Mr. Thompson has a class of 14 students. He can spend $25 on each student to buy math supplies for the year. He first buys all of his students calculators,
which costs a total of $84. 14. After buying the calculators, how much does he have left to spend on each student?
Answer:
he has $6 left.
Step-by-step explanation:
Answer:
$18.99 for each student
Step-by-step explanation:
First we need to find out how much he spent on each student for the calculators.
We can do that by dividing 84.14, the total, by the number of students, 14:
84.14/14 = 6.01
He spent 6.01 on each student and has 25 for each student, so we can subtract that:
25 - 6.01 = 18.99
For a party, Carlos buys 8 bags of popcorns and 4 bags of pretzels on sale for $10.36. During the party, he goes back to the store after the sale is over to buy 4 more bags of popcorns and 2 bags of pretzels for $20.72. Let x represent the price of each bag of popcorn and let y represent the price of each bag of pretzels. Which system of linear equations can you solve to find the price of each bag ofpopcorn and each bag of pretzels?
Answer:
addingadddddddddddddddddd
What is the result of the subtraction problem that is represented on the number line?
Enter your answer as a decimal, like this: 42.5
The required subtraction problem that is represented on the number line is 3 -(-5). Option B is correct.
Given that,
To determine the subtraction problem that is represented on the number line.
A number line is defined as the number marked on the line calibrated into an equal number of units. For example -1, 0, 1, and so on.
Here,
The line marked above the number line from -5 to 3
The subtraction problem would be given as 3 - (-5)
Thus, the required subtraction problem that is represented on the number line is 3 -(-5). Option B is correct.
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Since questions seem to be incomplete,
The given solution is based on the question given below,
Which subtraction problem is represented by the number line?
A: 3-5
B: 3 - (-5)
C: 3-8
D: 3-(-8)
Miguel made up an equation for his friend to solve. He told his friend that three times the square of a number is 265", What is the number to the nearest tenth
The number after rounding off to the nearest tenth will be 9.4
In this question, we have been given that Miguel made up an equation in which three times of square of a particular number equals 265. We have to set up the equation according to this.
Taking the number as 'x'. We get the equation according to the condition :
=> 3x² = 265
By solving this equation we get :
=> 3x² = 265 => x² = 88.3
=> x = 9.39
We get x = 9.39. By rounding off x to the nearest tens, we get x = 9.4
Hence, the number to the nearest tenth will be 9.4
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A triangle’s base is 5 cm more than its height of x cm. Find its height if the triangle’s area is 10 cm2. Quadratic equation
Answer:
A=2.5×x
10cm=2.5×x
10÷2.5=2.5÷2.5×x
x=4
(2x² + 4x³) + (-4x² + 6x³ - 2)
How many times larger is (1.092 × 101) than (7 × 10−1)?
0.156
15.6
6.41
6.908
The number 1.092×[tex]10^{1}[/tex] is 15.6 times larger than 7×[tex]10^{-1}[/tex]
Given,
The first number = 1.092×[tex]10^{1}[/tex]
The second number =7×[tex]10^{-1}[/tex]
Here,
Convert the given numbers to the simplest form
The first number 1.092×[tex]10^{1}[/tex] =1.092×10
=10.92
The second numbers 7×[tex]10^{-1}[/tex]= 7×0.1
=0.7
We know the division is one the basic arithmetic operations in the mathematics. It is the process of the splitting a particular amount or number into equal parts.
To find how many time larger 1.092×[tex]10^{1}[/tex] than 7×[tex]10^{-1}[/tex], we have to divide the first number by second number.
10.92 ÷ 0.7 =15.6
Hence, the number 1.092×[tex]10^{1}[/tex] is 15.6 times larger than 7×[tex]10^{-1}[/tex]
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The figure below is not drawn to scale. What is the value of x?
I help I need help please someone help me !!!!!
Answer:
answer for this question is alternative A (80, 60) & (95,85)
(2) six spheres of radius 1 are positioned so that their centers are at the vertices of a regular hexagon of side length 2. the six spheres are internally tangent to a larger sphere whose center is the center of the hexagon. an eighth sphere is externally tangent to the six smaller spheres and internally tangent to the larger sphere. what is the radius of this eighth sphere? (2013 amc 10a
The radius of 8th sphere is 3/2.
The 8th sphere's center and the hexagon's two opposing ends should form an isosceles triangle. Then put up another triangles between the point of tangency of the 7th and 8th spheres, and the point of tangency between the 7th sphere and 2 of the original spheres on different sides of the hexagon. Each triangle's side length should be expressed in terms of r (the sphere's 8 radius) and h. (the height of the first triangle). The values of h and r may then be determined by setting up two equations for the two triangles using the Pythagorean Theorem.
(1+r)² = [tex]2^{2}[/tex] + [tex]h^{2}[/tex]
(3√2)² =3² + (h+r)²
r= 3/2
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Answer the question in photo [ Brainliest + easy points ]
x+12+4x-16= 6x-13
5x-4=6x-13
-4=x-13
x=9
9+12+4(9)-16
21+36-16
57-16= 41
JL=41 units
Find FH
FH = {Blank}
Answer:
FH = 24
Step-by-step explanation:
HG = 13
FH = 37 - 13
= 24
Answer:
The value of FH is 24.
Step-by-step explanation:
The equation will be,
→ FHG = FH + HG
Then the value of FH will be,
→ 37 = FH + 13
→ FH = 37 - 13
→ [ FH = 24 ]
Hence, the value of FH is 24.
suppose M is the midpoint of FG. find each missing measure.
FM= 8a + 1, FG = 42, a =?
The value of a is 2.5
As FG is the line and M is the midpoint of the line
F ______________·_________________G
M
So by this, we have that
FG = FM + MG
Where FM = MG as M is the midpoint of the line.
Therefore FG = 2FM
As it is given that FM = 8a + 1 and FG = 42
Now putting the values we have
42 = 2( 8a + 1)
21 = 8a + 1
20 = 8a
a = 2.5
Therefore the value of a is 2.5.
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Consider the system of equations 2x + 5y = 5 and -3x + 7y = 7. What number would you multiply to eliminate the y?
Answer:
(0, 1 )
Step-by-step explanation:
2x + 5y = 5 → (1)
- 3x + 7y = 7 → (2)
to eliminate y multiply (1) by 7 and (2) by - 5 , then add the result
14x + 35y = 35 → (3)
15x - 35y = - 35 → (4)
add (3) and (4) term by term to eliminate y
29x + 0 = 0
29x = 0 ⇒ x = 0
substitute x = 0 into (1) and solve for y
2(0) + 5y = 5y
0 + 5y = 5
5y = 5 ( divide both sides by 5 )
y = 1
solution is (0, 1 )
I don’t understand this question
X/2 - 2 =x/4 + 2
Solve the inequality and express your answer in interval notation.
X^2+8x+5<0
Answer: (-4-[tex]\sqrt{11}[/tex], -4+[tex]\sqrt{11}[/tex]) ==> B
Step-by-step explanation:
x^2+8x+5<0
x^2+8x+16-11<0
(x+4)^2-11<0
(x+4)^2<11
x+4<[tex]\sqrt{11}[/tex]
x<-4+[tex]\sqrt{11}[/tex]
x+4>-[tex]\sqrt{11}[/tex]
x>-4-[tex]\sqrt{11}[/tex]
(-4-[tex]\sqrt{11}[/tex], -4+[tex]\sqrt{11}[/tex]) ==> B
Remember, the solution doesn't include the x values -4-[tex]\sqrt{11}[/tex] and -4+[tex]\sqrt{11}[/tex] since if they were plugged in x^2+8x+5, the expression would equal 0. The expression is supposed to be LESS than 0, not equal to 0.
Answer:
Answer: (-4-\sqrt{11}11 , -4+\sqrt{11}11 )
x^2+8x+5<0
x^2+8x+16-11<0
(x+4)^2-11<0
(x+4)^2<11
x+4<\sqrt{11}11
x<-4+\sqrt{11}11
x+4>-\sqrt{11}11
x>-4-\sqrt{11}11
(-4-\sqrt{11}11 , -4+\sqrt{11}11 )
you are selling flowers to raise money for a field trip. For each flower you sell you earn $5 toward the trip the total cost of the field trip including the bus ride is $75 you must sell enough flowers to cover the cost of the $15 bus ride and you plan to stop selling flowers if you earn enough to cover the total cost of the trip. Describe the possible numbers of flowers you sell.
The possible number of flowers you sell is 3 to 25
How to describe the possible numbers of flowers you sell.?The given parameters are:
Selling price = $5
Total cost of trip = $75
Bus ride = $15
If you earn enough to cover the total cost of the trip, the maximum numbers (Max) of flowers you sell is
Max = Total cost of trip/Selling price
This gives
Max = 75/5
Max = 25
If you earn enough to cover the bus ride, the minimum numbers (Min) of flowers you sell is
Min = Bus ride/Selling price
This gives
Min = 15/5
Min = 3
Hence, the possible number of flowers you sell is 3 to 25
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an independent group of food service personnel conducted a survey on tipping practices in a large metropolitan area. they collected information on the percentage of the bill left as a tip for 3535 randomly selected bills. the average tip was 12.7.7% of the bill with a standard deviation of 2.8%2.8%. assume that the tips are approximately normally distributed. construct an interval to estimate the true average tip (as a percent of the bill) with 99% confidence. round the endpoints to two decimal places, if necessary.
The interval to find the true average tip is (14.62,13.78).
Average is a number that is calculated by adding quantities together and dividing the total by the number of quantities.
The Standard deviation is a measure of the amount of variation or dispersion of a set of values. A low standard deviation indicates that the values tend to be close to the mean of the set, while a high standard deviation indicates that the values are spread out over a wider range
Given:
We know that the confidence interval = sample mean ± standard deviation substitute the values in it then confidence interval = 14.2 ±2.5/(35)^1/2
confidence interval = 14.2 ± 2.5/5.91
confidence interval = 14.2 ± 0.42
confidence interval = 14.2 + 0.42 ,
confidence interval = 14.2 - 0.42
confidence interval = (14.62,13.78)
So, an interval to estimate the true average tip is (14.62,13.78).
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An atom has a diameter of 2.00 Å and the nucleus of that atom has a diameter of 9.50×10−5 Å . Determine the fraction of the volume of the atom that is taken up by the nucleus. Assume the atom and the nucleus are a sphere.
fraction of the volume of the atom taken by nucleus = 1.07*10^-13
Space occupied by the sphere is the volume of sphere.
A straight line passing from side to side through the center of the body especially a circle or sphere is known as diameter.
Volume of sphere = 4/3πr³
Diameter of an Atom = 2.00Â
Diameter of an nucleus = 9.50×10⁻⁵Â
Radius of an Atom = 1.00Â
[tex]\frac{4}{3}\pi r^3=\frac{4}{3}\pi (4.75*10^(-5))^3\\[/tex]
Volume of an Atom = [tex]\frac{4}{3}\pi r^3= \frac{4}{3}\pi 1^3=\frac{4}{3}\pi[/tex]
Volume of nucleus = [tex]\frac{4}{3} \pi r^3=\frac{4}{3} \pi (4.75*10^-5)^3\\=\frac{4}{3} \pi 107.1718*10^-15[/tex]
fraction of the volume of the atom taken by nucleus =
4/3π 107.17*10^-15/ 4/3π =107.17*10^-15 = 1.07 *10^-13
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A clothing pattern calls for 4.81 yd2 of fabric. how many square inches of fabric does the pattern use? (note: 1 yd = 3 ft., 1 ft = 12 in.)
Pattern uses 6233.76 inches² fabric.
Firstly we will convert units in required form. Therefore, converting equivalent of yard² in inches². As per the given information, 1 yard = 3 feet and 1 foot = 12 inches.
As 1 foot = 12 inches, so, 3 feet = 36 inches, which is further equal to 1 yard.
Now, 1 yard² = (36 inches)²
1 yard² = 1296 inches²
Coming back to the problem, we will now calculate inches² from fabric measurement in yard². So, relating the units for conversion.
1 yard² = 1296 inches²
4.81 yard² = 1296 × 4.81
Performing multiplication
Measurement of 4.81 yard² in inches² = 6233.76
Hence, the pattern uses 6233.76 inches² fabric.
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a line passes through the points (9, 16) and (0, 5). what is it’s equation in slope intercept form
Answer:
y = x + 5
Step-by-step explanation:
Slope: m = (y2-y1)/(x2-x1)
m = (16 - 5)/(9 - 0) = 9/9 = 1
Using m = 1, y = 5, x = 0
then y = mx + b
5 = 1(0) + b
b = 5
so y = x + 5
The nth term of a sequence is 4−7. The last term of the sequence is 393.How many terms are there in the sequence?
Answer:
There are 98 terms in this sequence.
Verruca counted protrusions. she found that 3 times the number of protrusions was 15 less then -4 times the opposite of the number of protrusions. how many protrusions did she count?
15 protrusions were counted by her.
Clearly, there are multiple ways to treat verruca. For this type of patient, we would try a prescription for Drysol to apply topically once daily. In many of these patients, the skin is too moist. In our practice, we write a prescription for physical therapy for ultrasound application to the verruca. There is no guarantee with any treatment for verruca. Vitamin A adjunct treatment is often instituted: approx 7500 IU /day for 3 weeks.
Let no. of protrusions be x
3 * x = -4 * (-x) - 15
3x-4x = -15
x = 15
Therefore 15 protrusions were counted by her.
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how do I figure this out
Answer:
[tex]27^{\frac{1}{3}} \quad 125^{\frac{2}{3}} \quad 9^{\frac{3}{2}}[/tex]
Step-by-step explanation:
Rewrite 9 as 3²:
[tex]\implies 9^{\frac{3}{2}}=\left(3^2\right)^{\frac{3}{2}}[/tex]
[tex]\textsf{Apply exponent rule} \quad (a^b)^c=a^{bc}:[/tex]
[tex]\implies 3^{(2 \cdot \frac{3}{2})}=3^3[/tex]
Therefore:
[tex]\implies 3^3= 3 \cdot 3 \cdot 3=27[/tex]
---------------------------------------------------------
Rewrite 27 as 3³:
[tex]\implies 27^{\frac{1}{3}}=\left(3^3\right)^{\frac{1}{3}}[/tex]
[tex]\textsf{Apply exponent rule} \quad (a^b)^c=a^{bc}:[/tex]
[tex]\implies 3^{(3 \cdot \frac{1}{3})}=3^1[/tex]
Therefore:
[tex]\implies 3^1=3[/tex]
---------------------------------------------------------
Rewrite 125 as 5³:
[tex]\implies 125^{\frac{2}{3}}=\left(5^3\right)^{\frac{2}{3}}[/tex]
[tex]\textsf{Apply exponent rule} \quad (a^b)^c=a^{bc}:[/tex]
[tex]\implies 5^{(3 \cdot \frac{2}{3})}=5^2[/tex]
Therefore:
[tex]\implies 5^2=5 \cdot 5=25[/tex]
---------------------------------------------------------
Solution
In order, from smallest to largest:
[tex]27^{\frac{1}{3}} \quad 125^{\frac{2}{3}} \quad 9^{\frac{3}{2}}[/tex]
2. The sum of the interior angles in a quadrilateral is 360°. Determine the value of x in
the diagram on the right.
Answer:
267/5 ( or ) 53.2
Step-by-step explanation:
Note : -
□ means 90°
2x - 42 + 3x + 45 + 90 = 360
2x + 3x + 45 - 42 + 90 = 360
5x + 3 + 90 = 360
5x + 93 = 360
5x = 360 - 93
5x = 267
x = 267/5 ( in fraction )
( or )
x = 53.2° ( in decimal )
simplify. 2(x-2y)-5x+6y-1=
Alberto invests $1,130 in a savings
account with a fixed annual interest rate
compounded 6 times per year. After 8
years, the balance reaches $1,325.71.
What is the interest rate of the account?
The interest rate of the account is 2%
Compound interestFrom the question, we are to determine the interest rate of the account
From the compound interest formula, we have that
A = P(1 + r/n)^{nt}
Where A is the amount
P is the principal
r is the rate
n is the number of times compounded
t is the time in years
From the given information,
A = $1,325.71
P = $1,130
n = 6
t = 8 years
Thus,
1325.71 = 1130(1 + r/6)⁶⁽⁸⁾
1325.71 = 1130( 1 + r/6)⁴⁸
1325.71/1130 = ( 1 + r/6)⁴⁸
Take the 48th root of both sides
1.003333 = 1 + r/6
1.003333 - 1 = r/6
0.003333 = r/6
r = 6 × 0.003333
r = 0.019998
r ≈ 0.02
r ≈ 2%
Hence, the interest rate of the account is 2%.
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Can someone please help mee (20 points + brainliest!!!)
Answer:
a. Price needs to decrease by 6 Bozats.
[tex]\sf b. \ \ \sf x =-\dfrac{1}{6} p+\dfrac{100}{3}[/tex]
Explanation:
Equation: p = 200 - 6x
where:
p = price per kilogramx = number of kilogram of snig solda.
To sell an additional kilogram of snig that is (x + 1) kilogram of snig.
current price = 200 - 6(x + 1) = 200 - 6x - 6
b.
[tex]\rightarrow p = 200 - 6x[/tex]
[tex]\rightarrow - 6x = p-200[/tex]
[tex]\rightarrow x =\dfrac{ p-200 }{-6}[/tex]
[tex]\rightarrow x =-\dfrac{1}{6} p+\dfrac{100}{3}[/tex]
Largest possible value of a?
–9 – a = b
a2 – 6a – 9 = b
If the ordered pair (a, b) satisfies the system of equations above, what is the largest possible value of a?
Solving a quadratic equation, it is found that the largest possible value of a is of a = 5.
How to solve a quadratic equation?A quadratic equation is modeled by the following rule:
y = ax^2 + bx + c
The solutions of the equations are the values of x for which y = 0.
For this problem, the equation is:
a² - 6a - 9 = b.
b = -9 - a, hence we replace in the equation as follows;
a² - 6a - 9 = -9 - a
a² - 5a = 0.
Traditionally, the solutions are given using Bhaskara's formula, however, since the coefficient c is zero, we can solve the equation by elimination as follows:
a² - 5a = 0.
a(a - 5) = 0.
Then the solutions are:
a = 0.a - 5 = 0 -> a = 5.5 > 0, hence the largest possible value of a is of a = 5.
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suppose the random variables x1, x2,..., xn are independent an identically distributed , each with variance
The random variable is 3×sigma²/4.
Since, X1, X2 & X3 are independent & identically distributed.
so we have,
var(X1) = var(X2) = var(X3) = \sigma².
And,[tex]cov(X1 , X2) = cov(X2 , X3) = cov(X1 , X3) = 0.[/tex]
Now, [tex]var(Y1) = var(X2 + X3) = var(X2) + var(X3) + 2.cov(X2 , X3) = \sigma² + \sigma² + 0 = 2.\sigma²[/tex]
[tex]var[(Y1 + Y2 + Y3)/2] = (1/4). [var(Y1) + var(Y2) + var(Y3) + 2.cov(Y1 , Y2) + 2.cov(Y1 , Y3) + 2.cov(Y2 , Y3)] = (1/4). (\sigma² + \sigma² + \sigma² + 0 + 0 + 0) = 3.\sigma²/4[/tex]
What is random variable and example?The collection of potential outcomes for a random event is referred to as the sample space, which is the domain of a random variable. When a coin is tossed, for instance, there are only two possible outcomes: heads or tails. Read Related Links as well. Probability.
Different from an algebraic variable is a random variable. An algebraic equation's variable is an unknowable but calculable value. The formula [tex]10 + x = 13[/tex] demonstrates that we can determine the precise value of x, which is [tex]3.[/tex] As seen in the example of the dice above, a random variable has a set of values, and any of those values could be the outcome.
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