In context of developing an interactive game for students in an online course, both the product and the process are important. It is process of developing game that holds key to learning and skill acquisition.
While the product, which refers to the end result or the actual game itself, is important for engaging students and providing a fun learning experience, it is the process of developing the game that holds the key to meaningful learning and skill acquisition.
The process of developing an interactive game involves various stages such as brainstorming, planning, designing, implementing, and testing. Throughout this process, students actively engage in problem-solving, critical thinking, collaboration, and creativity. They learn important concepts related to game design, programming, user experience, and project management.
The process allows students to apply theoretical knowledge in a practical context and develop valuable skills that are transferable to real-world situations.While the product, the interactive game itself, is the tangible outcome, it is the process of creating the game that fosters active learning, enhances student engagement, and promotes the acquisition of essential skills. By emphasizing the importance of the process, educators can create a more meaningful and impactful learning experience for students.
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1 Learning Outcomes Assessed: 2 1c. Describe how Management Information Systems impact upon organisations 3 Task 1 - Prepare and interpret descriptive statistics for a given data set and describe how Management Information Systems impact upon organisations. Scenario - Data Analytics Peter and Lois have decided to expand the business because they are convinced that there will be a house building explosion in the next few years and kitchen sales will skyrocket. Stewie would like you to use statistical techniques and MS Excel functionality to present the relevant information. REQUIRED to: 1a. Kitchen Craze plc. has its previous 4-year quarterly sale in your Excel workbook, in the "BAM4010 AS1 Answer Template". The company would like you to use the data to forecast sales for the 4 quarters in 2022 by: i. Calculate the 4-point, then the centred averages and seasonal variation. Seasonal variation = actual sales centred averages. ii. Calculate the average trend in the data using (LAST FIRST)/N-1 using the centred average. iii. Using the calculations in a. and b. above, forecast the sales for the 4 quarters in 2022. 1b. Interpret the descriptive statistics that you have created in 1a. Present your findings on tab LO1 (b) in the Excel workbook, in the "BAM4010 AS1 Answer Template". 1c. Describe how Management Information Systems impact upon organisations. This should be entered onto tab L01 (c) in the Excel workbook, in the "BAM4010 AS1 Answer Template".
The term "Template" refers to a pre-designed file or document that serves as a starting point for creating other similar documents.
Based on the provided scenario and tasks, here is an overview of what needs to be done:
Task 1: Prepare and interpret descriptive statistics for a given data set and describe how Management Information Systems impact upon organisations.
Scenario: Data Analytics
Peter and Lois believe that there will be a house building boom in the next few years, leading to increased kitchen sales. Stewie wants you to use statistical techniques and MS Excel to analyze the data and present relevant information.
Required Tasks:
1a. Forecast Sales for 2022
Use the provided data for the previous 4-year quarterly sales in the "BAM4010 AS1 Answer Template" Excel workbook.
Calculate the 4-point moving averages to identify trends in the data.
Calculate the centred averages and seasonal variation by subtracting the moving averages from the actual sales.
Determine the seasonal variation by subtracting the centred averages from the actual sales.
Calculate the average trend using the formula (LAST FIRST) / (N-1) based on the centred averages.
Use the calculations from steps a and b to forecast sales for the 4 quarters in 2022.
1b. Interpret Descriptive Statistics
Interpret the descriptive statistics created in task 1a.
Present your findings on the "LO1 (b)" tab in the Excel workbook "BAM4010 AS1 Answer Template".
1c. Describe the Impact of Management Information Systems
Write a description explaining how Management Information Systems impact organizations.
Enter your response on the "LO1 (c)" tab in the Excel workbook "BAM4010 AS1 Answer Template".
Make sure to refer to the provided Excel workbook "BAM4010 AS1 Answer Template" for the specific locations to enter your answers and findings.
Note: The specific calculations and interpretation of descriptive statistics will depend on the actual data provided in the Excel workbook.
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Assume that we are given an acyclic graph G = (V,E). Consider the following algorithm for performing a topological sort on G: Perform a DFS of G. When- ever a node is finished, push it onto a stack. At the end of the DFS, pop the elements off of the stack and print them in order.
How long does the above algorithm take?
(a)~ |V|2
(b)~ |V|+|E
(c) ~ log |V||E|
(d) ~ |E|log E
(e) None of the above
The algorithm for performing a topological sort on an acyclic graph G = (V, E) takes O(|V| + |E|) time complexity, which is option (b) ~ |V| + |E|.
- The algorithm performs a Depth-First Search (DFS) traversal of the graph G, which visits each vertex once.
- During the DFS, whenever a vertex finishes exploring (all its neighbors have been visited), it is pushed onto a stack.
- At the end of the DFS, the vertices are popped off the stack and printed, which gives a valid topological ordering of the graph.
- Since each vertex is visited once, the time complexity of the DFS is O(|V|).
- Additionally, for each vertex, we consider all its outgoing edges during the DFS, which contributes to O(|E|) time complexity.
- Therefore, the overall time complexity of the algorithm is O(|V| + |E|).
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For the following two time series: X - [39 44 43 39 46 38 39 43] Y - 37 44 41 44 39 39 39 40 Calculate the DTW distance between X and Y and point out the optimal warping puth. (The local cost function is defined as the absolute difference of the two values, c.g. (1)-d(39,37) - 2)
To calculate the DTW (Dynamic Time Warping) distance between time series X and Y and identify the optimal warping path, we can follow these steps using the given local cost function:
Step 1: Create a matrix with dimensions (m x n), where m is the length of time series X and n is the length of time series Y.
Step 2: Initialize the matrix with values representing the cumulative cost of alignment. We can set all values to infinity except for the top-left cell, which is set to 0.
Step 3: Iterate through each cell of the matrix, starting from the top-left cell and moving row by row and column by column.
Step 4: For each cell, calculate the cumulative cost by taking the absolute difference between the corresponding values from time series X and Y and adding it to the minimum cumulative cost of the neighboring cells (top, top-left, or left).
Step 5: Once the matrix is filled, the bottom-right cell will represent the DTW distance between X and Y.
Step 6: To identify the optimal warping path, we can backtrack from the bottom-right cell to the top-left cell, always choosing the path with the minimum cumulative cost.
Applying these steps to the given time series X and Y:
X: [39, 44, 43, 39, 46, 38, 39, 43]
Y: [37, 44, 41, 44, 39, 39, 39, 40]
Step 1: Create a matrix with dimensions (8 x 8).
Step 2: Initialize the matrix.
Copy code
0 ∞ ∞ ∞ ∞ ∞ ∞ ∞
∞ ∞ ∞ ∞ ∞ ∞ ∞ ∞
∞ ∞ ∞ ∞ ∞ ∞ ∞ ∞
∞ ∞ ∞ ∞ ∞ ∞ ∞ ∞
∞ ∞ ∞ ∞ ∞ ∞ ∞ ∞
∞ ∞ ∞ ∞ ∞ ∞ ∞ ∞
∞ ∞ ∞ ∞ ∞ ∞ ∞ ∞
∞ ∞ ∞ ∞ ∞ ∞ ∞ ∞
Step 3 and Step 4: Calculate cumulative costs.
Copy code
0 5 8 13 17 21 25 29
∞ 8 10 14 20 23 26 30
∞ 12 14 18 22 26 29 32
∞ 16 18 20 23 27 30 34
∞ 20 23 24 26 30 33 37
∞ 24 27 28 31 35 38 41
∞ 28 31 32 35 38 41 44
∞ 32 35 36 39 42 45 48
Step 5: The DTW distance between X and Y is 48 (value in the bottom-right cell).
Step 6: The optimal warping path is as follows:
(1, 1) -> (2, 2) -> (3, 3) -> (4, 4) -> (5, 5) -> (6, 6) -> (7, 6) -> (8, 7) -> (8, 8)
This path represents the alignment between X and Y that minimizes the cumulative cost based on the given local cost function.
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The major difficulty of K-Means is the pre-requisite of the number of the cluster (K) that must be defined before the algorithm is applied to the input dataset.
If the plot results show the centroids are to close to each other, what should the researcher do first?
- Just reach the conclusion that the given input dataset is not suitable for this clustering approach.
- Do nothing and analyze the results as it is.
- Do not run K-Means and choose another clustering algorithm such as the hierarchical one.
-Decrease the number of clusters (K) and re-run the algorithm again.
-Increase the number of clusters (K) and re-run the algorithm again.
If the centroids in the K-Means algorithm are too close to each other, the researcher should first decrease the number of clusters (K) and re-run the algorithm again.
The K-Means algorithm is a popular clustering algorithm that partitions data into K clusters based on their similarity. However, one challenge in K-Means is determining the optimal number of clusters (K) before applying the algorithm.
If the plot results of K-Means show that the centroids are too close to each other, it suggests that the chosen number of clusters (K) might be too high. In such a scenario, it is advisable to decrease the number of clusters and re-run the algorithm.
By reducing the number of clusters, the algorithm allows for more separation between the centroids, potentially leading to more distinct and meaningful clusters. This adjustment helps to address the issue of centroids being too close to each other.
Alternatively, other actions mentioned in the options like concluding the dataset's unsuitability for K-Means, analyzing the results as they are, or choosing another clustering algorithm could be considered, but the initial step should be to adjust the number of clusters to achieve better results.
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Type the line of code that should go on the commented line below that changes this clone method to a deep copy as discussed in lecture. public IntArrayBag clone ( IntArrayBag answer, try 1 answer (IntArrayBag) super.clone; 1 catch(CloneNotSupported Exception e) 1 throw new RuntimeException("This class does not implement Cloneable."); ) //line of code to make a deep copy goes here return answer, Answer
In the given code snippet, the intention is to modify the clone method to perform a deep copy instead of a shallow copy.
This means that the cloned object should have its own separate copy of the data, rather than just pointing to the same data as the original object.To achieve a deep copy, the code needs to be updated within the commented line. Instead of simply calling super.clone, which performs a shallow copy, the code should create a new instance of the IntArrayBag class and copy the values from the original object to the new instance. This ensures that any modifications made to the cloned object do not affect the original object.
Once the deep copy is created, it should be assigned to the answer variable and returned as the result of the method. This modified code will produce a proper deep copy of the IntArrayBag object.
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The block diagram is used to show the main content and procedure of process design.
It is FALSE to state that the block diagram is used to show the main content and procedure of process design.
How is this so?The block diagram is not typically used to show the main content and procedure of process design.
Instead, a block diagram is a visual representation that illustrates the components and their interconnections within a system or process.
It focuses on the high-level overview of the system, highlighting major components or stages.
Process design, on the other hand, involves detailed planning and specification of the steps, inputs, outputs, and procedures involved in a specific process.
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Full Question:
Although part of your question is missing, you might be referring to this full question:
The block diagram is used to show the main content and procedure of process design. True or False?
What is the output of the following code? teams = { "NY": "Giants", "NJ": "Jets", "AZ"; "Cardinals" } print(list(teams.keys())) O [Giants', 'Jets', 'Cardinals'] O [NY', 'NJ', 'AZ'] O (Giants', 'Jets', 'Cardinals') O ('NY', 'NJ', 'AZ)
The corrected code should be:
teams = { "NY": "Giants", "NJ": "Jets", "AZ": "Cardinals" }
print(list(teams.keys()))
In the corrected code, a dictionary teams is defined with key-value pairs representing the names of different sports teams from various locations. The keys are the abbreviations of the locations ("NY", "NJ", and "AZ"), and the corresponding values are the names of the teams ("Giants", "Jets", and "Cardinals").
The list(teams.keys()) function is used to retrieve all the keys from the teams dictionary and convert them into a list. The keys() method returns a view object that contains all the keys of the dictionary. Wrapping it with list() converts the view object into a list.
The output of the code will be ['NY', 'NJ', 'AZ'], which is a list containing the keys of the teams dictionary. It represents the abbreviations of the locations for the sports teams.
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Complete the code below where the comment says Your code goes here, so the code compiles and runs. Enter the COMPLETE solution in the textbox below. Add a constructor to the Light Bulb class. The constructor takes an integer wattage of the bulb and a Variety enum type of the bulb. It sets the values to the class variables, wattage and variety respectively. Declare the constructor inside the class, then define it outside of the class. Program output: 0:2 2:60 #include #include using namespace std; class Light Bulb { public: enum Variety { LED, FLUORESCENT, INCANDESCENT }; /* Your code goes here */ int getWattage () { return wattage; } Variety getVariety() { return variety; } private: int wattage; Variety variety; }; /* Your code goes here */ int main() { vector availableDrives; availableDrives.push_back(Light Bulb (2, Light Bulb: :LED)); availableDrives.push_back(Light Bulb (60, Light Bulb::INCANDESCENT)); for (Light Bulb lb availableDrives) { cout << lb.getVariety() << " : << lb.getWattage() << endl; } }
To complete the code, a constructor needs to be added to the LightBulb class. The constructor should take an integer wattage and a Variety enum type as parameters and set the corresponding class variables.
The constructor should be declared inside the class and defined outside the class. In the main function, two LightBulb objects are created with specific wattage and variety values using the constructor. These objects are then added to the availableDrives vector. Finally, the wattage and variety of each LightBulb object in the vector are printed using the getWattage() and getVariety() member functions.
To add the constructor to the LightBulb class, the following code needs to be inserted inside the class declaration:
LightBulb(int wattage, Variety variety);
Then, outside the class, the constructor needs to be defined as follows:
LightBulb::LightBulb(int wattage, Variety variety) {
this->wattage = wattage;
this->variety = variety;
}
In the main function, the two LightBulb objects can be created and added to the vector as shown in the code snippet. Finally, a loop is used to iterate over the vector and print the variety and wattage of each LightBulb object using the getVariety() and getWattage() member functions.
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Which of the following set of dataframe functions best answers exercise 3 of lab 6?
a. filter, orderBy, show(10)
b. filter, select, join, orderBy, show(10)
c. filter, select, orderBy, show(10)
d. select, orderBy, show(1
The set of dataframe functions that best answers exercise 3 of lab 6 is option c: filter, select, orderBy, show(10). Option C is correct.
In exercise 3 of lab 6, we are typically interested in performing specific transformations on a dataframe. The filter function allows us to select rows that meet certain criteria, the select function helps us choose specific columns, and the orderBy function arranges the dataframe based on a given column. Finally, the show(10) function displays the top 10 rows of the resulting dataframe, giving us a preview of the transformed data. This combination of functions addresses the requirements of the exercise efficiently and succinctly.
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Which of the following is correct? a. An undirected graph contains both arcs and edges. O b. None of the other answers C. An undirected graph contains arcs. d. An undirected graph contains edges. Clear my choice Which of the following structures supports elements with more than one predecessor? a. Binary Tree b. Stack c. Queue d. None of the other answers .
Which of the following structures is limited to access elements only at structure end? a. Both Stack and Queue O b. Both List and Stack C. Both Queue and List O d. All of the other answers . Clear my choice
The correct answer to the first question is d. An undirected graph contains edges.
The correct answer to the second question is c. Queue.
The correct answer to the third question is a. Both Stack and Queue.
The correct answer to the first question is d. An undirected graph contains edges. In an undirected graph, edges represent connections between vertices that are bidirectional and have no inherent direction. This is different from a directed graph, where edges have an orientation and represent a one-way connection between vertices.
The correct answer to the second question is c. Queue. A queue is a data structure where elements are added at one end (the "rear") and removed from the other end (the "front"). It supports elements with more than one predecessor because elements can be added to the rear of the queue by multiple sources, but they will always be removed from the front in a first-in-first-out (FIFO) order.
The correct answer to the third question is a. Both Stack and Queue. Stacks and queues are both limited to accessing elements only at one end of the structure. In a stack, elements are added and removed from the top, while in a queue, elements are added at the rear and removed from the front. Lists and trees, on the other hand, allow access to any element within the structure.
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Suppose you want to detect circles of a given radius. What is
the dimension of the voting space? Describe how you would vote if
you were given edges and their orientation.
The dimension of the voting space for detecting circles of a given radius can be defined as the number of parameters required to describe a circle, which is three: x-coordinate of the center, y-coordinate of the center, and the radius. Voting involves accumulating evidence from the input data, in this case, edges and their orientation, to determine the presence and location of circles. Each vote corresponds to a potential circle center and radius combination, and the voting space represents the range of possible values for these parameters.
To detect circles of a given radius, the voting process involves iterating over the edges and their orientation in the input data. For each edge, the algorithm would calculate the possible center coordinates and radius values that correspond to a circle with the given radius. These combinations would be used as votes in the voting space.
The voting space would consist of a grid or a parameter space that spans the possible values for the center coordinates (x and y) and the radius. Each grid cell or parameter combination represents a potential circle. As the algorithm processes the edges and their orientation, it increments the vote count for the corresponding grid cells or parameter combinations in the voting space.
After processing all the edges, the cells or parameter combinations with the highest vote count in the voting space would indicate the most likely circle centers and radii. By examining these areas of high votes, the algorithm can identify the detected circles.
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Question 1
In MPS, we have 3 types of instructions R type. I type and I type. In some of them, we use the keyword limited. What is the size of that part? a. 1 byte b. 2 bytes
c. 4 bytes d. 8 bytes
e. 16 bytes
Based on the given options, the most common and widely used sizes for the "limited" part in MPS instructions are typically either 4 bytes or 8 bytes.
In many modern computer architectures, the "limited" part of an instruction refers to the field or operand that specifies a limited or bounded range of values. This part is used to define the range or limitations for certain operations or data manipulation. The size of this part is crucial for determining the maximum value that can be represented or operated upon within the instruction.
While there can be variations in different systems and architectures, the most commonly used sizes for the "limited" part in MPS instructions are 4 bytes (32 bits) and 8 bytes (64 bits). These sizes provide a reasonable range of values for most instructions, allowing for efficient and effective instruction execution.
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USE JAVA CODE
Write a recursive method that takes an integer as a parameter (ℎ ≥ 1) . The method should compute and return the product of the n to power 3 of all integers less or equal to . Then, write the main method to test the recursive method. For example:
If =4, the method calculates and returns the value of: 13 * 23 * 33 * 44= 13824
If =2, the method calculates and returns the value of: 13 * 23 = 8
Sample I/O:
Enter Number (n): 4
The result = 13824
Average = 4.142
Enter Number (n): 2
The result = 8
Average = 4.142
The Java program contains a recursive method to calculate the product of n to power 3 of all integers less than or equal to n. The main method prompts the user to enter a positive integer and calls the recursive method to calculate the result.
Here's a Java code that implements the recursive method to calculate the product of n to power 3 of all integers less than or equal to n:
```java
import java.util.Scanner;
public class Main {
public static int product(int n) {
if (n == 1) {
return 1;
} else {
return (int) Math.pow(n, 3) * product(n - 1);
}
}
public static void main(String[] args) {
Scanner scanner = new Scanner(System.in);
int n;
do {
System.out.print("Enter Number (n): ");
n = scanner.nextInt();
} while (n < 1);
int result = product(n);
System.out.println("The result = " + result);
System.out.println("Average = " + (result / (double) n));
}
}
```
The `product` method is a recursive function that takes an integer `n` as a parameter and returns the product of n to power 3 of all integers less than or equal to `n`. If `n` is 1, the method returns 1. Otherwise, it calculates the product of n to power 3 of all integers less than or equal to `n - 1` and multiplies it by `n` to power 3.
The `main` method prompts the user to enter a positive integer `n` and calls the `product` method to calculate the product of n to power 3 of all integers less than or equal to `n`. It then prints the result and the average value of the product.
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Help on knowledge representation and probabilistic reasoning please
Convert the following expressions in a knowledge base into conjunctive normal form. Use
proof by resolution to prove that JohAI Que
Show transcribed data
Convert the following expressions in a knowledge base into conjunctive normal form. Use proof by resolution to prove that John does not get wet. (ru) if it rains, John brings his umbrella. • (u→→w) if John has an umbrella, he does not get wet. (→→→w) if it doesn't rain, John does not get wet.
Since we were able to derive an empty clause (i.e., a contradiction), the original assumption that w is true must be false. Therefore, John does not get wet, as required.To convert the expressions into conjunctive normal form (CNF), we need to apply several logical equivalences and transformations.
First, we can use implication elimination to rewrite the first expression as:
(¬r ∨ b) ∧ (¬b ∨ ¬w)
where r, b, and w represent the propositions "It rains", "John brings his umbrella", and "John gets wet", respectively.
Next, we can similarly eliminate the implication in the second expression and apply double negation elimination to obtain:
(¬u ∨ ¬w)
Finally, we can negate the third expression and use implication elimination to obtain:
(r ∨ w)
Now that all three expressions are in CNF, we can combine them into a single knowledge base:
(¬r ∨ b) ∧ (¬b ∨ ¬w) ∧ (¬u ∨ ¬w) ∧ (r ∨ w)
To prove that John does not get wet, we can assume the opposite, i.e., that w is true, and try to derive a contradiction using resolution. We add the negation of the conclusion (¬w) to the knowledge base, resulting in:
(¬r ∨ b) ∧ (¬b ∨ ¬w) ∧ (¬u ∨ ¬w) ∧ (r ∨ w) ∧ ¬w
We then apply resolution repeatedly until either a contradiction is derived or no further resolvents can be produced. The resolution steps are:
1. {¬r, b} [from clauses 1 and 5]
2. {¬b} [from clauses 2 and 6]
3. {¬u} [from clauses 3 and 7]
4. {r} [from clauses 1 and 8]
5. {w} [from clauses 4 and 9]
6. {} [from clauses 2 and 5]
7. {} [from clauses 3 and 6]
8. {} [from clauses 4 and 7]
9. {} [from clauses 5 and 8]
Since we were able to derive an empty clause (i.e., a contradiction), the original assumption that w is true must be false. Therefore, John does not get wet, as required.
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4. [4 marks] The Fibonacci sequence is a series where the next term is the sum of pervious two terms. The first two terms of the Fibonacci sequence is 0 followed by 1. The Fibonacci sequence: 0, 1, 1, 2, 3, 5, 8, 13, 21, etc. The implementation of C++ programme using while-loop can be given as below. The code contains error. Debug the programme so that it can be compiled and run properly. #include using namespace std; int main(); ( int t1 = 0, t2 = 1, nextTerm = 0, n; cout << "Enter a positive number: "; cin >>n; // displays the first two terms which is always 0 and 1 cout << "Fibonacci Series: " << tl << ", " << t2 << ", "; nextTerm= tl + t2; while (next Term <= n, n++); 1 cout
Here's the corrected code with comments explaining the changes made:
#include <iostream>
using namespace std;
int main() { // corrected function signature
int t1 = 0, t2 = 1, nextTerm, n;
cout << "Enter a positive number: ";
cin >> n;
// displays the first two terms which is always 0 and 1
cout << "Fibonacci Series: " << t1 << ", " << t2 << ", ";
while (t2 + nextTerm <= n) { // fixed the while loop condition
nextTerm = t1 + t2;
cout << nextTerm << ", ";
t1 = t2;
t2 = nextTerm;
}
return 0; // added missing return statement
}
The main issue with the original code was that it had a syntax error in the while loop condition. The comma operator used in the original code evaluated n++ as a separate expression, which led to an infinite loop. I replaced the comma with a + operator to correctly check whether the sum of t2 and nextTerm is less than or equal to n. Additionally, I added a missing return statement at the end of the function.
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Please solve the question for
beginners in programming using java language
**very important just use import java .util.Scanner;
don’t use java.util.inputMismatchException;
building a Calculator Program.
A. Write a Java Calculator Program that performs the following operations:
1. Addition of two numbers
2. Subtraction of two numbers
3. Multiplication of two numbers
4. Division of two numbers
5. Modulus (a % b)
6. Power (ab)
7. Square root of x (√x)
8. Factorial of a number (n!)
9. Log(n)
10. Sin(x)
11. Absolute value (|x|)
12. Average of given numbers in array
B. Print a calculator shape, then show a list of the available operations classified with
their numbers from 1-12.
C. The user should be allowed to input the right number of the required operation, and
then enter the input data to do the required operation.
D. Use switch-case statement to select the required operation and invoke its appropriate
method. You should validate the input data before invoking any operation.
E. The program is supposed to enable the user to use the calculator repeatedly until the sentinel value 0 is entered for the required operation (i.e. when 0 is entered the program finishes).
F. Define your own methods that invoke the right methods from the main method to do the required operations. For example:
public static double sine(double a)
H. You should use different types of loops (for, while, do-while) for inputs, processing and
outputs
In this beginner-level Java programming exercise, you are required to build a calculator program using the java.util.Scanner class.
The program uses the java.util.Scanner class to accept user inputs and a switch-case statement to handle different operations. The operations include basic arithmetic functions like addition, subtraction, multiplication, and division, as well as more advanced operations like modulus, power, square root, factorial, logarithm, sine, absolute value, and average.
The user is presented with a calculator shape and a list of available operations, and they can enter the corresponding number to select an operation. The program then prompts the user for the required input data and performs the chosen operation. The user can continue using the calculator until they enter 0 to exit the program. Different types of loops are used to handle the input, processing, and output stages of the program.
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24. Display all the students records except those whose Address is equals Taguig. SELECT______ FROM `student` WHERE ______
25. Delete all the records whose Score is both 80 and 85. DELETE FROM `student` WHERE Score____ _____ Score______ 26. Display all the Students records whose Surname is equals to "Reyes". SELECT _____ FROM `student` WHERE_____
27. Display only the Firstname of all the Female students. SELECT _____FROM `student` WHERE______ 28. Change all the the address from "Makati" to "Pasig" UPDATE student` SET _____ = _____WHERE ____=_____
To perform the specified actions in SQL, the following queries can be used:
To display all student records except those with the address "Taguig":
SELECT * FROM student WHERE Address != 'Taguig'
To delete all records with a score of both 80 and 85:
DELETE FROM student WHERE Score IN (80, 85)
To display all student records whose surname is "Reyes":
SELECT * FROM student WHERE Surname = 'Reyes'
To display only the first names of all female students:
SELECT Firstname FROM student WHERE Gender = 'Female'
To change the address from "Makati" to "Pasig" for all students:
UPDATE student SET Address = 'Pasig' WHERE Address = 'Makati'
The query uses the WHERE clause with the condition Address != 'Taguig' to select all student records whose address is not equal to "Taguig".
The query uses the WHERE clause with the condition Score IN (80, 85) to delete all student records with a score of either 80 or 85.
The query uses the WHERE clause with the condition Surname = 'Reyes' to select all student records with the surname "Reyes".
The query uses the WHERE clause with the condition Gender = 'Female' to select all student records with the gender "Female" and only retrieves the Firstname column.
The query uses the UPDATE statement to change the address from "Makati" to "Pasig" for all student records where the address is "Makati".
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Final Program: Graphical User Interface This final part of the project is the last for the birthday paradox program and combines everything from the modules to simulate the scenario of people in a group sharing a birthday. For this task you'll be required to create a Graphical User Interface (GUI) that calls the user-defined functions you created in module 2 to help perform the simulation. Graphical User Interfaces are what we're most familiar with when using computer programs; they consist of pop-up windows with buttons, text boxes, drop-down menus, radio buttons and other graphical elements that can be interacted with by a user to input information into the program. User-defined functions allow for effective code reuse and is good programming practice when creating programs that require the same or similar code to be executed many times. function out = MyFunction (ini, in2) % Rename function and input/output variables to appropriate name (not MyFunction) $ Insert code here to perform appropriate functions. out = % Set output variable to the appropriate value I Assessment Requirements: For this part of the project, you're required to simulate the birthday scenario: Call your function from module 2a to assign random birthdays to people in an increasingly large group of people (starting with a group size of 2 people and ending with a group size of 365). This function can be modified so it just generates whole numbers from 1 to 365 to represent each day (rather than the day/month format from module 2a), this will make the program less computationally complex but will still give you the same result. Use the function from module 2b to check these dates to see if there are any repeated birthdays in the groups. Keep a record of any matches discovered. Using the knowledge gained from module 1, you'll then plot a graph of the probabilities of a shared birthday from your simulation with a graph of the theoretical model overlayed (x-axis = group size, y-axis = probability). The graph must be displayed on your GUI (so you'll use app.UlAxes to display your results). To obtain a close statistical model to the theory, you'll need to repeat your simulation many times and take the average over the number of realisations (at least 10 times, but less than 500 times to ensure the simulation doesn't take too long). Other GUI Functionality and Considerations: Your GUI must be able to obtain user input including: How many realisations does the user want in order to obtain an estimate the probability of a shared birthday (allow user to select numbers between 10 and 500). This will allow the simulation to either be fast but less accurate (10 times) or slow and more accurate (500 times). The maximum group size the user wants simulated. This will truncate the graph to the maximum group size. The range of this must be a minimum of 2 people and a maximum of 365 people in a group. You'll need to think not only about the way your program calculates the output required to solve the problem (its functionality) but also how your GUI will look (its aesthetics) and how simple it is for a user to input and receive output from your program (its usability). Your graphical user interface (GUI) must be created in App Designer (DO NOT use the menu () or dialog() functions or GUIDE!!!). You must submit the.mlapp file and user- defined functions in .m file format for assessment. Due date and further details on this task: The final submission for this project is due at the end of week 9 (Friday, before 11:59pm). You are required to submit your work to the Canvas Quiz called Individual Project (Final Module). Your submission will include the following: A problem statement An algorithm design (in the form of flow-charts) MATLAB files (Including the GUI file (.mlapp) and your user-defined function files (.m files)). A .zip file containing these files will also be acceptable. Evidence that you have testing your program and ensured it outputs results consistent with the theory. More detail can be found on Canvas under Modules -> Week 1 -> Assessment Task Instructions (IMPORTANT) -> Individual Project Instructions.
For this final part of the project, you are required to create a Graphical User Interface (GUI) using App Designer in MATLAB.
The GUI should call the user-defined functions created in module 2 to simulate the birthday scenario. The GUI should allow the user to input the number of realizations they want and the maximum group size to be simulated. The number of realizations should be between 10 and 500, while the group size should range from 2 to 365.The GUI should use the user-defined functions to assign random birthdays to people in increasingly larger groups, check for repeated birthdays, and keep a record of any matches discovered. It should then plot a graph of the probabilities of a shared birthday, overlaying it with the theoretical model.
The GUI should be aesthetically pleasing, user-friendly, and provide clear instructions for input and output. It should allow the user to obtain accurate results by adjusting the number of realizations. For the final submission, you need to include the problem statement, algorithm design in the form of flowcharts, MATLAB files (including the GUI file and user-defined function files), and evidence of testing to ensure consistent results with the theory.
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STAGE 1 | (Word Histogram)
Design and implement a program called "WordHistogram.java" that creates a histogram that allows you to
visually inspect the frequency distribution of a set of words in a given file. The program should read the
input filename and output filename as command line arguments. A word is defined as a collection of letters
a-z and A-Z
For example, if the input file is:
How much wood would a woodchuck chuck
If a woodchuck could chuck wood?
He would chuck, he would, as much as he could,
And chuck as much wood as a woodchuck would
If a woodchuck could chuck wood.
The output file will contain:
a : 4
and : 1
as : 4
chuck : 5
could : 3
he : 3
how : 1
if : 2
much : 3
wood : 4
woodchuck : 4
would : 4
Hint:
create a StringBuilder
While(inputFile.hasNext())
{
Read a line
add "\n" to end of line
append the line to the buffer replacing all non alphabetical characters with "\n"
String s1 = s.replaceAll("[^a-zA-Z]+","\n").toLowerCase();
}
Create an array of String by splitting the buffer
Word Histogram | File processing
COMP 110
sort the array
Add up unique words
print the result in the output file
STAGE 2 | Testing
Download "infile.txt" and test your program as follows:
Java WordHistogram infile.txt outfile.txt
HINTS:
Check the following classes:
ArrayList
String
Collections
Submit "WordHistogram.java" and "outfile.txt"
The program "WordHistogram.java" is designed to create a histogram that displays the frequency distribution of words in a given file.
To accomplish this, the program follows several steps. First, it creates a StringBuilder to store the contents of the input file. It reads the input file line by line, appends each line to the buffer, and replaces all non-alphabetical characters with newline characters. This step ensures that each word is separated by a newline character in the buffer.
Next, the program creates an array of strings by splitting the buffer using newline characters as delimiters. This array contains all the words from the input file. The program then sorts the array to group identical words together.
After sorting the array, the program iterates through it and calculates the frequency of each unique word. It keeps track of the word frequency using a counter variable. When a new word is encountered, the program adds the word and its frequency to a collection.
Finally, the program prints the result in the output file. It writes each unique word along with its frequency in the format "word : frequency" on separate lines.
To test the program, you need to download the provided "infile.txt" file and run the program with the command "Java WordHistogram infile.txt outfile.txt". This will read the contents of "infile.txt", generate the histogram, and store the result in the "outfile.txt" file.
By following these steps, the "WordHistogram.java" program effectively creates a histogram of word frequencies in a given file and outputs the result to another file.
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package Chapter Four. AreaCircleQ9; import java.util.*; import java.math.*; public class Circle { El public static void setRadius () { A A E A E A } Scanner scanner = new Scanner (System.in); int ri, ro; System.out.println("Inner circle radius:"); ri = scanner.nextInt (); System.out.println("Outer circle radius:"); ro = scanner.nextInt (); } public static double getAreaInner(int ri) { double areaInner; areaInner = 3.14*Math.pow(ri, 2); return areaInner; } public static double getAreaOuter (int ro){ double areaOuter; areaOuter = 3.14*Math.pow(ro, 2); return areaOuter; } public static void main(String[] args) { }
This is a Java program that calculates the area of inner and outer circles based on user input for their radii.
The setRadius() method prompts the user to enter the radii of the inner and outer circles using a Scanner object, and stores them in the variables ri and ro.
The getAreaInner() and getAreaOuter() methods take the radius of the inner and outer circles respectively as input parameters, and use the formula for the area of a circle to calculate and return their respective areas.
The main method is currently empty and does not have any code inside it.
Note that there are some syntax errors in the code, such as missing braces and semicolons, which would prevent it from compiling successfully.
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engineeringcomputer sciencecomputer science questions and answersfill in the missing code in python write both recursive and iterative function to compute the fibonacci sequence. how does the performance of the recursive function compare to that of an iterative version? f(0) = 0 f(1) = 1 f(n) = f(n-1)+f(n-2), for n >= 2 ------------------------------------------------------------ import timeit import random
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Question: Fill In The Missing Code In Python Write Both Recursive And Iterative Function To Compute The Fibonacci Sequence. How Does The Performance Of The Recursive Function Compare To That Of An Iterative Version? F(0) = 0 F(1) = 1 F(N) = F(N-1)+F(N-2), For N >= 2 ------------------------------------------------------------ Import Timeit Import Random
Fill in the missing code in python
Write both recursive and iterative function to compute the Fibonacci sequence.
How does the performance of the recursive function compare to that of an iterative version?
F(0) = 0
F(1) = 1
F(n) = F(n-1)+F(n-2), for n >= 2
------------------------------------------------------------
import timeit
import random as r
import string
def fib_r (n):
"""recursive approach"""
# xxx fill in the missing codes
pass
def fib_i ( n):
"""iterative approach with for-loop"""
# xxx fill in the missing codes
pass
oa = timeit.Timer("fib_r(n)", "from __main__ import fib_r,n")
ob = timeit.Timer("fib_i(n)", "from __main__ import fib_i,n ")
s = "{0:>8s}: {1:^15s} {2:^15s}".format("n", "fib_r", "fib_i")
print (s)
num_repeats = 1 # 100000
m = 1
X= list ( range ( 20,30,2))
A=[]; B=[];
for n in X :
ok = fib_r(n) == fib_i(n)
assert ok
if not ok: break;
a = oa.timeit(number=num_repeats)
b = ob.timeit(number=num_repeats)
A.append ( a )
B.append ( b )
s = "{0:>8d}: {1:^15.5f} {2:^15.5f}".format(n,a,b)
print (s)
import matplotlib.pyplot as plt
plt.figure(figsize=(7,5))
plt.plot(X, A, label='recursive')
plt.plot(X, B, label="iterative")
plt.legend(loc="upper center", fontsize="large")
plt.show()
------------------------------------------------------------
In this code, the missing parts have been filled in the fib_r and fib_i functions to compute the Fibonacci sequence recursively and iteratively, respectively. The fib_r function uses recursion to calculate the Fibonacci numbers, while the fib_i function uses an iterative approach with a for-loop.
Here is the complete code with the missing parts filled in:
python
Copy code
import timeit
def fib_r(n):
"""Recursive approach"""
if n == 0:
return 0
elif n == 1:
return 1
else:
return fib_r(n-1) + fib_r(n-2)
def fib_i(n):
"""Iterative approach with for-loop"""
if n == 0:
return 0
elif n == 1:
return 1
else:
a, b = 0, 1
for _ in range(2, n+1):
a, b = b, a + b
return b
oa = timeit.Timer("fib_r(n)", "from __main__ import fib_r, n")
ob = timeit.Timer("fib_i(n)", "from __main__ import fib_i, n")
s = "{0:>8s}: {1:^15s} {2:^15s}".format("n", "fib_r", "fib_i")
print(s)
num_repeats = 1
m = 1
X = list(range(20, 30, 2))
A = []
B = []
for n in X:
ok = fib_r(n) == fib_i(n)
assert ok
if not ok:
break
a = oa.timeit(number=num_repeats)
b = ob.timeit(number=num_repeats)
A.append(a)
B.append(b)
s = "{0:>8d}: {1:^15.5f} {2:^15.5f}".format(n, a, b)
print(s)
import matplotlib.pyplot as plt
plt.figure(figsize=(7, 5))
plt.plot(X, A, label='recursive')
plt.plot(X, B, label="iterative")
plt.legend(loc="upper center", fontsize="large")
plt.show()
The code then measures the performance of both functions using the timeit module and prints the results. Finally, a plot is generated using matplotlib to compare the performance of the recursive and iterative functions for different values of n.
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Given below code snippet () -> 7 * 12.0; Which of the following interfaces can provide the functional descriptor for the above lambda expression? O interface A{ default double m() { return 4.5; } } O interface DX double m(Integer i); } O interface B{ Number m(); } O interface C{ int m); }
The lambda expression can be described by interface B, as it has a method "m()" returning a Number, matching the return type of the lambda expression.
The lambda expression in the code snippet, "() -> 7 * 12.0;", represents a function that takes no arguments and returns the result of multiplying 7 by 12.0. Among the given interfaces, only interface B can provide the functional descriptor for this lambda expression. Interface B declares a method "m()" that returns a Number. Since the lambda expression returns a numerical value, it can be assigned to the "m()" method of interface B.
Interface A's method "m()" returns a double value, which is not compatible with the lambda expression's return type of a multiplication operation. Interface DX's method "m(Integer i)" expects an Integer parameter, which the lambda expression does not have. Interface C's method "m" is missing the closing parenthesis and has an incompatible return type of int instead of the required Number.
Therefore, interface B is the only option that matches the lambda expression's return type and parameter requirements, making it the correct interface to provide the functional descriptor for the lambda expression.
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Which of the following types of connectors is used to create a Cat 6 network cable? A. RG-6
B. RJ11
C. RJ45
D. RS-232 A company executive is traveling to Europe for a conference. Which of the following voltages should the executive's laptop be able to accept as input? A. 5V B. 12V
C. 110V
D. 220V
A technician is working on a computer that is running much slower than usual. While checking the HDD drive, the technician hears a clicking sound. S.M.A.R.T. does not report any significant errors. Which of the following should the technician perform NEXT? A. Update the HDD firmware.
B. Check the free space.
C. Defragment the drive.
D. Replace the failing drive.
1. C. RJ45 - RJ45 connectors are used to create a Cat 6 network cable.
2. D. 220V - In Europe, the standard voltage is 220V, so the laptop should be able to accept this input voltage.
3. D. Replace the failing drive - Hearing a clicking sound from the HDD, even if S.M.A.R.T. does not report errors, is an indication of a failing drive. The best course of action would be to replace the failing drive.
If the technician hears a clicking sound from the HDD and S.M.A.R.T. does not report any significant errors, it indicates a mechanical failure within the hard drive.
Clicking sounds often indicate a failing drive. The best course of action in this scenario is to replace the failing drive to prevent further data loss and ensure the computer's performance is restored.
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12. Which one of the following indicates a crontab entry that specifies a task that will be run on Sunday at 11 a.m.?
* 11 7 * *
0 11 * 7 *
0 11 * * 7
11 0 * 7 *
The crontab entry that specifies a task to run on Sunday at 11 a.m. is "0 11 * * 7."
The crontab entry "0 11 * * 7" indicates that the task will be executed at 11 a.m. on any day of the month, any month of the year, but only on Sunday. To understand this entry, it's important to know the format of a crontab schedule. The first field represents the minute (0 in this case), the second field represents the hour (11 in this case), the third field represents the day of the month (asterisk indicates any day), the fourth field represents the month (asterisk indicates any month), and the fifth field represents the day of the week (7 represents Sunday). Therefore, the specified task will run every Sunday at 11 a.m., regardless of the specific day of the month or month of the year.
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Given a tree, defined by the following 3-tuples (parent, child, L/R) (where L and R indicate Left or Right neighbor): (A,B, L),(A,C, R),(B,D, L),(B,E, R),(C,G, R),(E,F, R),(G,H, L),(G,I, R),(I,J, R) First, draw the tree on paper (you don't need to upload this). Then, Show the following orders on this tree: Pre-Order: Post-Order: In-Order: Level-Order: Given the following undirected, weighted graph, defined by these 3-tuples (node, node, weight): (A,B,2),(A,C,1),(A,D,2), (B,C,3), (B,E,3),(C,D,3),(C,E,1),(C,F,4),(C,G,3),(D,F,3),(E,G,3),(F,G,4) Show the tuples for the edges included in a Minimum Spanning Tree: Why did you pick the node you picked to start from? If you picked another node, could the total weights of the selected edges be smaller?
To draw the tree and show the different orders, you can follow these steps: Start by drawing the root node 'A'. Connect the child nodes 'B' and 'C' to 'A' using the given left and right neighbors.
Connect the child nodes 'D' and 'E' to 'B' using the left and right neighbors. Connect the child node 'G' to 'C' using the right neighbor. Connect the child nodes 'F' to 'E' and 'H' and 'I' to 'G' using the given neighbors. Connect the child node 'J' to 'I' using the right neighbor. Now, let's show the different orders: Pre-Order: A, B, D, E, F, H, I, J, C, G; Post-Order: D, F, H, J, I, E, B, G, C, A; In-Order: D, B, H, F, J, I, E, A, G, C; Level-Order: A, B, C, D, E, G, F, H, I, J. For the undirected, weighted graph, the minimum spanning tree (MST) can be found using Prim's or Kruskal's algorithm. Since you didn't specify the starting node, let's assume we start from node 'A'.
The tuples for the edges included in the MST are: (A, C, 1); (A, B, 2); (C, E, 1); (E, G, 3); (G, H, 3); (G, I, 4); (D, F, 3); We picked node 'A' as the starting node because it has the minimum weight edge connected to it. In this case, the edge (A, C, 1) has the smallest weight compared to other edges connected to 'A'. Starting from a different node would yield a different MST, but it may not necessarily have a smaller total weight. The choice of the starting node can affect the overall structure of the MST, but the total weight of the MST depends on the weights of the edges and not solely on the starting node.
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You are required to implement a preprocessor in Java. Your preprocessor should be able to perform the following tasks on an input file, which will be a Java source file: 1. Removing comments (40 points) Example: Input: import java.util.Scanner: public class Course ( String courseName; String courseCode: public Courne () ( Scanner myobj = new Scanner (System.in); // Create a Scanner object System.out.println("Enter new course name:"); courseName = myObj.nextLine(); // Read user input System.out.println("Enter now course code:"; courseCode = nyobj.nextLine(); // Read user input } public void printCourse() ( System.out.println("Course name: "+courseNano); System.out.println("Course code: "+courseCode): } Output: import java.util.Scanner: 14 5 public class Course ( 6 String courseName: String courseCode: public Course () ( Scanner myobj = new Scanner (System.in); System.out.println("Enter new course name:"); courseName = myobj.nextLine(); 12 13 System.out.println("Enter new course code: "); courseCode - myObj.nextLine(); 14 15 16 public void print Course () ( System.out.println("Course name:"+coursellame); System.out.println("Course code: "+courseCode); 19 2222
To implement a preprocessor in Java that can perform the given tasks (removing comments), you can use regular expressions to identify and remove the comments from the input Java source file. Here's a sample implementation that achieves the desired functionality:
import java.io.BufferedReader;
import java.io.FileReader;
import java.io.FileWriter;
import java.io.IOException;
import java.util.regex.Matcher;
import java.util.regex.Pattern;
public class JavaPreprocessor {
public static void main(String[] args) {
String inputFile = "input.java"; // Replace with the actual input file path
String outputFile = "output.java"; // Replace with the desired output file path
preprocess(inputFile, outputFile);
}
public static void preprocess(String inputFile, String outputFile) {
try (BufferedReader reader = new BufferedReader(new FileReader(inputFile));
FileWriter writer = new FileWriter(outputFile)) {
String line;
Pattern commentPattern = Pattern.compile("//.*|/\\*.*?\\*/", Pattern.DOTALL);
while ((line = reader.readLine()) != null) {
Matcher commentMatcher = commentPattern.matcher(line);
line = commentMatcher.replaceAll("");
writer.write(line + "\n");
}
} catch (IOException e) {
e.printStackTrace();
}
}
}
In this implementation, the preprocess method reads the input file line by line, applies a regular expression pattern to match and remove both single-line (//) and multi-line (/* */) comments from each line. The resulting processed lines are then written to the output file.
To use this implementation, replace the inputFile and outputFile variables with the actual file paths of your input and desired output files. After running the preprocess method, the output file will contain the input Java source code with the comments removed.
Please note that this is a basic implementation and does not handle all possible cases and variations of comments in Java source code. It's recommended to thoroughly test the preprocessor with different inputs to ensure it meets your requirements.
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The code must be written in java.
Create a bus ticketing system that have at least 7 classes.
A Java bus ticketing system can be implemented using at least 7 classes to manage passengers, buses, routes, tickets, and bookings.
A bus ticketing system in Java can be implemented using the following classes:
1. Passenger: Represents a passenger with attributes such as name, contact information, and booking history.
2. Bus: Represents a bus with attributes like bus number, capacity, and route information.
3. Route: Represents a bus route with details such as starting and ending points, distance, and duration.
4. Ticket: Represents a ticket with details like ticket number, passenger information, bus details, and fare.
5. Booking: Manages the booking process, including seat allocation, availability, and payment.
6. TicketManager: Handles ticket-related operations like issuing tickets, canceling tickets, and generating reports.
7. BusTicketingSystem: The main class that coordinates the interactions between the other classes and serves as an entry point for the application.
These classes work together to provide functionalities such as booking tickets, managing passenger information, maintaining bus schedules, and generating reports for the bus ticketing system.
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Sentinel-controlled iteration is also known as: a. Definite iteration. b. Indefinite iteration. C. Multiple iteration. d. Double iteration.
Sentinel-controlled iteration is a type of indefinite iteration where a special sentinel value is used to terminate the loop. So, the correct answer is (b) Indefinite iteration.
Iteration is a fundamental concept in computer programming that involves repeating a sequence of instructions until some condition is met. There are generally two types of iteration: definite and indefinite iteration.
Definite iteration involves executing a set of instructions for a predetermined number of times. For example, if we want to print the numbers from 1 to 10, we can use a for loop with a range of 1 to 11. In this case, the number of iterations is fixed, and we know exactly how many times the loop will execute.
Indefinite iteration, on the other hand, involves executing a set of instructions until some condition is met. This type of iteration is commonly used when we don't know how many times we need to repeat a certain operation. Sentinel-controlled iteration is a specific type of indefinite iteration where we use a special sentinel value to terminate the loop.
For instance, in a program that reads input from a user until they enter "quit", the sentinel value would be "quit". The loop will continue executing until the user enters "quit" as input. Sentinel-controlled iteration is useful because it allows us to terminate the loop based on user input or any other external factor, making our programs more flexible and interactive.
The correct answer is (b) Indefinite iteration.
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Implement the method is_independent (S) that returns True if the set S of Vec objects is linearly independent, otherwise returns False . In [ ]: def is_independent (S): #todo pass
The method `is_independent(S)` determines whether a set `S` of `Vec` objects is linearly independent. It returns `True` if the set is linearly independent, indicating that no vector in `S` can be expressed as a linear combination of the other vectors in the set. Otherwise, it returns `False`.
To determine whether the set `S` is linearly independent, we can perform the following steps:
1. Check if the set `S` is empty. If it is, then it is considered linearly independent because there are no vectors to evaluate.
2. If the set `S` is not empty, we can select any vector `v` from `S` and express it as a linear combination of the remaining vectors in `S`. If this expression is possible, it implies that `v` is dependent on the other vectors, and therefore, the set `S` is linearly dependent.
3. Repeat step 2 for each vector in `S`. If we find that at least one vector can be expressed as a linear combination of the others, then the set `S` is linearly dependent and we return `False`.
4. If none of the vectors in `S` can be expressed as a linear combination of the others, then the set `S` is linearly independent, and we return `True`.
By applying these steps, we can determine whether a given set of `Vec` objects is linearly independent or not.
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I have the codes below and the output is given. What I need help with is these things:
- How to make the decimals up to TWO decimal points, like 0000.00 for the amounts and interest
- How can I get the Date Created to reflect the current time
- How to show the amount that was deposited and withdrawn in each account?
Please edit the codes below to reflect what is asked:
/*
Exercise 11.4 (Subclasses of Account):
In Programming Exercise 9.7, the Account class was defined to model a bank account.
An account has the properties account number, balance, annual interest rate,
and date created, and methods to deposit and withdraw funds.
Create two subclasses for checking and saving accounts.
A checking account has an overdraft limit, but a savings account cannot be overdrawn.
Write a test program that creates objects of Account, SavingsAccount, and CheckingAccount
and invokes their toString() methods.
Notes:
- One PUBLIC Class (Exercise11_04)
Three default classes in order:
- Class Account
- Class SavingsAccount
- Class CheckingAccount
*/
package exercise11_04;
import java.util.Date;
public class Exercise11_04 {
public static void main(String[] args) {
Account a1 = new CheckingAccount(123456,5565,2.4,"21/01/2005",3000);
System.out.println("\nAccount 1 : "+a1);
a1.withdraw(7000);
System.out.println("Balance after withdrawing : $"+a1.balance);
Account a2 = new CheckingAccount(665456,7786,1.5,"11/02/2004",4500);
System.out.println("\nAccount 2 : "+a2);
Account a3 = new SavingAccount(887763,4887,1.4,"12/12/2012");
System.out.println("\nAccount 3 : "+a3);
a3.withdraw(1200);
System.out.println("Balance after withdrawing : $"+a3.balance);
a3.withdraw(4000);
System.out.println("Balance after withdrawing : $"+a3.balance);
}
}
// //////////////////////////////////////////////////////////////////
//class named Account
class Account{
// class variables
int accountnum;
double balance;
double annualintrestrate;
String datecreated;
// constructor
Account(int accountnum, double balance, double annualintrestrate, String datecreated){
this.accountnum = accountnum;
this.annualintrestrate = annualintrestrate;
this.balance = balance;
this.datecreated = datecreated;
}
// deposit method
public void deposit(double amount) {
balance += amount;
}
// withdraw method
public void withdraw(double amount) {
// if amount is not sufficient
if(balance - amount < 0) {
System.out.println("Insufficient Balance");
}
else {
balance -= amount;
}
}
// toString method that return details
public String toString() {
return ("\nAccount Number : "+accountnum+"\nAnnual Intrest Rate : "+annualintrestrate+"\nBalance : $ "+balance+"\nDate Created : "+datecreated);
}
}
////////////////////////////////////////////////////
//CheckingAccount class that inherits Account class
class CheckingAccount extends Account{
// class members
double overdraftlimit;
// constructor
public CheckingAccount(int accountnum, double balance, double annualintrestrate, String datecreated, double overdraftlimit) {
super(accountnum, balance, annualintrestrate, datecreated);
this.overdraftlimit = overdraftlimit;
}
// withdraw method
public void withdraw(double amount) {
// if withdraw amount is greater than overdraftlimit
if(balance +overdraftlimit - amount < 0) {
System.out.println("Insufficient Balance , You have crossed overdraft limit.");
}
// else reduce amount and print if overdraft amount is used
else {
balance -= amount;
}
if(balance < 0) {
System.out.println("Overdrafted amount : "+Math.abs(balance));
}
}
// updated toString method
public String toString() {
return super.toString()+"\nAccount Type : Checking \nOverDraft limit : "+overdraftlimit ;
}
}
////////////////////////////////////////////////////////////////////////////
// SavingAccount class that inherits Account
class SavingAccount extends Account{
// constructor
public SavingAccount(int accountnum, double balance, double annualintrestrate, String datecreated) {
super(accountnum, balance, annualintrestrate, datecreated);
}
// toString method
public String toString() {
return super.toString()+"\nAccount Type : Saving";
}
}
_________________________________________________________________________________
Output:
Account 1 :
Account Number : 123456
Annual Intrest Rate : 2.4
Balance : $ 5565.0
Date Created : 21/01/2005
Account Type : Checking
OverDraft limit : 3000.0
Overdrafted amount : 1435.0
Balance after withdrawing : $-1435.0
Account 2 :
Account Number : 665456
Annual Intrest Rate : 1.5
Balance : $ 7786.0
Date Created : 11/02/2004
Account Type : Checking
OverDraft limit : 4500.0
Account 3 :
Account Number : 887763
Annual Intrest Rate : 1.4
Balance : $ 4887.0
Date Created : 12/12/2012
Account Type : Saving
Balance after withdrawing : $3687.0
Insufficient Balance
Balance after withdrawing : $3687.0
BUILD SUCCESSFUL (total time: 0 seconds)
To achieve the requested changes in the code, you can make the following modifications:
Format decimals up to two decimal points:
In the Account class, modify the toString method to use String.format and specify the desired format for the balance and annual interest rate:
public String toString() {
return String.format("\nAccount Number: %d\nAnnual Interest Rate: %.2f\nBalance: $%.2f\nDate Created: %s",
accountnum, annualintrestrate, balance, datecreated);
}
Get the current date for the "Date Created" field:
In the Account class, you can use the java.util.Date class and its toString method to get the current date and time. Modify the constructor to set the datecreated field using new Date().toString():
Account(int accountnum, double balance, double annualintrestrate) {
this.accountnum = accountnum;
this.balance = balance;
this.annualintrestrate = annualintrestrate;
this.datecreated = new Date().toString();
}
Show the amount deposited and withdrawn in each account:
In the Account class, modify the deposit and withdraw methods to print the amount deposited or withdrawn:
public void deposit(double amount) {
balance += amount;
System.out.println("Amount deposited: $" + amount);
}
public void withdraw(double amount) {
if (balance - amount < 0) {
System.out.println("Insufficient Balance");
} else {
balance -= amount;
System.out.println("Amount withdrawn: $" + amount);
}
}
After making these modifications, you can run the code, and the output will reflect the changes you requested.
Please note that it's recommended to follow Java naming conventions, such as starting class names with an uppercase letter.
Learn more about code here:
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