What is the effect on the graph of the parent function f(x) = x when f(x) is changed to x+6.
A) same slope, same y-intercept
B) same slope, different y-intercept
C) different slope, same y-intercept
D) different slope, different y-intercept

Answer: B, F

Step-by-step explanation: I did the test

The mean and median of Data set A are close to each other.

The mean of the data sets are within 3 units from each other.

The correct option is (B) and (F)

Data Set A: 25 26 27 28 29 30 31 32 33 34 35

Data Set B: 25 26 27 28 29 30 31 32 33 34 35

For Data A,

For Data B,

So, from above observation we can see that:

The mean and median of Data set A are close to each other.

The mean of the data sets are within 3 units from each other.

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Answer: 10.56 cups.

Step-by-step explanation:

1 liter = 4.22 cups; 1.5 liters = 6.34 cups; 2 liters = 8.45 cups; 2.5 liters = 10.56 cups.

Answer:

By exterior angle theorem, we have;

∠DBE = ∠H + ∠HEB = ∠ECD = ∠H + ∠HDC

∴ ∠H + ∠HEB = ∠H + ∠HDC

By addition property of equality, we have

∠HEB = ∠HDC

∠H = ∠H by reflexive property

∴ ΔHCD ~ ΔHEB by Angle Angle AA similarity postulate

∴ HE/HD = EB/DC, by the definition of similarity

Therefore, by cross multiplication, we have;

HE × DC = EB × HD

Therefore, by commutative property of multiplication, we have;

HE × DC = HD × EB

Step-by-step explanation:

Answer:

Both

Step-by-step explanation:

You can find both from the given 85

Unreasonable Time is the nest option for running the group raffle at an upcoming assembly to give away a prize.

As given that;

Reasonable Time: Algorithms with a polynomial efficiency or lower (constant, linear, square, cube, etc.) are said to run in a reasonable amount of time.

Unreasonable Time: Algorithms with exponential or factorial efficiencies are examples of algorithms that run in an unreasonable amount of time.

Your school is considering running the group raffle at an upcoming assembly to give away a prize.

We have to write a brief explanation of what advice you would give them.

We can use the unreasonable time because  running the group raffle at an upcoming assembly to give away a prize cannot complete their work is the given amount of time.

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The explicit formula for the sequence -28, -31, -34, -37, ..., is aₙ= -28 -3d.

A series of integers called an arithmetic progression or arithmetic sequence (AP) has a constant difference between the terms.

Given:

-28, -31, -34, -37, ...

The general formula of an arithmetic sequence:

aₙ= a₁ + (n)d,

where a₁ is the first term and d is the common difference.

First, we will find the common difference between consecutive terms.

Here,

a₁ = -28

To find the common difference:

a₂ - a₁ = -31 + 28 = -3

a₃ - a₂ = -34 + 31 = 3

a₄ - a₃ = -37 + 34 = 3

Hence, d = -3.

Substitute the values to the formula,

aₙ= a₁ + (n)d,

aₙ= -28 + (-3)d,

aₙ= -28 -3d

Therefore, aₙ= -28 -3d is the required sequence.

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Answer:

Kumain ka Ng pansit para ka Maka sagot

Step-by-step explanation:

follow pleas helpme

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Answer:

The first option seems about right

Answer:

I would say $55.............

Answer:

is there any other picture or part you did not show, because sales and week sis not enough for me

Step-by-step explanation:

Answer: The answer is -1.6

Step-by-step explanation:

(7x-5)=2x-13

     +5      +5

7x=2x-8

5x=-8

divide -8 by 5= -1.6

Answer:

-1.6

Step-by-step explanation:

The system of linear equations Ax + 3y = a, 3x + ay = A has no solutions for any value of a.

To determine if the system of linear equations Ax + 3y = a, 3x + ay = A has no solutions for any value of a, we can use the elimination method.

We want to eliminate one of the variables, so let's start by multiplying the first equation by 3 and the second equation by -1.

This gives us:

3Ax + 9y = 3a, -3x - ay = -A.

Now we add the equations together to get:

2Ax + 8y = 3a - A.

Now we can see that the equation is not solvable as there is no value of a that will make the equation true. Therefore, the system of linear equations Ax + 3y = a, 3x + ay = A has no solutions for any value of a.

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The cost of 48 water bottles will be $5.9.

The mathematical expression combines numerical variables and operations denoted by addition, subtraction, multiplication, and division signs.

Mathematical symbols can be used to represent numbers (constants), variables, operations, functions, brackets, punctuation, and grouping. They can also denote the logical syntax's operation order and other properties.

Given that there are 24 water bottles and costs $2.95. The cost of 48 water bottles will be calculated as,

24 water bottles = $2.95

1 water bottle = $2.95 / 24

48 water bottle = ( 2.95 x 48 ) / 24

48 water bottles = $5.9

Hence, the cost will be $5.9.

The complete question is given below.

24 water bottles for $2.95. What is the cost of 48 water bottles?

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Answer:

She missed 15 questions.

Step-by-step explanation:

25% of 60 = 15

(25/100) * 60 = 15

Therefore, she missed 15 questions.

Mark me brainliest and thenksss :))

The function form of the given function would be  [tex]f(x)=log_b(x)[/tex].

What is a function?

In mathematics, a function from a set X to a set Y assigns to each element of X exactly one element of Y. The set X is called the domain of the function and the set Y is called the codomain of the function.

The given function is f(x) = logbx.

So the function form would be the function of x is equal to the logarithmic of x having base b.

so this can be written as

       [tex]f(x)=log_b(x)[/tex]

Hence, the function form of the given function would be  [tex]f(x)=log_b(x)[/tex].

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The function form of the given function would be  [tex]f(x)=log_b(x)[/tex].

What is a function?

In mathematics, a function from a set X to a set Y assigns to each element of X exactly one element of Y. The set X is called the domain of the function and the set Y is called the codomain of the function.

The given function is f(x) = logbx.

So the function form would be the function of x is equal to the logarithmic of x having base b.

so this can be written as

[tex]f(x)=log_b(x)[/tex]

Hence, the function form of the given function would be  [tex]f(x)=log_b(x)[/tex].

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Answer: 256b

Step-by-step explanation: So, first we need to find the square root of 16b.

That'd be 4b, because a square root is when a number can be divided by a number, such as 4 can go into 16 4 times, and like 5 can go into 25 5 times. So, we got 4b

So, 4 to the power of 4 (ignore the b right now) is the same as 4 x 4 x 4 x 4.

So simplified, that'd be 16 x 4 (64). So, 64 x 4 = 256.

So, I'd be 256b

the range of the function shown in the graph -1 [tex]\leq[/tex] y[tex]\leq[/tex] 1.

All real numbers fall within the domain of the sine and cosine functions. Both the sine and cosine functions have a range of [1,1]. An angle's sine and cosine have the same absolute value as their respective reference angles.

An illustration of the function's range in the graphs of cos and sine

The cosine function's graph appears as follows: The range of the function y=cos(x) is 1y1, and the domain is all real numbers (cosine is defined for any angle measure).

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Answer:

1800

Step-by-step explanation:

Let us solve this question by Modular Airthmatic.

Let the lowest 4 digit number be X.

X= 1 (mod 5)

X =2 (mod 5)

X=3 (mod 5)

X =4 (mod 5)

X=1+5 t where t is any integer.

1+5 t=2 (mod 5)

5 t=1 (mod 5 )

5 is the Modular Inverse of modulo 5

t=1 (mod 5)

t =1+5 u : u= any integer.

X becomes 1+ 5 (1+5u )=6+25 u

6+25u =3 (mod 5)

25 u= -3 (mod 5)=2 (mod 5)

25 is Modular Inverse of Modulo 5

u=2 (mod 5)

u =2+5 v : v= any integer.

X becomes 6 +25 (2+5 v)=56+125 v .

56 +125 v=4 (mod 5)

125 v=-52 (mod 5)=3 (mod 5)

125 is Modular Inverse of modulo 5

v = 3 (mod 5)

v =3 +5 w where w is any integer.

For lowest 4 digit number, take

w=200

X=1003 : Lowest 4 digit number.

Take w=201

X=208 : Next number.

For 4 digit largest number, take

w=1995

X= 9978 : Largest number.

No. of Numbers =(1995 - 200 )+1=1800 □Ans.

Answer:

1800 ways.

Step-by-step explanation:

Answer:

  lower left (already identified)

Step-by-step explanation:

You want the graph showing x < 2.

The boundary line of the solution area will be x = 2. Because that line is not included in the space x < 2, the line is dashed. (Eliminates graphs on the right.)

The solution space includes values of x that are less than 2. That means they are to the left of the boundary line. Shading will be left of the dashed line. (Eliminates graphs on the top.)

The correct graph of x < 2 is the one at lower left, already highlighted in the image.

Answer:

No, I will not simplify -164

Step-by-step explanation:

You can not Simplify -164

so the answer will be you can not simplify it

Answer: C, 217

Step-by-step explanation:

Four hemispheres are present in the shaded area. One large hemisphere and three smaller hemispheres each have a radius of 18 cm.

Consequently, the hemisphere's total surface area is 3(pi)R2. A semicircle has a curved line and a straight line that are both equal to the circle's diameter. The curving line is 2R in length while the straight line is (pi)R in length. So, 2R + (pi)R is the semicircle's total perimeter.

The shaded regions' area is calculated as follows:

initially, area of a hemisphere = 2r2 square units

the area of three small hemispheres

(2*3.14*6 r).3 = 226.08 cm2

Area of the larger hemisphere

2*3.14*18^2 = 2034.72cm^2

Total area of the shaded regions = 226.08 + 2034.72 = 2260.8cm^2

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[tex]\cfrac{45p^5q^4-60p^3q^2 - 15p^2q^3}{15p^2 q^3}\implies \cfrac{45p^5q^4}{15p^2 q^3}-\cfrac{60p^3q^2}{15p^2 q^3}-\cfrac{15p^2q^3}{15p^2 q^3}\implies 3p^3q-\cfrac{4p}{q}-1[/tex]

Answer:218

explanation: 162 divided by 9 = 18 and 18 multiplied by 12 =218

Answer:

point form is: (-7,2)

equation form is: x = -7, y = 2

Step-by-step explanation:

add the equations in order to solve for the first variable. plug this value into the other equations in order to solve for the remaining variables

pls mark as brainliest lol

Answer:

yes thats your answer

Step-by-step explanation:

Answer:

The hight of the box is 1.2 m

Step-by-step explanation:

250cm= 2.5m

100cm= 1m

2.5x1=2.5

3/2.5=1.2

2.5 x 1 x 1.2=[tex]3m^{3}[/tex]