, a, start superscript, minus, 13, end superscript, divided by, a, start superscript, minus, 6, end superscript, end fraction, equals

The volume of the cone with the same radius and height as the cylinder is 36 cm³.

To find the volume of a cone with the same radius and height as the cylinder, we first need to find the radius and height of the cylinder.

The formula for the volume of a cylinder is V = πr^2h, where r is the radius and h is the height.

We are given that the volume of the cylinder is 108 cm^3.

So, 108 = πr^2h

To solve for r and h, we need more information. However, we can use the fact that the cone has the same radius and height as the cylinder to our advantage.

The formula for the volume of a cone is V = (1/3)πr^2h.

Since the cone has the same radius and height as the cylinder, we can substitute the values of r and h from the cylinder into the cone formula.

V = (1/3)π( r^2 )(h)

V = (1/3)π( r^2 )(108/π)

V = (1/3)( r^2 )(108)

V = 36( r^2 )

Therefore, the volume of the cone with the same radius and height as the cylinder is 36 cm³

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The regular membership fee of the Holiday Health Club is $300.

Let the regular membership fee be x. According to the problem, the club has reduced its annual membership by 10%, so the discounted membership fee is 0.9x. We know that Jorge Sanchez has purchased a year's membership for $270, which is the discounted membership fee. Therefore, we can set up an equation as follows:

0.9x = 270

Solving for x, we get:

x = 270/0.9

x = 300

Hence, the regular membership fee of the Holiday Health Club is $300.

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Answer:

part a: The slope of the function represents the rate of change of the balance in the bank account per day. To find the slope, we can use the formula: slope = (change in y)/(change in x).

Using the values from the table, we have: slope = (720-600)/(3-0) = 120/3 = 40. Therefore, the slope of the function g(x) is 40.

part b: Using the point-slope form of the equation of a line, we can write: g(x) - 600 = 40(x-0). Simplifying, we get: g(x) = 40x + 600. This is the slope-intercept form of the equation, where the y-intercept is 600 and the slope is 40.

To write in standard form, we can rearrange the equation as: -40x + g(x) = 600.

part c: Using function notation, we can write the equation as: g(x) = 40x + 600.

part d: To find the balance in the bank account after 7 days, we can use the equation we found in part c and substitute x = 7: g(7) = 40(7) + 600 = 880. Therefore, the balance in the bank account after 7 days is $880.

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The value of the triple integral ∫∫∫[tex]E \sqrt{(x^2 + y^2)} dV[/tex] over the solid bounded by the circular paraboloid [tex]z = 9 - (x^2 + y^2)[/tex] and the xy-plane is 486π/5.

To evaluate the triple integral ∫∫∫[tex]E \sqrt{(x^2 + y^2)} dV[/tex], where E is the solid bounded by the circular paraboloid [tex]z = 9 - (x^2 + y^2)[/tex] and the xy-plane, we can use cylindrical coordinates. In cylindrical coordinates, the equation of the paraboloid becomes:

[tex]z = 9 - (r^2)[/tex]

The limits of integration are:

0 ≤ r ≤ 3 (since the paraboloid intersects the xy-plane at z = 0 when r = 3)

0 ≤ θ ≤ 2π

0 ≤ z ≤ 9 - (r^2)

The triple integral becomes:

∫∫∫[tex]E √(x^2 + y^2) dV = ∫0^3 ∫0^2π ∫0^(9-r^2) r√(r^2) dz dθ dr[/tex]

Simplifying, we get:

∫∫∫[tex]E √(x^2 + y^2) dV = ∫0^3 ∫0^2π ∫0^(9-r^2) r^2 dz dθ dr[/tex]

Evaluating the innermost integral, we get:

∫[tex]0^(9-r^2) r^2 dz = (9-r^2)r^2[/tex]

Substituting this back into the triple integral, we get:

∫∫∫[tex]E √(x^2 + y^2) dV = ∫0^3 ∫0^2π (9-r^2)r^2 dθ dr[/tex]

Evaluating the remaining integrals, we get:

∫∫∫[tex]E √(x^2 + y^2) dV = ∫0^3 (9r^2 - r^4) dθ[/tex]

= 2π [243/5]

= 486π/5

Therefore, the value of the triple integral ∫∫∫[tex]E \sqrt{(x^2 + y^2)} dV[/tex] dV over the solid bounded by the circular paraboloid [tex]z = 9 - (x^2 + y^2)[/tex] and the xy-plane is 486π/5.

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The polynomial represented by the model is [tex]]x^2 - x + 2[/tex]

Based on the provided model, the polynomial represented is:

1 black square block: x^2
2 white thin blocks: -2x
1 black thin block: x
1 white small square block: -1
3 black small blocks: +3

The polynomial that the model represents is:
[tex]x^2 - 2x + x - 1 + 3[/tex]

Combining like terms, we get:
[tex]x^2 - x + 2[/tex]

So, the polynomial represented by the model is [tex]x^2 - x + 2[/tex].

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Answer:

6x + 4y

Step-by-step explanation:

2(2x + 4y + x − 2y)

= 4x + 8y + 2x - 4y

= 6x + 4y

Answer:

pls mrk me brainliest (⁠・⁠(⁠ｪ⁠)⁠・⁠）

Answer: Dude, I think its B. but I wouldn't use this site, its not a good rabbit hole to go down.

Step-by-step explanation:

A circle with a circumference of 40π and a chord of the circle is 24 units, then the chord is 16 units from the center of the circle,

The circumference of a circle is given by the formula C = 2πr, where r is the radius of the circle. Here, we are given that the circumference is 40π. That is

40π = 2πr

Dividing both sides by 2π, we get:

r = 20

Now, we need to find the distance between the chord and the center of the circle. Let O be the center of the circle, and let AB be the chord. We know that the perpendicular bisector of a chord passes through the center of the circle. Let P be the midpoint of AB, and let OP = x.

By the Pythagorean Theorem,

x^2 + 12^2 = 20^2

Simplifying,

x^2 + 144 = 400

x^2 = 256

x = ±16

Since OP is a distance, it must be positive. Therefore, x = 16, and the chord is 16 units from the center of the circle.

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The probability of a sophomore attending the prom, given that they were selected from the group of sophomores, is:

P(will attend the prom|sophomore) = (number of sophomores attending the prom) / (total number of sophomores)

From the table, we see that the number of sophomores attending the prom is 10, and the total number of sophomores is 54 (10 + 17 + 27). Therefore:

P(will attend the prom|sophomore) = 10 / 54

Simplifying the fraction, we get:

P(will attend the prom|sophomore) = 5 / 27

So the probability of a sophomore attending the prom is 5/27 (18.519%).

Geometric transformations can be found in everyday life, such as moving furniture (translation), opening a door (rotation), using mirrors (reflection), zooming in and out of maps (scaling), skewing images in Photoshop (shearing), and stretching a rubber band (stretching).

Here are some examples of different types of transformations and their applications:

Translation:

Moving furniture in a room

Moving a vehicle on a map

Shifting a picture on a wall

Rotation:

Swinging a pendulum

Turning a key in a lock

Opening a door

Reflection:

Mirrors reflecting images

Water reflections of a landscape

Reflective surfaces on cars and buildings

Scaling:

Enlarging or reducing a picture on a screen

Adjusting the size of a printout

Shearing:

Skewing an image in Photoshop

Tilting a picture frame on a wall

Slanting the roof of a building for better drainage

Stretching:

Stretching a rubber band

Stretching a balloon before inflating it

Stretching a canvas for painting

These are just a few examples of the many ways geometric transformations are used in our everyday lives. By understanding these concepts, we can appreciate the beauty and functionality of the world around us.

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X = 0 and Y = 6 are the answers to the equation system. The system's two equations are satisfied at the location (0, 6). Choice D

To solve the system of equations:

2x + 3y = 18

3x + y = 6

We can employ the substitution or elimination strategy. Let's solve this system via the process of elimination:

To make the coefficients of x in both equations equal, multiply the second equation by two:

2(3x + y) = 2(6)

6x + 2y = 12

Now we have the system of equations:

2x + 3y = 18

6x + 2y = 12

Next, by deducting the first equation from the second equation, we can remove the y term:

(6x + 2y) - (2x + 3y) = 12 - 18

6x + 2y - 2x - 3y = -6

4x - y = -6

4x - y = -6

y = 4x + 6

At this point, we can add this expression for y to one of the initial equations. Let's employ the first equation:

2x + 3(4x + 6) = 18

2x + 12x + 18 = 18

14x + 18 = 18

14x = 0

x = 0

Replacing x = 0 in the equation y = 4x + 6 now:

y = 4(0) + 6

y = 6

Thus, x = 0 and y = 6 are the answers to the system of equations. The system's two equations are satisfied at the location (0, 6). Basketball or baseball in option D is 5/6, or approximately 0.8333.

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Answer:

Option D, (0,6)

Step-by-step explanation:

took the test xx

Answer:

a. n < 14

b.  n ≥ 14

Step-by-step explanation:

a.

We see the line to the left of 14, meaning it will be smaller than 14. So, the inequality is n < 14

b.

The line goes to the right of 14, meaning it will be bigger than 14. This has a close circle meaning there will be an equal sign. So, the inequality is n ≥ 14

The probability of the complement of the event of Ignacio chooses a plant at random that does not have a white bloom is 0.7692.

The probability of an occurrence is a figure that represents how likely it is that the event will take place. In terms of percentage notation, it is stated as a number between 0 and 1, or between 0% and 100%. The higher the likelihood, the more probable it is that the event will take place.

Probability is a way to gauge how likely something is to happen. Several things are difficult to forecast with absolute confidence. With it, we can only make predictions about the likelihood of an event happening, or how likely it is.

The probability that Ignacio chooses the plant which have white bloom in it is,

P = number of white bloom / total number of flowers

P = 21 / 91

So the probability that the chosen flower is not white is,

1 - P = 1 - 21/91 = 70/91 = 0.7692.

Therefore, the probability of not choosing white is 0.7692.

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Therefore, the solutions of tan x = -1/2 in the interval (0, 2) are:

x ≈ 2.034, 5.176

We can simplify the given equation as follows:

4 tan 2x - 4 cot x = 0

4(tan 2x - cot x) = 0

4[(2tan x)/(1 - tan^2 x) - (1)/(tan x)] = 0

Multiplying both sides by (1 - tan^2 x) * (tan x), we get:

8tan^3 x - 4tan^2 x - 8tan x + 4 = 0

Dividing both sides by 4 and rearranging, we get:

2tan^3 x - tan^2 x - 2tan x + 1 = 0

Factorizing, we get:

(tan x - 1)(2tan^2 x - tan x - 1) = 0

Using the quadratic formula to solve for the roots of 2tan^2 x - tan x - 1 = 0, we get:

tan x = [1 ± sqrt(1 + 8)] / 4 = [1 ± sqrt(9)] / 4 = 1, -1/2

Therefore, the solutions of the given equation in the interval (0, 2) are the values of x such that tan x = 1 or tan x = -1/2.

We know that tan (π/4) = 1 and tan (-π/4) = -1, so the solutions of tan x = 1 in the interval (0, 2) are:

x = π/4, 5π/4

We can find the solutions of tan x = -1/2 in the interval (0, 2) by finding the reference angle and using the signs of sine and cosine in the corresponding quadrants. We have:

tan x = -1/2

Let θ be the reference angle such that tan θ = 1/2. We know that θ is in the second or fourth quadrant.

In the second quadrant, sine is positive and cosine is negative, so we have:

sin θ = sqrt(1/(1 + tan^2 θ)) = sqrt(1/5)

cos θ = -tan θ = -1/2

Therefore, we get:

x = π - θ = π + arctan(1/2) ≈ 2.034

In the fourth quadrant, both sine and cosine are negative, so we have:

sin θ = -sqrt(1/(1 + tan^2 θ)) = -sqrt(1/5)

cos θ = -tan θ = -1/2

Therefore, we get:

x = 2π - θ = 2π + arctan(1/2) ≈ 5.176

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The equation 15√2 = x√2 can be solved, the value of x that satisfies the equation is 15.

To solve the equation 15√2 = x√2, you can divide both sides by √2 since the square root of 2 is a common factor on both sides of the equation. This gives:

15√2 / √2 = x√2 / √2

On the left side of the equation, the √2 and the denominator cancel out, leaving:

15

On the right side of the equation, the √2 and the denominator also cancel out, leaving:

x

So the solution to the equation is:

x = 15

Therefore, the value of x that satisfies the equation is 15.

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The congruency statement that describes the figures is:
ΔDEF ≅ ΔRSU

To answer your question, let's first find the image of triangle DEF after reflecting over the y-axis and then translating down 4 units and right 3 units.

1. Reflect ΔDEF over the y-axis:
D'(−6, 4), E'(−5, 8), F'(−1, 2)

2. Translate ΔD'E'F' down 4 units and right 3 units:
D''(−3, 0), E''(−2, 4), F''(2, −2)

Now, we have ΔD''E''F'' with points (−3, 0), (−2, 4), and (2, −2). Comparing this to ΔRSU with points (−2, 4), (−3, 0), and (2, −2), we can see that:

ΔD''E''F'' ≅ ΔRSU
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Answer:

ΔDEF ≅ ΔRSU

Step-by-step explanation:

Answer:

[tex] \sqrt{3 {x}^{3} } = x \sqrt{3x} [/tex]

We note that x>0 here.

Answer:

The answer is x√3x

Step-by-step explanation:

√3x³=x√3x

Answer:

In simplified form: 1/27

Evaluated: 0.037

Step-by-step explanation:

To simplify and evaluate 81^(-3/4), we use the rule that (a^m)^n = a^(mn) and rewrite the expression as (3^4)^(-3/4). Then, we use the rule that a^(-n) = 1/(a^n) to get:

81^(-3/4) = (3^4)^(-3/4) = 3^(-3) = 1/(3^3) = 1/27

Therefore, 81^(-3/4) simplifies to 1/27 and evaluates to 0.037

The distance that the bees cover in feet is 10.84 feet.

The speed at which the bees travel is given in the unit inches per min but the required solution is in feet so we need to convert the unit from in/min to ft/min using the unit conversion method.

We know that

1 inch=1/12feet.

so 32 inches/min=32.5 *(1/12) feet/min.

which is roughly equal to 2.71 feet/min (rounded to two decimal places).

Now by using the speed, distance, and time formula which is:

distance=speed*time

we can calculate the distance covered by bees at the given speed and time.

Substituting the values in the equation.

distance=2.71 feet/minute * 4.0 minutes.

=10.84 feet

Therefore, the bee's distance in feet will be 10.84 feet (rounded off to 2 digits).

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To determine how long it would take Jose to read 20 pages at his average rate, you can use a proportion.

Let x be the time in minutes it would take Jose to read 20 pages.

Then, you can set up the following proportion:

2.5 pages / 4 minutes = 20 pages / x minutes

To solve for x, you can cross-multiply:

2.5 pages * x minutes = 4 minutes * 20 pages

2.5x = 80

Finally, divide both sides by 2.5 to isolate x:

x = 32

Therefore, it would take Jose 32 minutes to read 20 pages at his average rate.

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The percentage is 9.0% of the senior class are either members of the Key Club, enrolled in AP Physics, or both.

We need to find the percentage of seniors who are either members of the Key Club, enrolled in AP Physics, or both. We can use the formula:

Total percentage = Key Club percentage + AP Physics percentage - Both percentage

Step 1: Identify the given percentages
Key Club percentage = 2.3%
AP Physics percentage = 8.6%
Both percentage = 1.9%

Step 2: Apply the formula
Total percentage = 2.3% + 8.6% - 1.9%

Step 3: Calculate the result
Total percentage = 9.0%

So, 9.0% of the senior class are either members of the Key Club, enrolled in AP Physics, or both.

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Answer:

Billy can buy 19 or less than 19 stickers.

Step-by-step explanation:

  Let the unknown variable - number of stickers be 'x'.

   Cost of one sticker = $1.34

   Cost of 'x' stickers = 1.34 * x = 1.34x

   Maximum amount that can be spent for buying stickers = 80 - 54.50

                                                                                                 = $25.50

   Inequality:

          1.34x ≤ 25.50

 Solving:

         Divide both sides by 1.34,

            [tex]\sf x \leq \dfrac{25.50}{1.34}[/tex]

            x ≤ 19.03

            x ≤ 19

Billy can buy 19 or less than 19 stickers.

A) The distribution is a negative binomial distribution with parameters r and p.

B) The probability that the 8th success occurs on the 17th spin is approximately 0.8%.

C) The probability that the 13th success occurs between the 31st and 34th spin is approximately 0.6%.

A) The distribution is a negative binomial distribution with parameters r = number of successes (in this case, r = 1 since we are only interested in the first success), and p = probability of success (landing in a green slot).

B) To find the probability that the 8th success occurs on the 17th spin, we use the formula for the negative binomial distribution:

P(X = k) = (k-1)C(r-1) * [tex]p^r[/tex] * [tex](1-p)^{(k-r)[/tex]

where X is the number of spins until the Rth success, k is the number of spins, and C(n,r) is the binomial coefficient (n choose r).

In this case, we want to find P(X = 17) when r = 8 and p = 2/38 (since there are 2 green slots out of 38 total slots):

P(X = 17) = (16 C 7) * (2/38)⁸ * (36/38)⁹
          ≈ 0.008 or 0.8%

So the probability that the 8th success occurs on the 17th spin is approximately 0.8%.

C) To find the probability that the 13th success occurs between the 31st and 34th spin, we need to find the probability of getting exactly 12 successes in the first 30 spins, followed by a success on one of the next 4 spins (31st, 32nd, 33rd, or 34th).

P(31 ≤ X ≤ 34) = P(X ≤ 34) - P(X ≤ 30)
               = ∑[k=13 to 34] (k-1 C 12-1) * (2/38)¹² * [tex](36/38)^{(k-12)[/tex] - ∑[k=1 to 30] (k-1 C 12-1) * (2/38)¹² * [tex](36/38)^{(k-12)[/tex]
               ≈ 0.006 or 0.6%

So the probability that the 13th success occurs between the 31st and 34th spin is approximately 0.6%.

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Step-by-step explanation:

B

26 = 13.5 + m/2.5; m = 31.25

26 = 13.5 + 31.25/2.5

26 = 13.5 + 12.5

26 = 26

The number of engines that must be made to minimize the unit cost are 180

From the question, we have the following parameters that can be used in our computation:

C(x) = −0.5x² + 180x + 25,609.

Differentiate the above equation

So, we have the following representation

C'(x) = -x + 180

Set the equation to 0

So, we have the following representation

-x + 180 = 0

This gives

x = 180

Substitute x = 180 in the above equation, so, we have the following representation

C(180) = −0.5(180)² + 180(180) + 25,609

Evaluate

C(180) = 41809

Hence, the engines that must be made to minimize the unit cost are 180

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The equivalent expression is $\left(\dfrac{4^{3}}{5^{-2}}\right)^{5} = 102400000000000000000$.

We can simplify the expression inside the parentheses first:

\begin{aligned} \frac{4^3}{5^{-2}} &= 4^3 \cdot 5^2 \ &= (2^2)^3 \cdot 5^2 \ &= 2^6 \cdot 5^2 \ &= 2^5 \cdot 2 \cdot 5^2 \ &= 2^5 \cdot 10^2 \ &= 3200 \end{aligned}

Now we can substitute this value into the original expression and simplify further:

\begin{aligned} \left(\frac{4^3}{5^{-2}}\right)^5 &= (3200)^5 \ &= (2^8 \cdot 5^2)^5 \ &= 2^{40} \cdot 5^{10} \ &= (2^4)^{10} \cdot 5^{10} \ &= 16^{10} \cdot 5^{10} \ &= (16 \cdot 5)^{10} \ &= 80^{10} \ &= 102400000000000000000 \end{aligned}

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The t-test statistic value that has a P-value of 0.10 when the alternative hypothesis is

(a) Ha: μ ≠ 0 is ±1.711.

(b) Ha: μ > 0 is 1.319.

(c) Ha: μ < 0 is -1.319.

(d) Ha: μ ≠ 0 is ±1.711.

To find the t-test statistic value for a given P-value and alternative hypothesis, we need to use a t-distribution table or a statistical software program. Here, we will use a t-distribution table to find the t-test statistic value for a sample of 24 observations and a P-value of 0.10 for each alternative hypothesis.

(a) Ha: μ ≠ 0 (two-tailed test)

The critical t-value for a two-tailed test with a P-value of 0.10 and degrees of freedom (df) of 23 (sample size - 1) is:

t = ±1.711

Therefore, the t-test statistic value that has a P-value of 0.10 when the alternative hypothesis is Ha: μ ≠ 0 is ±1.711.

(b) Ha: μ > 0 (one-tailed test)

The critical t-value for a one-tailed test with a P-value of 0.10 and df of 23 is:

t = 1.319

Therefore, the t-test statistic value that has a P-value of 0.10 when the alternative hypothesis is Ha: μ > 0 is 1.319.

(c) Ha: μ < 0 (one-tailed test)

The critical t-value for a one-tailed test with a P-value of 0.10 and df of 23 is:

t = -1.319

Therefore, the t-test statistic value that has a P-value of 0.10 when the alternative hypothesis is Ha: μ < 0 is -1.319.

(d) Ha: μ ≠ 0 (two-tailed test)

To find the t-test statistic value when Ha: μ ≠ 0, we can use the inverse t-distribution function in a statistical software program or a calculator. The t-test statistic value that corresponds to a P-value of 0.10 with 23 degrees of freedom is:

t = ±1.711

Therefore, the t-test statistic value that has a P-value of 0.10 when the alternative hypothesis is Ha: μ ≠ 0 is ±1.711.

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