The law of sines is solved and the triangle is given by the following relation
Given data ,
From the law of sines , we get
a / sin A = b / sin B = c / sin C
a)
C = 135° C = 45₁ B = 10°
So , the measure of triangle is
A/ ( 180 - 35 - 10 ) = A / 35
And , a/ ( sin 135/35 ) = sin 35 / a
On simplifying , we get
a = 36.50
Hence , the law of sines is solved
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A sample of an element with a half-life of 8 years has a mass of 10 grams after 100 years. What was the mass of the original sample?
The mass of the original sample was approximately 1592.5 grams.
A sample of an element with a half-life of 8 years has a mass of 10 grams after 100 years. What was the mass of the original sample?The half-life of an element is the time it takes for half of a given sample of that element to decay.
Let's assume that the original mass of the sample was x grams.
After the first half-life of 8 years, the mass of the sample would be x/2 grams.
After the second half-life (16 years total), the mass would be x/4 grams.
After the third half-life (24 years total), the mass would be x/8 grams.
We can continue this pattern until we get to 100 years (which is 12.5 half-lives):
Mass after 100 years = x/2^12.5
We also know from the problem that the mass after 100 years is 10 grams:
x/2^12.5 = 10
Solving for x:
x = 10 x 2^12.5
x ≈ 1592.5 grams
Therefore, the mass of the original sample was approximately 1592.5 grams.
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HELP!!! A lake currently has a depth of 30 meters. As sediment builds up in the lake, its depth decreases by 2% per year.
This situation represents [exponential growth or exponential decay]
The rate of growth or decay, r, is equal to [. 98 or. 02 or 1. 02]
So the depth of the lake each year is [1. 02 or. 98 or. 02]
times the depth in the previous year.
It will take between [11 and 12 or 9 and 10 or 3 and 4 or 5 and 6]
years for the depth of the lake to reach 26. 7 meters
This situation represents exponential decay because the depth of the lake decreases over time.
Exponential decay is a mathematical term used to describe the process of decreasing over time at a constant rate where the amount decreases by a constant percentage at regular intervals. It is a type of exponential function where the base is less than 1.
In other words, the quantity is decreasing by a fixed percentage at regular intervals.
The rate of decay, r, is equal to 0.98 because the depth decreases by 2% per year.
So the depth of the lake each year is 0.98 times the depth in the previous year. It will take between 5 and 6 years for the depth of the lake to reach 26.7 meters.
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The ages of a and b are in the ratio 8:3.6 years later their ages are ok the ratio 9:4.Find their present ages
Answer:
The present ages of A and B will be 48 and 18 years.
Step-by-step explanation:
Let the coefficient be x.
A's age = 8x
B's age = 3x
Six years hence,
Ages will be 8x+6 and 3x+6.
Now, As per the question,
(8x+6) /(3x+6) = 9/4
32x+24 = 27x+54
5x = 30
x = 6.
The mean number of days with 0. 01 inch or more precipitation per month for Lewiston, Idaho, is about 8. 7. Find the probability that in a given month
(a) There are exactly 9 days with 0. 01 inch or more precipitation.
(b) There are at most 9 days with 0. 01 inch or more of precipitation.
(c) There are more than 9 days with 0. 01 inch or more of precipitation
We will use the Poisson distribution, which is a probability distribution that models the number of events occurring in a fixed interval of time or space, given the average rate of occurrence and assuming that the events are independent and randomly distributed.
For this problem, we will assume that the number of days with 0.01 inch or more precipitation in Lewiston, Idaho, follows a Poisson distribution with parameter λ = 8.7.
(a) To find the probability that there are exactly 9 days with 0.01 inch or more precipitation, we can use the Poisson probability mass function:
P(X = k) = e^(-λ) * λ^k / k!
where X is the random variable representing the number of days with 0.01 inch or more precipitation, λ is the parameter of the Poisson distribution, and k is the number of events we are interested in.
Plugging in the values, we get:
P(X = 9) = e^(-8.7) * 8.7^9 / 9! ≈ 0.151
Therefore, the probability that there are exactly 9 days with 0.01 inch or more precipitation is approximately 0.151.
(b) To find the probability that there are at most 9 days with 0.01 inch or more precipitation, we can use the cumulative distribution function of the Poisson distribution:
P(X ≤ k) = ∑i=0^k e^(-λ) * λ^i / i!
Plugging in the values, we get:
P(X ≤ 9) = ∑i=0^9 e^(-8.7) * 8.7^i / i! ≈ 0.503
Therefore, the probability that there are at most 9 days with 0.01 inch or more precipitation is approximately 0.503.
(c) To find the probability that there are more than 9 days with 0.01 inch or more precipitation, we can subtract the probability of having 9 or fewer days from 1:
P(X > 9) = 1 - P(X ≤ 9) ≈ 0.497
Therefore, the probability that there are more than 9 days with 0.01 inch or more precipitation is approximately 0.497.
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The sugar company will chose from two companies to transport it’s sugar to market. the first company charges $5143 to rent trucks plus an additional fee of $200.75 for each ton of sugar. the second company charges $5500 to rent plus an additional fee of $175.25 for each ton of sugara. for what amount of sugar do the two companies charge the same?b. what is the cost when the two companies charge the same?
a. The two companies charge the same for 14 tons of sugar.
b. The cost when the two companies charge the same is $7953.50.
a. Let's represent the amount of sugar as x, and the total cost as C. Then we can set up the following equations for each company:
Company 1: C = 5143 + 200.75x
Company 2: C = 5500 + 175.25x
To find the amount of sugar for which the two companies charge the same, we can set the two equations equal to each other and solve for x:
5143 + 200.75x = 5500 + 175.25x
25.5x = 357
x = 14
So the two companies charge the same for 14 tons of sugar.
b. To find the cost when the two companies charge the same, we can plug in x = 14 into either equation. Let's use Company 1's equation:
C = 5143 + 200.75x
C = 5143 + 200.75(14)
C = 5143 + 2810.50
C = 7953.50
Therefore, the cost when the two companies charge the same is $7953.50.
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Grace and Kelly can create math problems for a particular course in 20 hours. Alone, Grace can do write all of the problems 4 hours faster than Kelly could if she were to work alone. How long would it take each person to write the problems if they worked alone?
From the word problem given, it will take Grace 0.05 hours and Kelly 4.05 to complete the task
How long will it take for each person to write the problem if they worked alone?To solve this problem, we need to write an equation for the word problem.
Let x = time it takes for Kelly
let y = time it takes for Grace
From the problem;
y = x - 4 ...eq(i)
Since they can complete the work in 20 hours;
1/x + 1/y = 20 ...eq(ii)
Solving for both equations
From equ(ii)
1/x + 1/(x - 4) = 20
Solving for x;
x = 4.05 or x = 0.049
Put the value in and solve for y
y = x - 4
y = 4.05 - 4 = 0.05 or y = 0.0049 - 4 = insignificant
The value of y = 0.5 hours
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Jerry has the following assets a house with equity of $15. 0. A car with equity of $2. 500, and household goods worth $6,000 (no single item over $400). He also has tools worth $5. 800 that he needs for his business. Using the federal list, the total amount of exemptions that Jerry would be allowed is $____. 0. Using the state list, the total amount of exemptions that jerry would be allowed is $____. 0.
00. Using the state list the total amount of exemptions that Jerry would be allowed is s
. 0. The state
list will be more favorable for him
tially Connect
Under the federal list, the total amount of exemptions that Jerry would be allowed is $27,900.
Under the state list, the total amount of exemptions that Jerry would be allowed is $37,500.
What are the exemptions?Under the federal list, Jerry's exemptions can only be be:
Equity in home: $15,000
Motor vehicle: $2,400
Household goods: $8,000
Tools (for debtor’s trade): $1,500
Total exemptions = $27,900
Under the state list, Jerry's exemptions can only be be
Equity in home: $25,000
Motor vehicle: $1,500
Household goods: $6,000
Tools: $5,000
Total exemptions = $37,500
Based on the above, the state list can be more favorable for Jerry as it will give him a lot of exemption a higher total value of assets.
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See full question below
Computing Exemptions Under Chapter 7 Bankruptcy
Assume the current federal bankruptcy exemptions are listed at the left, and the state exemptions are
listed at the right. The debtor may use the exemption table that best benefits him or her. For the two
circumstances shown below, compute the exemption amounts and decide which will be better for the
debtor—the federal list or the state list.
LIST A. FEDERAL EXEMPTIONS
Equity in home .......................................$15,000
Motor vehicle .............................................2,400
Household goods .......................................8,000
($400 limit for a single item)
Jewelry .......................................................1,000
Other property ..............................................800
Tools (for debtor’s trade) ...........................1,500
LIST B. STATE EXEMPTIONS
Equity in home ....................................... $25,000
Motor vehicle ............................................. 1,500
Household goods ..................................... 10,000
($1,000 limit for a single item)
Jewelry .......................................................... 500
Other property .............................................. 100
Tools ........................................................... 5,000
1. Jerry has the following assets: a house with equity of $15,000, a car with equity of $2,500, and household goods worth $6,000 (no single item over $400). He also has tools worth $5,800 that he needs for his business. What is the total amount of exemptions Jerry would be allowed using the federal list? The state list? Which list will be more favorable for him? SHOW YOUR WORK!
A theater ticket costs £63 plus a booking fee of 3% what is the total price for the ticket
Answer:
The cost of Ticket = £63Booking Fee = 3% = 63*(3/100) = 1.89 = £ 1.89The total price of the ticket = £63 + £1.89 = £64.89. Therefore, the total price of the ticket is £64.89.
Estimate the solution to the system of equations. You can use the interactive graph below to find the solution.
7x−y=7
x+2y=6
Choose 1 answer:
(Choice A): x=1 1/3, y=1 1/3
(Choice B): x=2 1/3, y=2 1/3
(Choice C):x=2 1/3, y=1 1/3
(Choice D):x=1 1/3, y=2 1/3
Answer:
the answer is D
Step-by-step explanation:
Answer:
C. x = 2 1/3, y = 1 1/3.
Step-by-step explanation:
To solve this question, we need to plot the two equations on the graph and see where they cross. The graph below shows the two lines in different colors:
We can see that the point of intersection is somewhere between (1, 2) and (2, 1). Looking at the given options, we can see that only one of them is in that range. That is option C. x = 2 1/3, y = 1 1/3. Therefore, the answer is C. x = 2 1/3, y = 1 1/3.Which expression is equivalent to 24+30?
A. 6(4+5)
B. 6(4+6)
C. 8(3+4)
D. 8(3+12)
Please i need an answer to this
Answer:
A
Step-by-step explanation:
6x4 = 24
6x5 = 30
24+30
:)
Answer:
A.) 6(4+5)
Step-by-step explanation:
*Solve the parenthesis first: 4+5 = 9
*Next, multiply 6×9= 54
Write a numerical expression using at least three operations a parenthesis an exponent that when solved has a solution of 23
Therefore, when you solve this expression (6 + 5) x 2^2 - 4 , the solution is 23.
Here's an example of a numerical expression using at least three operations, a parenthesis, and an exponent that when solved has a solution of 23:
(6 + 5) x 2^2 - 4 = 23
Explanation:
- Parenthesis: (6 + 5) = 11
- Exponent: 2^2 = 4
- Multiplication: 11 x 4 = 44
- Subtraction: 44 - 4 = 40
- Solution: 40 divided by 2 = 20, then 20 plus 3 = 23
Therefore, when you solve this expression, the solution is 23.
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Rhombus abcd has vertices (1, 10), (-4, 0), (7, 2), (12, 12), respectively. part 1 use the distance formula to find the lengths of the diagonals. part 2 use the lengths of the diagonals to calculate the area of the rhombus. part 3 one of the similar characteristics in a square and rhombus is that they both have four equal sides. the formula for the area of a square uses the side lengths to compute the area while the formula for the area of a rhombus uses the lengths of the diagonals to compute the area. are area formulas for a square and rhombus interchangeable? in complete sentences, explain why or why not you think that the formulas are interchangeable. create your own example using a square with side lengths and a rhombus with side lengths to prove your explanation.
The area of the square is 16 square units.
The area of the rhombus is 24 square units.
Part 1: Using the distance formula, we can find the lengths of the diagonals:
Diagonal AC = √[tex][(7-1)^2 + (2-10)^2[/tex]] = √(36 + 64) = √100 = 10
Diagonal BD = √[[tex](12-(-4))^2 + (12-0)^2[/tex]] = √(256 + 144) = √400 = 20
Part 2: The area of a rhombus can be calculated using the formula: Area = (diagonal 1 x diagonal 2)/2.
So, for this rhombus, the area = (10 x 20)/2 = 100 square units.
Part 3: The area formulas for a square and rhombus are not interchangeable because they have different ways of computing their areas. A square has all four sides equal in length, while a rhombus has opposite sides equal in length. The diagonals of a square bisect each other at right angles, and each diagonal divides the square into two congruent triangles, so the area of a square is simply side length squared (Area =[tex]s^2[/tex]). However, the diagonals of a rhombus bisect each other at right angles, but they do not necessarily divide the rhombus into congruent triangles. Therefore, the area of a rhombus is calculated using the lengths of the diagonals (Area = (diagonal 1 x diagonal 2)/2).
For example, let's consider a square with side length 4 units and a rhombus with diagonals 6 units and 8 units.
The area of the square = [tex]4^2 = 16[/tex]square units.
The area of the rhombus = (6 x 8)/2 = 24 square units.
As we can see, the formulas are not interchangeable.
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Select the equation that most accurately depicts the word problem. The perimeter of a rectangle is 68 inches. The perimeter equals twice the length of L inches, plus twice the width of 9 inches. 68 = 9(L + 2) 68 = 2L + 2(9) 68 = 2(L - 9) 68 = 9L + 2 68 = 2/L + 2/9 68 = L/2 + 2(9)
The equation which most accurately represents the word problem, is (b) 68 = 2L + 2(9).
The word problem states that the perimeter of a rectangle is 68 inches, and the perimeter equals twice the length (L) plus twice the width (9). We can represent this relationship by using the equation as :
We know that, the perimeter of rectangle is : 2(length + width),
Substituting the value,
We get,
⇒ 68 = 2(L + 9);
⇒ 68 = 2L + 2(9); and this statement is represented by Option(b).
Therefore, the correct equation is (b) 68 = 2L + 2(9).
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The given question is incomplete, the complete question is
Select the equation that most accurately depicts the word problem.
"The perimeter of a rectangle is 68 inches. The perimeter equals twice the length of L inches, plus twice the width of 9 inches".
(a) 68 = 9(L + 2)
(b) 68 = 2L + 2(9)
(c) 68 = 2(L - 9)
(d) 68 = 9L + 2
(e) 68 = 2/L + 2/9
(f) 68 = L/2 + 2(9)
Let f(a) = 15a squared + 40a - 30 and a(b) = 3b -5 find f(b), then find the value of f when b = -3
In mathematics, an expression is a combination of numbers, variables, and/or operators that represents a mathematical phrase or equation. Therefore, when b = -3, f(b) = -15.
An expression can contain constants, variables, functions, and/or mathematical operators such as addition, subtraction, multiplication, division, exponentiation, and logarithms.
To find f(b), we need to substitute b for a in the expression for f(a):
f(b) = 15b^2 + 40b - 30
To find the value of f when b = -3, we substitute -3 for b in the expression above:
f(-3) = 15(-3)^2 + 40(-3) - 30
f(-3) = 135 - 120 - 30
f(-3) = -15
Therefore, when b = -3, f(b) = -15.
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Exercise 11. 3. 1: Applying the pigeonhole principle - heights and times. About Apply the pigeonhole principle to answer the following questions. If the pigeonhole principle can not be applied, give a specific counterexample. (a) A team of three high jumpers all have a personal record that is at least 6 feet and less than 7 feet. Is it necessarily true that two of the team members must have personal records that are within four inches of each other
To apply the pigeonhole principle, we need to determine the number of pigeonholes and the number of pigeons. The pigeonhole principle cannot be applied to this question.
In this case, the" holes" are the high minidresses and the" lockers" are the ranges of particular records. Let's assume that the range of particular records is from 6 bases( 72 elevation) to 7 bases( 84 elevation). The difference between the upper and lower bounds of the range is
84- 72 = 12 elevation.
We can divide this range into five subintervals of length2.4 elevation( 72,74.4),(74.4,76.8),(76.8,79.2),(79.2,81.6), and(81.6, 84).
Since there are only five subintervals, but we've three high minidresses, it isn't inescapably true that two of the platoon members must have particular records that are within four elevation of each other. For illustration, if the three high minidresses have particular records of 6 bases 3 elevation( 75 elevation), 6 bases 7 elevation( 79 elevation), and 7 bases( 84 elevation), also none of them have particular records within four elevation of each other.
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What technique is happening to this object?
Step-by-step explanation:
Looks as though it has been cropped.....picture is only a PART of the original...it has been 'cut off' or 'cropped' on both sides .
consider the multiple regression model with two regressors x1 and x2, where both variables are determinants of the dependent variable. you first regress y on x1 only and find no relationship. however when regressing y on x1 and x2, the slope coefficient changes by a large amount. this suggests that your first regression suffers from:
When a multiple regression model created incorrectly then leaves out one and more than one important factors are omitted.
Multiple regression is a statistical way that can be used to analyze the relationship between a single dependent variable and several independent variables. Equation is written as y =
We have regressors x₁ and x₂ where both variables are determinants of the dependent variable. you first regressor y on x₁ only and find no relationship. however when regressing y on x₁ and x₂.
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Complete question:
consider the multiple regression model with two regressors x1 and x2, where both variables are determinants of the dependent variable. you first regress y on x1 only and find no relationship. however when regressing y on x1 and x2, the slope coefficient changes by a large amount. this suggests that your first regression suffers from:
to find out whether a new serum will arrest leukemia, 9 mice, all with an advanced stage of the disease, are selected. five mice receive the treatment and 4 do not. survival times, in years, from the time the experiment commenced are as follows: treatment 2.1 5.3 1.4 4.6 0.9 no treatment 1.9 0.5 2.8 3.1 at the 0.05 level of significance, can the serum be said to be effective? assume the two populations to be normally distributed with equal variances.
The serum be said to be effective can't be concluded, since the test statistic is less than the critical value, we fail to reject the null hypothesis.
Let [tex]n_A[/tex] denotes the number of mice which receiving treatment. Therefore,
[tex]n_A[/tex] = 5,
Let [tex]n_B[/tex] denotes the number of mice which do not receive treatment. Therefore, [tex]n_B[/tex] = 4
Survival times for the mice receiving the treatment are: 2.1; 5.3; 1.4; 4.6; 0.9
Survival times for the mice not receiving the treatment are: 1.9; 0.5; 2.8; 3.1
Let [tex]x_A[/tex] be the mean of survival time for the mice receiving the treatment and [tex]x_B[/tex] be the mean of survival time for the mice not receiving the treatment.
We have: [tex]x_A[/tex] = 2.86
[tex]x_B[/tex] = 2.075
Standard deviation be:
[tex]S_A=\sqrt{\frac{\sum (x_a-x_A)^2}{n_A-1} }[/tex]
[tex]=\sqrt{\frac{[(2.1-2.86)^2+(5.3-2.86)^2+(1.4-2.86)^2+(4.6-2.86)^2+(0.9-2.86)^2]}{4} }[/tex]
= 1.971
[tex]S_B=\sqrt{\frac{\sum (x_b-x_B)^2}{n_B-1} }[/tex]
[tex]=\sqrt{\frac{[(1.9-2.08)^2+(0.5-2.08)^2+(2.8-2.08)^2+(3.1-2.08)^2]}{3} }[/tex]
= 1.167
[tex]\mu_A[/tex] and [tex]\mu_B[/tex] are population means for the groups receiving the treatment and not receiving the treatment respectively.
Level of significance is α = 0.05
If P-value is less then 0.05, we will reject [tex]H_o[/tex]
The test statistic is,
[tex]t=\frac{(x_A-x_B)-(\mu_A-\mu_B)}{s_p\sqrt{\frac{1}{n1} +\frac{1}{n2} } }[/tex]
[tex]=\frac{2.86-2.07)-(0)}{1.674388\sqrt{\frac{1}{5} +\frac{1}4} } }[/tex]
= 0.79/1.123
t = 0.70
Degrees of freedom is,
[tex]d_f=n_A+n_B-2[/tex]
= 5 + 4 - 2
= 7.
According to the value in the table, the test's critical value is 1.895.
We are unable to reject the null hypothesis since the test statistic is less than the threshold value.
We thus cannot draw the conclusion that the serum is working.
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Find the most general antiderivative of the function. (Check your answer by differentiation. Use C for the constant of the antiderivative.)
g(v) = 5 cos (v) - 8/√(1-v^2)
g(v) = ____
The most general antiderivative of the function g(v) = 5 cos(v) - 8/√(1-v^2) is 5 sin(v) + 8 arcsin(v) + C, where C is the constant of the antiderivative.
To find the antiderivative of the given function g(v), we can use the basic antiderivative rules. The antiderivative of 5 cos(v) is 5 sin(v), as the derivative of sin(v) is cos(v) and we only need to reverse the process.
Similarly, the antiderivative of -8/√(1-v^2) can be found using the inverse trigonometric function arcsin(v), as its derivative is -1/√(1-v^2). However, we need to include a constant of integration, denoted by C, as the antiderivative is not unique.
So the most general antiderivative of g(v) is 5 sin(v) + 8 arcsin(v) + C, where C represents the constant of the antiderivative. To check the correctness of the answer, we can differentiate it and verify if it gives us the original function g(v) as the result.
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As a contestant on a televised game show, lucy gets to spin the big prize wheel, which has a radius of 2 yards. what is the prize wheel's area?use 3.14 for .
The prize wheel's area is approximately 12.56 square yards.
The area of a circle can be calculated using the formula A = πr², where A represents the area, r represents the radius, and π is approximately 3.14. In Lucy's case, the big prize wheel has a radius of 2 yards.
To find the area of the prize wheel, we can plug the radius value into the formula:
A = π(2 yards)²
Squaring the radius (2 yards) gives us:
A = π(4 square yards)
Now, we can multiply by the given value of π (3.14):
A = 3.14 × 4 square yards
Finally, multiplying these values together, we get:
A = 12.56 square yards
Therefore, the area of the prize wheel is approximately 12.56 square yards. This calculation helps us understand the size of the prize wheel, which can be useful for various purposes such as determining the space required for the game show set or designing the prize sections on the wheel.
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secθ in simplest radical form.
The value of secθ in simplest radical form is:
[tex]sec\theta = -\frac{\sqrt{61} }{5}[/tex]
If the point is given on the terminal side of an angle, then:
Calculate the distance between the point given and the origin:
[tex]r = \sqrt{x^{2} +y^2}[/tex]
Here, x = -5 and y = -6
The secant can be found by the following trigonometric relation:
[tex]sec\theta = \frac{1}{cos\theta}[/tex]
[tex]sec\theta = \frac{1}{\frac{x}{r} }\\ \\sec\theta = \frac{r}{x}\\ \\sec\theta = \frac{\sqrt{x^{2} +y^2} }{x}\\ \\sec\theta =\frac{\sqrt{(-5)^2+(-6)^2} }{-5}\\ \\sec\theta = -\frac{\sqrt{61} }{5}[/tex]
The secant function ‘or’ Sec Theta is one of the trigonometric functions apart from sine, cosine, tangent, cosecant, and cotangent. In right-angled trigonometry, the secant function is defined as the ratio of the hypotenuse and adjacent side.
Now , the secθ functions:
[tex]sec\theta = -\frac{\sqrt{61} }{5}[/tex]
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The given question is incomplete, complete question is:
If θ is an angle in standard position and its terminal side passes through the point (-5,-6), find the exact value of secθ in simplest radical form.
Question 11(Multiple Choice Worth 2 points) (Line of Fit MC) A scatter plot is shown on the coordinate plane. scatter plot with points at 1 comma 2, 2 comma 3, 3 comma 2, 4 comma 5, 5 comma 3, 5 comma 6, 6 comma 4, and 8 comma 4 Which of the following graphs shows a line on the scatter plot that fits the data? scatter plot with points at 1 comma 2, 2 comma 3, 3 comma 2, 4 comma 5, 5 comma 3, 5 comma 6, 6 comma 4, and 8 comma 4, with a line passing through the coordinates 1 comma 2 and 2 comma 3 scatter plot with points at 1 comma 2, 2 comma 3, 3 comma 2, 4 comma 5, 5 comma 3, 5 comma 6, 6 comma 4, and 8 comma 4, with a line passing through the coordinates 1 comma 2 and 8 comma 4 scatter plot with points at 1 comma 2, 2 comma 3, 3 comma 2, 4 comma 5, 5 comma 3, 5 comma 6, 6 comma 4, and 8 comma 4, with a line passing close through the coordinates at about 2 comma 3 and 8 comma 5 scatter plot with points at 1 comma 2, 2 comma 3, 3 comma 2, 4 comma 5, 5 comma 3, 5 comma 6, 6 comma 4, and 8 comma 4, with a line passing through the coordinates 1 comma 3 and a half and 2 comma 3 and a half
A graph that shows a line on the scatter plot that fits the data include the following: B. scatter plot with points at 1 comma 2, 2 comma 3, 3 comma 2, 4 comma 5, 5 comma 3, 5 comma 6, 6 comma 4, and 8 comma 4, with a line passing through the coordinates 1 comma 2 and 8 comma 4.
What are the characteristics of a line of best fit?In Mathematics and Geometry, there are different characteristics that are used for determining the line of best fit on a scatter plot and these include the following:
The line should be very close to the data points as much as possible.The number of data points that are above the line should be equal to the number of data points that are below the line.By critically observing the scatter plot using the aforementioned characteristics, we can reasonably and logically deduce that line B represents the line of best fit because the data points are in a linear pattern.
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Inayah claims that the pool is draining at a rate of 1. 36% per hour
The pool is draining at a rate of 1.36% per hour according to Inayah's claim.
What is the claimed rate at which the pool is draining?According to Inayah's claim, the pool is experiencing a draining at a rate of 1.36% per hour. This means that for every hour that passes, the pool's water level decreases by 1.36% of its total volume.
Understanding the rate at which a pool is draining is essential for monitoring and managing water levels. If the rate of drainage is accurate, it can help estimate how long it would take for the pool to reach a certain level or completely drain. Additionally, it aids in determining the necessary actions to maintain the pool's water balance and prevent potential issues such as overflow or inadequate water supply.
It is crucial to verify the accuracy of the claim by monitoring the pool's water level over a specific period. This can be done by measuring the change in water volume or using other reliable methods to ensure the drainage rate aligns with the claimed percentage.
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HELPPPPPPPPPPP HELPPPP PLEASEEE ITS MATHHHH
sorry, I am really sorry I really need the points. Just by seeing it I think in the 3 one am not sure but don't trust me because I just saw it and thought it was 3........
Your cousin is bulding a sandbox for his daughter. How much sand will he need to fill the box? Explain. How much paint will he need to paint all six surfaces of the sandbox? Explain.
The amount of paint that he will need to paint all six surfaces of the sandbox is: 68 square feet
How to find the volume of the prism?Since the image is a rectangular prism
The volume of the box can be obtained by using the formula:
Volume = l * b * h
The box has a dimension of 1ft x 4ft x 6ft
The volume of the box = 1 x 4 x 6 = 24 cubic feet
Therefore, the volume of sand needed to fill the box will be = 24 cubic feet of sand
The surface area of the box can be obtained using the formula:
2(lb + lh + bh)
= 2(1*4 + 1*6 + 4*6)
=2(4 + 6 + 24)
=2 (34)
= 68 square feet
Therefore a total surface area of 68 square feet needs to be painted
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Complete question is:
Your cousin is building a Sandbox for his daughter how much sand will he need to fill the Box? Explain. How much paint will he need to paint all six surface of the sandbox? Explain. 1ft 4ft 6ft not answer choices
Mario had 40 shares of stock that each lost $75 during the half of the year. He also had 24 shares of a different stock that gained $50 each. What was his net change during this time period on these stocks?
The net change in the stock is $1800
How to calculate the net change ?Mario has 40 shares of stick that each lost $75 during half of the year
He also had 24 shares of a different stock that gained $50
The net change can be calculated as follows
-40 × 75
= -3000
= 24 × 50
= 1200
Net change
-3000 + 1200
= -1800
Hence the net change in the stocks is $1800
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A large corporation with monopolistic control in the marketplace has its average daily costs, in dollars, given by 900 + 100x + x2 C = X = 180,000 – 50x dollars. Find the quantity that gives maximum profit
The quantity that gives maximum profit is 1,750 units.
To find the quantity that gives maximum profit, we first need to determine the profit function.
Profit = Total Revenue - Total Cost
Total Revenue is given by the price (p) times the quantity (q):
TR = pq
Since the corporation has monopolistic control, it can set the price to maximize profit. We can use the demand function
to find the price that will maximize profit:
Q = 180,000 - 50p
Solving for p, we get:
p = 3,600 - 0.02Q
Now we can substitute this into the profit equation:
Profit =[tex](3,600 - 0.02Q)Q - (900 + 100Q + Q^2)[/tex]
Simplifying:
Profit = [tex]-Q^2 + 3,500Q - 900[/tex]
To find the quantity that gives maximum profit, we can take the derivative of the profit function with respect to Q and
set it equal to zero:
[tex]d/dQ (-Q^2 + 3,500Q - 900) = 0[/tex]
-2Q + 3,500 = 0
Q = 1,750
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The second of three numbers is 8 more than the first,
and the third number is 3 less than 3 times the first.
If the third number is 15 more than the second, find
the three numbers.
1st.
2nd
3rd
Which of the following is the correct ratio for the image:
Responses
Sin 25 = 8 over b
Sin 25 = b over 8
Tan 25 = 8 over b
Tan 25 = b over 8
Carl takes out a loan which accrues interest at a flat rate of 1.96% per quarter.
what is the equivalent yearly simple interest rate?
Carl will be charged 7.84% of the initial loan amount as interest.
When taking out a loan, it's important to understand the interest rate and how it will affect the total amount you will owe. In this case, Carl's loan accrues interest at a flat rate of 1.96% per quarter. This means that every quarter, Carl will be charged 1.96% of the initial loan amount as interest.
To determine the equivalent yearly simple interest rate, we use the formula: Yearly interest rate = Quarterly interest rate x 4. This formula works because there are four quarters in a year, so we can multiply the quarterly interest rate by four to get the annual interest rate.
In this case, the quarterly interest rate is 1.96%. Multiplying this by four, we get an annual interest rate of 7.84%. This means that over the course of a year, Carl will be charged 7.84% of the initial loan amount as interest.
Understanding the interest rate is important because it can significantly impact the total amount that you will owe on a loan. A higher interest rate means that you will pay more in interest over the life of the loan, which can make the loan more expensive overall.
By calculating the equivalent yearly simple interest rate, Carl can better understand how much he will owe in interest over the course of the loan and make an informed decision about whether or not to take out the loan.
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