What happens when light hits the pigment in photosystem II?

Explanation:

2CO (g) + O2 (g) → 2CO2 (g) ∆H = –566.0 kJ exothermic

2SO2(g) + O2(g) <=> 2SO3(g). Delta H = -198.2 kJ/mol. exothermic

Polar endotherms must save heat, hence they usually have a significant surface area to volume ratio. The capacity to maintain blood is what makes heat conservation unique.

Vasoconstriction keeps it in the centre by decreasing blood flow to the outside (also known as peripheral vasoconstriction). An endotherm is an organism that uses heat produced by its internal biological processes rather than nearly exclusively relying on ambient heat to keep its body at a metabolically advantageous temperature. In thermodynamics, heat is defined as a kind of energy that crosses a thermodynamic system's boundary due to a temperature differential across the barrier. Heat is not present in a thermodynamic system.

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If it forms ions with ammonium in the ratio of (NH4)3X, X could be in Group IV A. Group IVA (14) metals form cations with +4 charge, although tin (Sn) and lead (Pb) can form cations having +2 charge.

A covalent link (a shared pair of electrons) in which both electrons originate from the same atom is known as a coordinate bond (also known as a dative covalent bond). Two atoms sharing a pair of electrons make a covalent connection. Because the electron pair is drawn to both nuclei, the atoms are kept together.

An arrow pointing from the donor to the acceptor, with a positive charge on the donor and a negative charge on the acceptor, is used to symbolize a coordinate bond.

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The given sample of matter has the lowest average kinetic energy is 50g at -55°C and 2.0 atm option - A is correct answer.

The force an object experiences as a result of motion is known as kinetic energy. An object can only accelerate if a force is applied to it. We have to put in the effort to use force. Once the work is done, energy is transferred to the object, which then moves at a new, constant speed.

Kinetic energy, which can be seen in the motion of an object or subatomic particle, is the energy of motion.

The average kinetic energy is the subject of the query. Thus, the only connection is to temperature. Kinetic energy increases with increasing temperature and decreases with decreasing temperature.

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Answer:

The top left one is the answer I believe

Answer:

the one on the bottom right https://www.tenor.co/VV3E.gif

Calcium oxide reacts with water to form calcium hydroxide which is a type of combination reaction. Therefore, the balanced chemical equation is: CaO+H2O→Ca(OH)2+Δ

The symbolic representation of a chemical reaction is a chemical equation. In this, the formulas and symbols for the reactants and products are used to depict them. Since the Middle Ages, quicklime, also known as calcium oxide, has been utilized as an alkaline substance. One of the oldest substances that humans have ever discovered is quicklime. Other names for it include lime or burned lime. Lime, or calcium oxide, is a chemical substance with the formula CaO. When calcium oxide, also referred to as quick lime, and water combine, calcium hydroxide is created (commonly known as slaked lime). This reaction is an example of a combination reaction.

Calcium oxide + Water → Calcium hydroxide

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If 1 gram (g) of glycogen is split into maltose: The total mass of the product would be 2 grams (g).

When 1 gram of glycogen is broken down into maltose, the result is two molecules of maltose, each having a molecular weight of 342.29 g/mol. Therefore, the total mass of the product is equal to 2 x 342.29 g/mol, or 684.58 g/mol, which is equal to 2 grams (g).

This is because each molecule of maltose is composed of two molecules of glucose, which have a mass of 342.29 g/mol each. Therefore, when the 1 gram of glycogen is split into maltose, the total mass of the product is 2 grams (g).

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Answer:

Pf= 190 mmHg

Explanation:

(Pi×Vi)/Ti = (Pf×Vf)/T2

Initial Pressure Pi = 756mmHg,

Initial Volume Vi = 2L,

Initial Temperature Ti = 0°C=273K

Final Pressure Pf = ?,

Final Volume Vf = 2L+ Vi = 4L,

Final Temperature T2= 137K

Pf = (Pi × Vi × T2 )/(Vf × Ti)

Pf = (756 × 2 × 137)/(4 × 273)

Pf = 189.7 mmHg

Pf approx. 190mmHg

The combined gas law states the relationship between temperature, pressure, and volume. The final pressure of the gas is 190 mmHg.

Combined gas law states the relationship between the initial pressure, volume, and temperature to the final and is given as,

[tex]\rm \dfrac{P_{i} \times V_{i}}{T_{i}} = \rm \dfrac{P_{f} \times V_{f}}{T_{f}}[/tex]

Given,

Initial Pressure = 756 mmHg

Initial Volume = 2 L

Initial Temperature = 273 K

Final Volume = 4 L

Final Temperature = 137 K

The final pressure is calculated as:

[tex]\begin{aligned} \rm P_{f} &= \rm \dfrac{P_{i} \times V_{i} \times T_{f}}{V_{f} \times T_{i}}\\\\&= \dfrac{756 \times 2 \times 137}{4 \times 273}\\\\&= 189.7 \;\rm mmHg\end{aligned}[/tex]

Therefore, 190 mmHg is the final pressure.

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moles of HCl are reacting is [tex]135\times10^{-3}[/tex]

In the International System of Units, the mole is used to measure material quantity. The number of a substance's elementary entities that are present in an object or sample depends on the amount of that substance. A solute's molar concentration is used to represent how much of a solute there is per unit volume of a solution or how much of a chemical species there is in a solution.

Magnesium reacts with hydrochloric acid to generate a salt of magnesium chloride and release hydrogen gas.

Mg(s) +HCl(aq) [tex]\rightarrow[/tex] [tex]MgCl_{2}[/tex](aq)+[tex]H_{2}[/tex](g)

molarity =[tex]\frac{moles of solute}{volume of solution \:(l)}[/tex]

molarity of Mg is 3.0M volume of solution is 45ml

now, 3M=[tex]\frac{moles of solute}{45\times 10^{-3} \:(l)}[/tex]

moles of mg = 135 millimoles.

now according to the reaction by using stoichiometry

moles of Mg = moles of HCl

moles of HCl =135 millimoles =[tex]135\times10^{-3}[/tex]

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An alkene is subjected to an oxymercuration demercuration reaction sequence to attain a synthetic aim is the conversion of an alkene into an alcohol.

The oxymercuration reaction involves the addition of a hydroxymercury(II) compound (Hg(OH)2 or Hg(OAc)2) to the alkene in the presence of a strong base, such as sodium hydroxide (NaOH). This results in the formation of an intermediate alkoxymercury(II) compound, which can then be converted into an alcohol through the demercuration step. In the demercuration step, the alkoxymercury(II) compound is treated with a reducing agent, such as sodium borohydride (NaBH4), which reduces the mercury(II) to mercury(0) and converts the alkoxymercury(II) compound into an alcohol. In summary, the oxymercuration-demercuration reaction sequence is a two-step process that converts an alkene into an alcohol by adding a hydroxymercury(II) compound to the alkene in the presence of a base and then reducing the intermediate alkoxymercury(II) compound with a reducing agent.

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Answer:

[A]²

Explanation:

Since the formation is independent of D, D is 0 order.

Since a quadruples when it is doubled it can be written as

2A^X= 4

To find the unknown power we can assume A= 1 to make the math simple. So When a = 2 (Because you doubled it) raised to X power it will equal 4

so the unknown power is 2

Making the rate law

[a]²[b]⁰

or simply just

[A]²

3.4 mole of H₂SO₄ moles of sulfuric acid (H₂SO4) are needed to react completely with 6.8 moles of lithium hydroxide.

How many moles of sulfuric acid (H₂SO4) are needed ?

Based on the reaction’s stoichiometry: 2 LiOH + H2SO4 Li2SO4 + 2 H2O

It is obvious that when 2.0 moles of LiOH react with 1.0 mole of H2SO4, 1.0 mole of Li2SO4 and 2.0 moles of H2O are produced.

Making use of cross multiplication:

1.0 mole of H2SO4 totally interacts with LiOH (2.0 moles)

2.0 mole of H2SO4 is required to totally react with 6.8 mole of LiOH.

The mole of H2SO4 = (1.0 x 6.8) / (2.0) = 3.4 mole of H2SO4.

One mole of H2SO4 has an atomic mass of 98 grams. So 98 grams of H2SO4 comprises one mole of H2SO4 molecule, or seven moles of atoms.

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The phase and temperature changes that will occur if you heat 50.0 g of H2O in its solid state at -8 C until it all vaporizes is that the solid H2O will transition to a liquid state at 0 C and then to a vapor at 100 C.

Vapor is an aerosolized suspension of tiny liquid particles that are released into the air. It is made up of a mixture of water and other chemicals, such as nicotine, propylene glycol, and other flavorings. Vapor is produced when heated liquid, such as e-liquid, is turned into a vapor. This vapor can be inhaled and exhaled in a manner similar to smoking a traditional cigarette, which is why vapor has become an alternative to traditional smoking.

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The orbitals within subshells are filled in the sequence of increasing energy. The filling can choose from the 5s, 4d, as well as 5p sub-shells. Consequently, there are 18 total components in period 5.

There are 18 atoms in the 5th grade of the periodic table, never 32. Reason l=0, 1, 2, and 3 and n=5. The energy of the accessible electron shells 4d, 5s, and 5p grows in the correct sequence: 5s4d5p. and since there are a total of 9 accessible orbitals, 18 electrons could fit.

The fourth period includes 18 elements owing to the 10 extra electrons which the 3d orbitals can hold since the 3d sublevel doesn't really fill before the 4s sublevel.

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The molecule represented below is Butane.

looking at the structure give each point represents a carbon atom, placing a C on each point gives you a total of 4, making it to be butane.See picture attached for a vivid illustration of butane.

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Answer:

Butane

Explanation:

i just took tha test

Elements of group 18 belongs to the family of noble gases with a general electronic configuration ns²np⁶,  where the valence shell is completely filled.

The elements of group 18 are considered to be noble because they have a completely filled valence shell due to which they donot have the tendency to gain, lose or share their valence electrons with other atoms. Thus, they are highly unreactive.

The elements belonging to noble gas family are:  Helium (He), Neon (Ne), Argon(Ar), Krypton(Kr), Xenon(Xe), Radon(Rn).

under conditions of standard pressure and temperature, these elements exists as gases with very low chemical reactivity so they are known as inert gases.

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Answer:

     3S₈  +  28Br₂ => 8S₃Br₇

Explanation:

Start with either sulfur (S) or bromine (Br) and balance ...

    3S₈  +  Br₂ => 8S₃Br₇    or      S₈  +  7/2Br₂ => S₃Br₇

Balance the remaining reactant ...

    3S₈  +  56/2Br₂ => 8S₃Br₇    

Remove fractions by multiplying by the fraction's denominator

    2(3S₈  +  56/2Br₂ => 8S₃Br₇)     =>     6S₈  +  56Br₂ => 16S₃Br₇      

Reduce to smallest whole number ratio => standard equation at STP ...

        3S₈  +  28Br₂ => 8S₃Br₇

Answer:

4. Double replacement

Explanation:

The generic equation shows that two compounds are being swapped, which is an indication of a double substitution reaction.

Correct answer double replacement.

So the correct answer is D) Double replacement.

Students can learn about the impact of both the design and the paper by working with the same layout. Students can learn about causality in design by replicating it and seeing its effects firsthand. The pupils won't get the full benefit of the paper unless they all follow the same format. There is no need for uniformity in airplane design since pupils will not be comparing the performance of different planes.

For the first test, students conduct an experiment to evaluate whether or not different types of paper affect the airplane's range of flight. Therefore, in the first experiment, the distance the paper travels after being thrown is the dependent variable and the type of paper is the independent variable.

The airplane's design is kept constant so that any differences in flight distance can be attributed to variations in the paper used in the experiment.

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Answer:

6 moles

Explanation:

When using a graduated cylinder you must look at Meniscus of the liquid when taking readings.

The surface at the center of the meniscus, not the top of the ring of liquid clinging to the graduated cylinder's wall, must be read in order to read a graduated cylinder correctly. This "center" will be the meniscus's lowest point for the majority of liquids. The center of the meniscus will be the highest point of the liquid for a very small number of liquids, such as mercury. Your line of sight must be level with the meniscus's center of curvature in order to interpret it correctly.

Reading a graded cylinder is a matter of paying close attention to the details once the measurement interval has been established and the meniscus has been assessed. Read the numbered line below while keeping your eyes level with the meniscus's middle and looking straight down.

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Answer:

I do

Explanation:

But i am unable to share my grade because of personal info.

Answer:

11 th

Explanation:

Answer:

• potential for a species to increase in number

• the heritable genetic variation/ which results from mutation in dna

• the size of a population increases

• competiton for resources that are limited in that specific environment.

Explanation:

these are all factors that would affect natural selection although there are many more.

Answer:

8.74kj

Explanation:

There are three steps

Warming up the ice to its melitng point. THe nergy required to melt it completely. The energy requiered to warm up the water to a certain temp.

It can be seen by the three equations written

Answer:

O₂ is the limiting reactant

0.406 moles of ammonia remains after the reaction goes complete.

Explanation:

Balanced reaction is:

4NH₃  + 5O₂  →  4NO  +  6H₂O

Let's determine the moles of each reactant:

12 g . 1mol / 17g = 0.706 moles of ammonia.

12 g . 1mol / 32g = 0.375 moles of oxygen.

4 moles of ammonia react to 5 moles of oxygen

Then, 0.706 moles of ammonia may react to (0.706 . 5) /4 = 0.882 moles

We only have 0.375 moles of oxygen and there are needed 0.882. O₂ is the limiting reactant. Definetely ammonia is in excess.

5 moles of oxygen react to 4 moles of ammonia

Our 0.375 moles may react to (0.375 . 4) / 5 = 0.3 moles

We have 0.706 moles of NH₃ and we only need 0.3

After the reaction goes complete (0.706 - 0.3) = 0.406 moles of ammonia still remains.

Given :

2 Mg + O₂ → 2 MgO

To Find :

How many moles of magnesium oxide are formed if you burn a 2.3 mol sample of magnesium ribbon in the air.

Solution :

From given balanced chemical reaction we can see that 2 mole of Magnesium reacts with 1 mole of O₂ to produce 2 mole of MgO.

Since, there is abundance of oxygen in air.

Therefore, 2.3 moles of magnesium will produced 2.3 moles of magnesium oxide.

The moment of inertia of this molecule about the y-axis is 14ma^2.

The moment of inertia, also called angular mass or rotational inertia, of a rigid body refers to a quantity that determines the required torque for a desired angular acceleration about a rotational axis. Moment of inertia is the sum of the product of the mass of every particle with its square of a distance from the axis of rotation.  Hence, moment of inertia of a system about an axis can be found by simply adding each of their moments, i.e., I = I1 + I2 + I3…+ In. Moment of inertia is given as: I = mr^2

Hence, based on given information:

I = m1(r1)^2 + m2(r2)^2 + m3(r3)^2

I = m(0)^2 + 2m(a)^2 + 3m(2a)^2

I = 2ma^2 + 12ma^2

I = 14ma^2

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You may determine the number of moles of solution you need by multiplying the volume in liters (4.00L) by the solution's molar concentration (0.250M), and then by the mass of sodium hydroxide (39.99 g/mol) in molar form. 1L = 39.99g × 4.00L x 0.250 M x 39.99g

The number sodium hydroxide of moles of solute dissolved in one liter of a solution is known as its molarity.

where,

250 mM Molarity =

moles of solute = n

= liquid volume in milliliters = 4L = 4000 ml

Now, using the molarity formula to combine all the values provided, we obtain

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The products of the reaction of OCH2CH2OH with excess HBr under heat are: OCH2CH2Br (2-bromoethanol) and BrCH2CH2OH (1-bromo-1-propanol)

The mechanism for the reaction of OCH2CH2OH with excess HBr under heat is a multi-step process that involves the formation of a carbocation intermediate. Step 1: Protonation of the oxygen atom in OCH2CH2OH by HBr to form a good leaving group (OH) and a carbocation intermediate.

Step 2: Bromine atom from HBr attacks the positively charged carbon of the carbocation intermediate to form a covalent bond, resulting in the formation of intermediate compound.Step 3: Deprotonation of the intermediate compound by the remaining hydroxyl group to give OCH2CH2Br (2-bromoethanol) and HBr

Step 4: the HBr molecule from the step 3 could protonate another molecule of OCH2CH2OH and repeat the step 1 to 3 to form BrCH2CH2Br (1-bromo-1-propanol) as second product.

Overall, the reaction is an electrophilic substitution reaction, with HBr as the electrophile and the oxygen atom of the alcohol as the nucleophile.

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