Formulas change from F to degree C : C = ( F - 32 )/1.8
so we have (77-32)/1.8 = 25 oC
ok done. Thank to me :>
Answer: The answer is C. 298 K
Explanation:
- A cylinder of volume 5.0 x 103 cm3 contains air at a pressure of 8.0 x 105 Pa.
A leak develops so that air gradually escapes from the cylinder until the air in the cylinder
is at atmospheric pressure. The pressure of the atmosphere is 1.0 x 105 Pa.
Calculate the volume of the escaped air, now at atmospheric pressure. Assume that the
temperature stays constant.
Answer:
10
Explanation:
if you put 10 your right
A ball of mass 2.0 kg is travelling at a speed of 12 m/s. It moves towards an object of mass 3.0 kg which is at rest.
The ball hits the object and sticks to it.
Which row gives the total momentum, and the speed of both objects immediately after the collision?
total momentum (kg m/s)
A- 0
B- 0
С- 24
D- 24
AND..
speed (m/s)
A- 4.8
B- 8.0
C- 4.8
D- 8.0
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The velocity for the entire trip is 0.4 m/s as It takes her 500 seconds to make the round trip and 60 kg • m/s2 = (45 kg • v) + (20 kg • 3 m/s).
Path 1 = 400 m В B. A Path 2 = 200 m Path 3 = 300 m. Thus, option C is correct.
What is velocity?A particle's settling velocity known as the rate at which is travels through a still fluid. The specific gravity of the particles, their size, and their shape all have an impact on settling velocity.
A particle in still air will gravitationally settle and reach its terminal velocity fairly quickly. A particle's terminal velocity in a still fluid is referred to as the settling velocity (also known as the "sedimentation velocity").
Understanding variations in the hydraulic regime and interactions between sediment and fluid in the surf zone depends heavily on the particle settling velocity at the foreshore region. In contrast to sedimentation, which is the end product of the settling process, settling is the movement of suspended particles through the liquid.
Therefore, Thus, option C is correct.
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how long does it take saturn to revolve around the sun
Answer: about 29.4 Earth years
Orbit and Rotation
One day on Saturn takes only 10.7 hours (the time it takes for Saturn to rotate or spin around once), and Saturn makes a complete orbit around the Sun (a year in Saturnian time) in about 29.4 Earth years (10,756 Earth days).
Which ONE of the following pairs of physical quantities consists of one scalar and one vector quantity?
A. Distance and speed
B.Speed and acceleration C.Displacement and velocity
D. Velocity and acceleration.
Answer:
speed and acceleration
Explanation:
speed is a scalar quantity
acceleration is a vector quantity
If a train travels 25 miles in 2 hours 15 minutes, what is its average speed in miles per hour? 11. 1 mph 12. 5 mph 10 mph 9. 1 mph.
Answer:
11.1
Explanation:
2 hours 15 mins = 2 1/4 hours
2 1/4 hours = 25 miles
1 hour = 25 ÷ 2 1/4 = 25 ÷ 9/4 = 25 x 4/9 = 11.1 miles
SOMEONEEEE HELP ME PLEASE ILL MARK YOUR BRAINLIST !!!
This was kinda hard thinking it might be that the new force is going to 4 times bigger than the original one.
A person makes a loud sound and hears the echo of this sound 1.2s later .calculate how far the person is from the object causing the echo assume that the speed of sound is 330m/s calculate the distane
Answer:
198m
Explanation:
Distance = speed x time
. d = 330m/s x 1.2s = 396m
This is the distance travelled by the sound from the person to the object and then back to the person. To get the distance from the person to the object, we would have to divide by 2.
. distance = 396 / 2 = 198m
Two conditions must
be met for work to be done, what are they?
The two conditions are:
1) Application of-force on the body.
2) Displacement of the body in the direction of force.
Hope this helps!
A car was driving at a speed of 10 m/s. In 3 seconds, it accelerated to a speed of 50 m/s. Calculate the car's acceleration.
30 m/s2
16.7 m/s2
13.3 m/s2
Answer:
[tex]\boxed {\boxed {\sf 13.3 \ m/s^2}}[/tex]
Explanation:
Acceleration is the rate of change of velocity with respect to time. It is the change in velocity over the change in time, and it is calculated using the following formula.
[tex]a= \frac{ v_f-v_i}{t}[/tex]
The car starts at a speed of 10 meters per second, then it accelerates to a speed of 50 meters per second. It achieves this acceleration in 3 seconds.
[tex]v_f[/tex]= 50 m/s[tex]v_i[/tex]= 10 m/s t= 3 sSubstitute the values into the formula.
[tex]a= \frac{50 \ m/s - 10 \ m/s}{3 \ s}[/tex]
Solve the numerator.
50 m/s -10 m/s= 40 m/s[tex]a= \frac{40 \ m/s}{3 \ s}[/tex]
Divide.
[tex]a= 13.3333333 \ m/s/s[/tex]
[tex]a \approx 13.3 \ m/s^2[/tex]
The car's acceleration is approximately 13.3 meters per second squared.
a force that is at rest or moves in at a constant speed and in a constant direction is called a what force
The question is fishing for "balanced force".
But the description in the question is terrible.
Imagine you have a ball tied to the end of a string. You hold the other end of the string and swing it around. Suppose the string breaks, what direction will the ball travel
As the distance between two objects changes, how does the gravitational force between them change?
Answer:
Explanation:
The gravitational force = G * m1 * m2 / r^2
That means as the distance increases, r get's bigger and m1 and m2 don't change, the force decreases. Read that sentence carefully. In physics, it is very important to know what goes up and goes down means and especially why.
Sound is repeated near hills. Give reason
Explanation:
Sound is repeated near hills due to reverberation. The sound effect is prolonged is an empty room because , in a furnished room, reverberation occurs less than in a room with no furniture.
Answer:
sound that occurs in nature, such as those of animal, trees, people, the wind, the rain, etc. are the natural sounds. it is heard near the hill because of the echo and the reverberation of the sound
a soccer ball is kicked at an angle of 35° and it lands on even ground.
A) What angle will produce the same range?
B) Which angle of the two will produce the highest ball?
C) Which angle of the two will produce the ball that is in the air the longest?
D) What angle in this situation would produce the furthest range?
Hi there!
A)
The angle that will produce the same range is the compliment of 35°.
Thus, kicking the ball at 55° will result in the same range.
We can prove this by using the derived range equation:
[tex]R = \frac{v^2sin2\theta}{g}[/tex]
An angle of 35° yields:
[tex]R = \frac{v^2sin(2*35)}{g} = .939R[/tex]
An angle of 55° yields:
[tex]R = \frac{v^2sin(2*55)}{g} = .939R[/tex]
Both are the same, thus indicating that 55° produces the same range.
B)
The angle of 55° will produce the higher ball because the VERTICAL component of the ball's velocity is greater compared to kicking the ball at 35° degree.
sin(55) > sin(35)
C)
The angle of 55° will result in the ball being in the air the longest because when a ball is in the air (assuming no air resistance), the ball experiences an acceleration due to gravity of -9.8 m/s², causing the vertical velocity to decrease until it eventually reaches 0 m/s at the top of its path. A greater initial vertical velocity means that it will take longer for the ball to fall.
We can prove this using:
vf = vi + at
0 = vy - 9.8t
vy/9.8 = t
Greater vy (vertical component of velocity) ⇒ greater time taken.
D)
The angle that would result in the furthest range is 45°.
We can prove this using calculus. Recall the above range equation:
[tex]R = \frac{v^2sin2\theta}{g}[/tex]
We can take the derivative and use the first-derivative test to find its critical point:
[tex]\frac{dR}{d\theta} = \frac{v^22cos2\theta}{g} = 0[/tex]
Evaluate:
[tex]v^22cos2\theta = 0 \\\\cos2\theta = 0 \\\\2\theta = 90^o\\\\\boxed{\theta = 45^o}[/tex]
A. The angle that will produce the same range as a 35° kick is 53°.
B. The angle that produces the highest ball is 45°.
C. The angle that produces the ball that is in the air the longest is 45°.
D. There is no single angle that will produce the furthest range for all initial velocities and accelerations due to gravity.
A. The range of a projectile is the horizontal distance it travels before it hits the ground. The range of a projectile is determined by the initial velocity, the angle of projection, and the acceleration due to gravity.
For a given initial velocity, the range of a projectile is maximized when the angle of projection is 45°. However, if the ground is not level, the range of a projectile can be maximized at other angles.
In the case of a soccer ball kicked at an angle of 35°, the range will be maximized at an angle of 53°. This is because the range of a projectile is maximized when the vertical component of the initial velocity is equal to the horizontal component of the initial velocity.
The angle of 53° is the angle that produces a vertical component of the initial velocity that is equal to the horizontal component of the initial velocity when the ball is kicked at an angle of 35°.
Therefore, the angle that will produce the same range as a 35° kick is 53°.
B. The angle that produces the highest ball is 45°.
C. The angle that produces the ball that is in the air the longest is 45°.
D. The angle that produces the furthest range depends on the initial velocity and the acceleration due to gravity. There is no single angle that will produce the furthest range for all initial velocities and accelerations due to gravity.
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How much work must be done to stop a 925-kg car traveling at 95 km/h?
The amount of work done to stop the car is equal to 322,099.85 Joules.
Given the following data:
Mass = 925 kilogramsVelocity = 95 km/hConversion:
Velocity = 95 km/h = [tex]\frac{95 \times 1000}{60 \times 60} = 26.39 \;m/s^2[/tex]
To determine the amount of work done to stop the car, we would apply the work-energy theorem:
Note: The amount of work done must balance the kinetic energy possessed by the car due to its motion.
From the work-energy theorem, we have:
[tex]Work\done = \Delta K.E\\\\Work\done = \frac{1}{2} MV^2[/tex]
Substituting the given parameters into the formula, we have;
[tex]Work\;done = \frac{1}{2} \times 925 \times (26.39)^2\\\\Work\;done =462.5 \times 696.4321[/tex]
Work done = 322,099.85 Joules
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one end of a light inextensible string is attached to a tool box of mass 2.5 kg which is lying on a horizontal table. The string passing over a smooth pulley and is tied at the other end to a bag of mass 1.4kg as shown in the diagram
a. If the toolbox on the point of sliding, find the value for μ, the coefficient of friction.
b. Supposing the coefficient of friction between the tool boxe and the table is 0.20, calculate the acceleration of the system and the tension in the string gravity as 10 m per second square
Answer:
the answer is A
Explanation:
Wind energy is the example of A) potential energy B)mechanical energy C) Kinetic energy
Answer:
Kinetic Energy
Explanation:
Its on the internet
hannah drove 360 mi in 5.2 hours. What was her average speed?
When you mix pigments together, why does the resulting color always look darker?
Answer:
because you are not only mixing the colors u are also mix the colors in side the colors for example if u take pink red and white and mix it with green blue and yellow it will make it darling because if the inside colors
change 176°F to the Celsius and Kelvin scales. pura batana kese hua fir answer dena plzz
Formulas change from F to degree C : C = (F – 32) / 1.8
so we have (176-32) /1.8= 80 oC
Formulas change from F to degree K : K = 5 / 9 x (F – 32) + 273.15
so we have 5/9 x (176-32) + 273.15 = 353 oK
ok done. Thank to me :>
What are nucleic acids, and what are their function and structure? Give an example
A helicopter travelling at a velocity of 15 m/s [W] accelerates uniformly at a rate of 7.0 m/s2 [E] for 4.0 s. What is the helicopter’s final velocity?
If we take West to be the negative direction, then the initial velocity is -15 m/s and the acceleration (which points East) is +7.0 m/s².
After t = 4.0 s, the helicopter's velocity is
-15 m/s + (7.0 m/s²) (4.0 s) = +13 m/s
or 13 m/s [E].
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What are the main pieces of evidence we use to differentiate a black hole binary from a neutron star binary
Answer:
Black hole accretion disk emit in the X-rays but neutron star disks are cooler
Hope this Helps
What is the total amount of potential and kinetic energy in a system? *
1 point
A: Electrical energy
B: Heat energy
C: Mechanical energy
D: Nuclear energy
Answer:
C. Mechanical Energy
Explanation:
The total amount of mechanical energy is merely the sum of the potential energy and the kinetic energy.
newtons 2nd law of the law of…
1. If the mass of an object is measured in kg and the velocity is measured in m/s, what is the unit for momentum?
The unit for momentum is equal to Kgm/s.
Given the following data:
Unit of mass = Kilogram (kg).Unit of velocity = meter per seconds (m/s).To determine the unit for momentum:
What is momentum?In Science, momentum can be defined as a multiplication of the mass of an object and its velocity.
Mathematically, momentum is giving by this formula;
[tex]Momentum = mass \times velocity[/tex]
Substituting the given parameters into the formula, we have;
[tex]Momentum = kg \times m/s\\\\[/tex]
Momentum = Kgm/s.
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What nation recently blew up one of its own satellites as part of a missile test, triggering a warning from the u.s. over a potentially dangerous debris field?
Answer:
Russia
Explanation:
my answer was deleted for no reason. apparently i was violating community guidelines when i wasnt. anyways, the answer is russia...
10. Which of the following will happen to the respiratory-associated muscles if you were to blow up a balloon?
A. Diaphragm contracts, Internal intercostal would relax
B. Diaphragm would contract, external intercostal would relax
C. Internal intercostal and abdominal muscles would contract
D. External intercostal would contract and diaphragm would relax
Answer:
C
for sure
go for it
..............
If the momentum of the NASA space shuttle as it leaves the atmosphere is 3.75 x 10^8 kg ·m/s and its mass is 75000 kg, what is its speed?
Hi there!
We know that:
Momentum (p) = mass (kg) × velocity (m/s)
Or:
P = mv
We can rearrange the equation to solve for speed:
P/m = v
Plug in the given values:
(3.75 × 10⁸)/75000 = 5000 m/s
Block 1, of mass m1, moves across a frictionless surface with speed ui. It collides elastically with block 2, of mass m2, which is at rest (vi=0). (Figure 1)After the collision, block 1 moves with speed uf, while block 2 moves with speed vf. Assume that m1>m2, so that after the collision, the two objects move off in the direction of the first object before the collision. What is the final speed vf of block 2?
The conservation of the momentum allows to find the velocity of the second body after the elastic collision is:
[tex]v_f = \frac{2u_o}{1- \frac{m_2}{m_1} }[/tex]
the momentum is defined by the product of the mass and the velocity of the body.
p = mv
The bold letters indicate vectors, p is the moment, m the mass and v the velocity of the body.
If the system is isolated, the forces during the collision are internal and the it is conserved. Let's find the momentum is two instants.
Initial instant. Before crash.
p₀ = m₁ u₀ + 0
Final moment. After crash.
[tex]p_f = m_1 u_f + m_2 v_f[/tex]
The momentum is preserved.
p₀ = [tex]p_f[/tex]
[tex]m_1 u_o = m_1 u_f + m_2 v_f[/tex]
Since the collision is elastic, the kinetic energy is conserved.
K₀ = [tex]K_f[/tex]
½ m₁ u₀² = ½ m₁ [tex]u_f^2[/tex] + ½ m₂ [tex]v_f^2[/tex]
Let's write our system of equations.
[tex]m_1 u_o = m_1 u_f + m_2 v_f \\m_1 u_o^2 = m_1 u_f^2 + m_2 v_f^2[/tex]
Let's solve
[tex]u_f = u_o - \frac{m_2}{m_2} \ v_f \\u_f^2 = u_o^2 - \frac{m_2}{m_1} \ v_f^2[/tex]
[tex]( u_o - \frac{m_2}{m_1} v_f)^2 = u_o - \frac{m_2}{m_1} \ v_f^2 \\u_o^2 - 2 \frac{m_2}{m_1} \ u_o v_f + (\frac{m_2}{m_1} )^2 v_f^2 = u_o^2 - \frac{m_2 }{m_1} \ v_f^2[/tex]
[tex]2 \frac{m_2}{m_1} \ u_o = \frac{m_2}{m_1} v_f \ ( 1 - \frac{m_2}{m_1}) \\v_f = \frac{2u_o}{1-\frac{m_2}{m_1} }[/tex]
In conclusion, using the conservation of momentum, we can find the velocity of the second body after the elastic collision is:
[tex]v_f = \frac{2u_o}{1-\frac{m_2}{m_1} }[/tex]
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