what is the most basic level of organization that can perform functions like converting food into energy

Answers

Answer 1

Answer: Cells

Explanation:


Related Questions

You want to have a barbecue this weekend! But you're worried about global warming. You only want to release a maximum of 0.750 kg of carbon dioxide from your propane grill. Using the below equation to answer the following questions.

CH3(g) + 5O2(g) → 3CO2(g) + 4H2O(g)

ΔHrxn = -2220.1 kJ

a. How many kilojoules will you be able to release?

b. If it requires 1900 kJ to cook one hamburger, how many hamburgers can you cook?

Answers

a. We will be able to release 37,827 kJ. b. You can cook a maximum of 19 hamburgers without exceeding the limit of 0.750 kg of carbon dioxide.

a. We need to use the balanced chemical equation and the enthalpy change of the reaction.

Therefore, moles  [tex]CO_2[/tex] produced are[tex]0.750 kg / 44.01 g/mol = 17.03 mol.[/tex]

The enthalpy change of the reaction is -2220.1 kJ/mol. Thus, the maximum number of kilojoules that can be released is:

[tex]\Delta Hrxn * moles of[/tex] [tex]CO_2[/tex] = [tex]-2220.1 kJ/mol * 17.03 mol = -37,827 kJ[/tex]

We need to reverse the sign of the answer, giving us 37,827 kJ.

b. If it requires 1900 kJ to cook one hamburger, we can divide the maximum number of kilojoules that can be released by the energy required to cook one hamburger:

37,827 kJ / 1900 kJ/hamburger = 19.91 hamburgers

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Please help me with this chemistry investigation I need answers as soon as possible please ​

Answers

B. To plot the data on a bar chart, draw a horizontal axis for metals and a vertical axis for time to complete the reaction. Then, draw bars for each metal that represent the amount of time required to complete the reaction. The height of the bars must match the time values ​​in the table.

C. No, Emilia was not correct in her forecast. According to the data, aluminum reacted 100 seconds faster than magnesium, which reacted in 50 seconds. Thus aluminum reacts more rapidly with hydrochloric acid than magnesium.

From most reactive to least reactive, the metals are as follows:

aluminummagnesiumZincIron

This order is consistent with the reactivity series, which is:

PotassiumSodiumCalciumMagnesiumAluminiumZincIronCopperSilverGold

We are unable to estimate the reactivity of potassium, sodium, calcium, copper, silver, or gold from this experiment because those variables are not present in the data.

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If the reaction A (aq) + B (aq) C(aq) has a Ka value equal to 4.26 x 10-6, what is the G value at 25 °C if the concentrations are as follows:

[A] = 1.50 M
[B] = 1.00 M
[C] = 5.00 x 10-5 M

Answers

The ΔG value for the reaction A (aq) + B (aq) → C(aq) at 25 °C and the given concentrations is -8.35 kJ/mol.

The relationship between ΔG and K is given by the following equation:

ΔG = -RTln(K)

where R is the gas constant (8.314 J/(mol·K)), T is the temperature in Kelvin (25 °C = 298.15 K), and ln denotes the natural logarithm.

To calculate K, we need to use the equilibrium expression and the given concentrations:

[tex]K = [C]/([A][B])[/tex]

[tex]K = (5.00 * 10^{-5} M)/((1.50 M)(1.00 M))[/tex]

[tex]K = 3.33 x 10^{-5}[/tex]

Now we can substitute the values for R, T, and K into the equation for ΔG:

ΔG = -RTln(K)

ΔG = [tex]-(8.314 J/(mol.K))(298.15 K)ln(3.33 x 10^{-5})[/tex]

ΔG = -8.35 kJ/mol

Therefore, the ΔG value for the reaction A (aq) + B (aq) → C(aq) at 25 °C and the given concentrations is -8.35 kJ/mol.

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which type of mutation could have the most drastic effect
on a gene a chromosomal mutation? Back up your choice.

Answers

Answer:

we need to know the definitions of the two types of mutations:

A chromosomal mutation is a change in the structure or number of chromosomes, which are the structures that carry genes. Examples of chromosomal mutations are deletions, duplications, inversions, and translocations.A gene mutation is a change in the sequence of nucleotides, which are the building blocks of DNA and RNA. Examples of gene mutations are substitutions, insertions, and deletions.

Looking at the definitions, we can see that a chromosomal mutation can affect many genes at once, while a gene mutation can affect only one or a few nucleotides. Therefore, a chromosomal mutation could have the most drastic effect on a gene, because it could alter or delete an entire gene or multiple genes, resulting in major changes in the phenotype or function of an organism. A gene mutation could also have significant effects on a gene, but it could also be silent or minor depending on the location and type of the mutation. Therefore, the answer is a chromosomal mutation. One possible way to back up this choice is to give an example of a chromosomal mutation that causes a genetic disorder, such as Down syndrome or Turner syndrome.

If 50 joules of energy is added to sample of water, the temperature will?

Answers

Explanation:

The temperature change of a substance when it absorbs or loses energy can be calculated using the specific heat capacity of the substance. The specific heat capacity of water is approximately 4.18 J/(g°C), which means that it takes 4.18 joules of energy to raise the temperature of 1 gram of water by 1 degree Celsius.

To calculate the temperature change of the water sample when 50 joules of energy is added, we need to use the following equation:

q = m * c * ΔT

where q is the amount of energy absorbed by the water, m is the mass of the water sample, c is the specific heat capacity of water, and ΔT is the resulting temperature change.

Rearranging the equation to solve for ΔT, we get:

ΔT = q / (m * c)

Plugging in the values, we get:

ΔT = 50 J / (m * 4.18 J/(g°C))

We need to know the mass of the water sample to calculate the temperature change. Let's assume a mass of 10 grams:

ΔT = 50 J / (10 g * 4.18 J/(g°C))

ΔT = 1.2°C

Therefore, if 50 joules of energy is added to a 10-gram sample of water, the resulting temperature change will be approximately 1.2 degrees Celsius.

what is the pH of a solution prepared.by dissolving 4.0 g of HCL in water to make 475mL of a solution

Answers

To find the pH of the solution, we need to first calculate the concentration of H+ ions in the solution using the following equation:

[H+] = (moles of HCl) / (volume of solution in liters)

First, let's convert the mass of HCl to moles:

moles of HCl = mass / molar mass = 4.0 g / 36.46 g/mol = 0.1096 moles

Next, let's convert the volume to liters:

475 mL = 0.475 L

Now we can calculate the concentration of H+ ions:

[H+] = 0.1096 moles / 0.475 L = 0.2306 M

Finally, we can calculate the pH using the equation:

pH = -log[H+]

pH = -log(0.2306) = 0.637

Therefore, the pH of the solution is approximately 0.637.

What is the number of molecules of NO, which contains 16 gm of oxygen. 14

Answers

We can start by using the molecular formula of NO, which is NO = N + O. From the formula, we can see that the molecular weight of NO is 30 g/mol (14 g/mol for nitrogen + 16 g/mol for oxygen).

To find the number of molecules of NO that contains 16 g of oxygen, we need to first calculate the number of moles of oxygen in 16 g of oxygen. Using the atomic weight of oxygen (16 g/mol), we can calculate:

moles of O = mass of O / atomic weight of O = 16 g / 16 g/mol = 1 mol

Next, we need to determine the number of moles of NO that contains 1 mol of oxygen. From the molecular formula of NO, we can see that 1 mol of NO contains 1 mol of oxygen. Therefore, the number of moles of NO that contains 1 mol of oxygen is also 1 mol.

Finally, we can use Avogadro's number to convert the number of moles of NO to the number of molecules of NO. Avogadro's number is approximately 6.02 x 10^23 molecules/mol. Therefore, the number of molecules of NO that contains 16 g of oxygen is:

number of molecules of NO = number of moles of NO x Avogadro's number
number of molecules of NO = 1 mol x 6.02 x 10^23 molecules/mol
number of molecules of NO = 6.02 x 10^23 molecules

Therefore, there are approximately 6.02 x 10^23 molecules of NO that contain 16 g of oxygen.

A sphere has a diameter of 16 m. What is the volume of the sphere?

Answers

Answer:

V ≈ 2144.66 m³

Explanation:

Volume of sphere formula is:

V = 4/3 πr³

Radius is half the diameter so we divide the given diameter, 16 by 2 to get 8, the radius. Now we can solve

V = 4/3 π (8)³

V = 4/3 (512π)

V = 2048/3 π

V ≈ 2144.66 m³

Answer:

4/3 x π

Explanation:

please help me with this lab i wasn’t here for!

3. now that you have the mass of the NaHCO3 reactant, and the mass of the product NaCI , convert each to moles and compare to the mole ratio from your balanced equation C space below for your calculations

mass NaHCO3:
mass NaCI:
moles NaHCO3:
moles NaCI:

does the mole to mole ratio for your reaction? Agree with the ratio for the balanced equation?___

4. which reactant is the excess reactant for your reaction, how do you know?

5. Using the limiting reactant calculate the maximum amount of product that can be made from this reaction.

6. using the theoretical yield in the mass of the product that you put produce calculate percent yield.

calculations:
question #3: converting mass to moles

question #5: calculating the theoretical yield

question #6: calculating percent yield

Answers

Question #3: 0.8 g of NaHCO3 mass NaCI weight: 0.4 g 0.8 g/84 g/mol, or 0.0095 moles, of NaHCO3 0.4 g/58.5 g/mol = 0.0068 moles of NaCI are the moles.

The reaction's mole to mole ratio and the ratio in the balanced equation (1:1) are in agreement. The highest quantity of NaCI that may be produced from this reaction is 0.0095 moles since NaHCO3 is the limiting reactant.

The theoretical yield of NaCI is 0.0095 moles, which is question #6. The finished product weighs 0.4 g. The percent yield is 0.4 g/0.0095 moles times 100, which is 42.1%.

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A 0.4856 g sample of solid silver oxide is heated. Find the volume of O2 that can be released at STP.

Answers

The volume of O2 that can be released at STP from the given sample of silver oxide is 23.45 mL.

To solve this problem

Creating the balanced chemical equation for the breakdown of silver oxide is the first step in tackling this issue:

2Ag2O(s) → 4Ag(s) + O2(g)

We can deduce from the equation that 2 moles of AgO will result in 1 mole of O2. Since Ag2O has a molar mass of 231.735 g/mol, 0.4856 g of Ag2O is equivalent to:

0.4856 g Ag2O x (1 mol Ag2O/231.735 g Ag2O) = 0.002095 mol Ag2O

Therefore, the number of moles of O2 that can be produced from 0.4856 g of Ag2O is:

0.002095 mol Ag2O x (1 mol O2/2 mol Ag2O) = 0.0010475 mol O2

1 mole of any gas takes up 22.4 L of space at STP As a result, 0.4856 g of Ag2O can generate the following amount of O2 at STP:

0.0010475 mol O2 x 22.4 L/mol = 0.02345 L or 23.45 mL

Therefore, the volume of O2 that can be released at STP from the given sample of silver oxide is 23.45 mL.

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What is volume of 12.0 g of carbon dioxide at stp?

Answers

Answer: 6.11 L

Explanation:

STP= 1atm, 273.15K

Molar mass of CO2=44.01g/mol so n= (12.0/44.01)

PV=nRT

V=(nRT)/P

V=((12.0/44.01)(0.0821)(273.15))/1

V=6.11L

PLEASE ACTUALLY ANSWER THE WHOLE ASSIGNMENT FOR BRAINLIEST

Answers

The results of the lab activity showed that the larger the mass of the sun, the more likely at least one planet will fall into the habitable zone.

What effect does the mass of the Sun have on the orbits of Planets?

The mass of the sun affects the orbits of planets in a solar system. When the mass of the sun is larger, the gravitational force between the sun and the planets is stronger, causing the planets to move at a slower pace around the sun.

Conversely, when the mass of the sun is smaller, the gravitational force is weaker, causing the planets to move at a faster pace.

Additionally, when Earth is closer to the sun, the gravitational force is stronger, causing its orbit to become faster, while a farther distance from the sun results in a slower orbit.

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How many grams of KOH are needed to make 185.5 ml with a concentration of 5 M?
Type your answer...

Answers

To calculate the mass of KOH needed to make a 5 M solution in 185.5 mL, we need to use the formula:

mass = moles × molar mass

where moles is the amount of KOH in moles and molar mass is the mass of one mole of KOH.

We can calculate the moles of KOH as follows:

moles = Molarity × Volume (in liters)

First, we need to convert the volume from milliliters to liters:

185.5 mL = 0.1855 L

Now we can calculate the moles of KOH:

moles = 5 M × 0.1855 L = 0.9275 moles

The molar mass of KOH is 56.11 g/mol. Therefore, the mass of KOH needed is:

mass = 0.9275 moles × 56.11 g/mol = 52.05 g

Therefore, 52.05 grams of KOH are needed to make a 5 M solution in 185.5 mL.

Suppose 10.0 g of ice at -10.0C is placed into 300.0 g of water in a 200.0-g copper calorimeter. The final temperature of the water and copper calorimeter is 18.0C.
1) What was the initial common temperature of the water and copper? (Express your answer to three significant figures.)

Answers

The intital common temperature of copper and water is 9.5°C, under the condition that 10.0 g of ice at -10.0C is placed into 300.0 g of water in a 200.0-g copper calorimeter.

Now to evaluate the initial common temperature of the water and copper calorimeter, we have to apply the formula
m1c1(Tk - Ti) + m2c2(Tk - Ti)
= mcopperccopper(Tk - Ti)

Here,
m1 = mass of water,
c1 =specific heat capacity of water,
m2 = mass of copper calorimeter,
c2 = specific heat capacity of copper calorimeter, mcopper = mass of copper block
ccopper =specific heat capacity of copper.

Here, this equation to evaluate Ti
Ti = (m1c1Tk + m2c2Tk - mcopperccopperTk - m1c1Ti - m2c2Ti) / (m1c1 + m2c2 - mcopperccopper)

Staging the given values into this equation
Ti = (-300.0 g)(4.18 J/g°C)(18.0°C) + (200.0 g)(0.385 J/g°C)(18.0°C) + (10.0 g)(0.385 J/g°C)(18.0°C) / [(300.0 g)(4.18 J/g°C) + (200.0 g)(0.385 J/g°C) - (10.0 g)(0.385 J/g°C)]
Ti = 9.5°C

Hence, the initial common temperature of the water and copper calorimeter was 9.5°C.
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ichiometry in space
A typical space shuttle crew consists of six individuals and
each CCC contains 750 g of LIOH. Assuming that each crew
member expels 42.0 g of CO₂ per hour on average, and that
a mission is scheduled to last 18 days, how many CCCS must
be carried on board the space
shuttle?
- By knowing the recipe (balanced chemical equation), and
some molar masses, I can calculate this answer.

Answers

We need to carry at least 187 CCCs on board the space shuttle to absorb all the CO2 produced by the crew during the 18-day mission.

What is the amount of CO2 absorbed?

To solve this problem, we need to use the following information:

Each crew member expels 42.0 g of CO2 per hour.The mission is scheduled to last 18 days.There are 6 crew members on board.Each CCC contains 750 g of LIOH.

First, we need to calculate the total amount of CO2 that will be expelled during the mission:

Total CO2 = 6 crew members x 42.0 g CO2/hour x 24 hours/day x 18 days = 136,080 g CO2

Next, we need to calculate the amount of LIOH needed to absorb this CO2. The balanced chemical equation for the reaction between CO2 and LIOH is:

CO2 + 2 LIOH → Li2CO3 + H2O

The molar mass of CO2 is 44.01 g/mol, and the molar mass of LIOH is 23.95 g/mol.

This means that 2 moles of LIOH are needed to absorb 1 mole of CO2.

So, to absorb 136,080 g of CO2, we need:

136,080 g CO2 x (1 mol CO2/44.01 g) x (2 mol LIOH/1 mol CO2) x (23.95 g LIOH/1 mol) = 139,648 g LIOH

Since each CCC contains 750 g of LIOH, we need:

139,648 g LIOH / 750 g CCC = 186.2 CCCs

Therefore, we need to carry at least 187 CCCs on board the space shuttle to absorb all the CO2 produced by the crew during the 18-day mission.

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What mass (grams) of silver oxide would you need to decompose in order to produce 120.6 grams of silver?

Ag2O --> Ag + O2

Answers

The mass of silver oxide needed to decompose in order to produce 120.6 grams of silver is 494.5 grams.

The balanced chemical equation for silver oxide breakdown is:

[tex]Ag_2O[/tex] → [tex]2 Ag[/tex] + [tex]1/2 O_2[/tex]

The equation shows that for every mole of silver oxide that decomposes, two moles of silver are created, and the molar mass of [tex]Ag_2O[/tex] is 231.74 g/mol.

Hence, using stoichiometry, we can calculate the quantity of silver oxide necessary to generate 120.6 grams of silver:

120.6 g Ag × (1 mol Ag / 107.87 g Ag) × (1 mol [tex]Ag_2O[/tex]/ 2 mol Ag) × (231.74 g [tex]Ag_2O[/tex] / 1 mol [tex]Ag_2O[/tex] )

= 494.5 g [tex]Ag_2O[/tex]

As a result, 494.5 grams of silver oxide is needed to decompose in order to produce 120.6 grams of silver.

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How are models used in chemistry? How does evidence change these models?​

Answers

Answer: As they develop theories, chemists use models to attempt to explain their findings. Chemists assess the model they are using as new evidence becomes available and, if required, continue to refine it by making modifications.

Explanation:

WHEN SOME PEOPLE HAVE AN UPSET STOMACH, THEY TAKE A SODA TABLET LIKE
TUMS TO NEUTRALIZE THEIR STOMACH ACID.
THE REACTION IS HYDROCHLORIC ACID PLUS SODIUM BICARBONATE MAKES SALT,
CARBON DIOXIDE (THAT'S WHY SOME PEOPLE BURP) AND WATER.
HOW MUCH CARBON DIOXIDE AND SALT (IN GRAMS) ARE PRODUCED IF A 2 GRAM
TABLET OF SODIUM BICARBONATE IS TAKEN TO REACT WITH 18 GRAMS OF
HYDROCHLORIC ACID?

Answers

The balanced chemical equation for the reaction between hydrochloric acid (HCl) and sodium bicarbonate [tex](NaHCO_3)[/tex] is:

[tex]HCl + NaHCO_3\ - > NaCl + CO_2 + H_2O[/tex]

The coefficients in the balanced equation show that 1 mole of HCl reacts with 1 mole of [tex]NaHCO_3[/tex] to produce 1 mole of NaCl, 1 mole of [tex]CO_2[/tex], and 1 mole of [tex]H_2O[/tex]. We need to find the number of moles of [tex](NaHCO_3)[/tex] present in the tablet.

2 grams of [tex]NaHCO_3[/tex] is equivalent to 0.02 moles, and 18 grams of HCl is equivalent to 0.45 moles. Since [tex](NaHCO_3)[/tex] is limiting reagent, only 0.02 moles of NaCl and [tex]CO_2[/tex] will be produced. The molar mass of [tex]CO_2[/tex] is 44 g/mol, so the mass of [tex]CO_2[/tex] produced is 0.88 g. The molar mass of NaCl is 58.44 g/mol, mass of NaCl produced is 1.17 g.

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Benzoic acid (C6H5COOH) and aniline (C6H5NH2) are both derivatives of benzene. Benzoic acid is an acid with Ka=6.3×10^(−5) and aniline is a base with Kb=4.3×10^(−10) .What is the value of the equilibrium constant for the following equilibrium? C6H5COOH(aq)+C6H5NH2(aq)⇌C6H5COO−(aq)+C6H5NH3+(aq)
i want an accurate answer

Answers

The reaction C₆H₅COOH(aq) + C₆H₅NH₂(aq) ⇌ C₆H₅COO⁻(aq) + C₆H₅NH₃⁺(aq) has an equilibrium constant of 0.3698.

How to determine equilibrium constant?

The equilibrium constant (Kb) for the reaction can be calculated using the Ka and Kb values of the reactants and the equation:

Kw = Ka x Kb

where Kw = ion product constant of water (1.0 x 10⁻¹⁴ at 25°C).

Calculate the Kb value for aniline:

Kb = Kw/Ka = (1.0 x 10⁻¹⁴)/(4.3 x 10⁻¹⁰) = 2.33 x 10⁻⁵

Use the Kb value for aniline and the Ka value for benzoic acid to calculate the equilibrium constant (K) for the reaction:

K = Kb/Ka = (2.33 x 10⁻⁵)/(6.3 x 10⁻⁵) = 0.3698

Therefore, the equilibrium constant for the reaction C₆H₅COOH(aq) + C₆H₅NH₂(aq) ⇌ C₆H₅COO⁻(aq) + C₆H₅NH₃⁺(aq) is 0.3698.

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If 12.5 mol
of an ideal gas occupies 50.5 L
at 69.00 ∘C,
what is the pressure of the gas?

Answers

The pressure of a gas that occupies 50.5L at 69.0°C is 6.95 atm.

How to calculate pressure?

The pressure of an ideal gas can be calculated using Avogadro's equation as follows;

PV = nRT

Where;

P = pressureV = volume n = no of molesT = temperatureR = gas law constant

According to this question, 12.5 mol of an ideal gas occupies 50.5 L at 69.00°C. The pressure can be calculated as follows:

P × 50.5 = 12.5 × 0.0821 × 342

50.5P = 350.9775

P = 6.95 atm

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You react 0.017 mol of solid metal with HCl in a coffee cup calorimeter (reaction shown below). The calorimeter has 100 mL of water in it, and the temperature of the water increases by 3.81°C. The calorimeter has a heat capacity of 40.4 J/°C. What is the enthalpy of the reaction in terms of kJ per mol of the metal (your answer should be NEGATIVE, remember to convert from J to kJ, specific heat capacity of water is 4.184 J/g-°C)?

M(s) + 2 HCl (aq) MCl2 (aq) + H2 (g)

M = metal

Answers

To calculate the enthalpy of the reaction in terms of kJ per mol of the metal, we can use the following formula:

q = -mCΔT

where q is the heat absorbed by the water and the calorimeter, m is the mass of the water, C is the heat capacity of the calorimeter, and ΔT is the change in temperature of the water.

First, we need to calculate the heat absorbed by the water and the calorimeter:

q = (100 g) x (4.184 J/g-°C) x (3.81°C) + (40.4 J/°C) x (3.81°C)
q = 1657.4 J

Next, we need to calculate the moles of HCl used in the reaction. From the balanced chemical equation, we can see that 2 moles of HCl react with 1 mole of the metal, so:

moles of HCl = 2 x moles of metal = 2 x 0.017 mol = 0.034 mol

Finally, we can calculate the enthalpy of the reaction per mole of the metal:

ΔH = -q / moles of metal
ΔH = -(1657.4 J) / (0.017 mol)
ΔH = -97,494 J/mol

To convert to kJ/mol, we divide by 1000:

ΔH = -97.494 kJ/mol

Therefore, the enthalpy of the reaction is -97.494 kJ/mol of the metal. Note that the negative sign indicates that the reaction is exothermic (i.e. heat is released).

bromsted-lowry acids and bases
find out the acids and bases

Answers

Johannes Brsted and Thomas M. Lowry, two chemists, identified the Bromsted-Lowry acids and bases as a particular kind of acid-base reaction in 1923.

Acids are substances that give a base a proton (H+), whereas bases are substances that take a proton from an acid. In a Bromsted-Lowry acid-base reaction, the acid gives the base a proton in order to create the conjugate base and the conjugate acid, two new compounds.

Nitric acid (HNO3), sulfuric acid (H2SO4), and hydrochloric acid (HCl) are a few examples of acids. Sodium hydroxide (NaOH), ammonium hydroxide (NH4OH), and potassium hydroxide (KOH) are a few examples of bases.

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17. An artist took two photographs of the Moon that were several days apart. Images that look like his photographs are shown above. The light part of the Moon appeared to get smaller over time. Why did this happen?

Answers

According to the information, we can infer that the difference between photographs 1 and 2 originate from the translation of the Moon around the earth (option C).

How do we explain the differences between the two images?

To explain the difference between both images we must take into account the movement patterns of the earth and the moon. In the case of the earth, it has 2 main movements, which are rotation on its own axis and translation around the sun.

On the other hand, the moon has a translational movement around the earth, which is what causes the different lunar phases. This motion causes the moon to appear partially shadowed from the earth because the earth blocks the sunlight.

Based on the above, we can infer that the correct answer is option C because this phenomenon is caused by the translation of the moon.

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Pleas help thanks!!!!!!!!!!!!!!!!!!!!

Answers

The number of molecules of BF₃ present in 2 grams of BF₃ is 1.776×10²² molecules (1st option)

How do i determine the number of molecules of BF₃?

We'll begin by calculating the number of mole of 2 grams of BF₃. Details below:

Mass of BF₃ = 2 grams Molar mass of BF₃ = 67.81 g/molMole of BF₃ =?

Mole = mass / molar mass

Mole of BF₃ = 2 / 67.81

Mole of BF₃ = 0.02949 mole

Finally, we shall determine the number of molecules of BF₃. This is shown below:

Avogadro's hypothesis suggest that:

1 mole of BF₃ = 6.022×10²³ molecules

Therefore,

0.02949 mole of BF₃ = 0.02949 × 6.02×10²³

0.02949 mole of BF₃ = 1.776×10²² molecules

Thus, the number of molecules of BF₃ is 1.776×10²² molecules (1st option)

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aHow does the electronic configuration of a sodium cation differ from that of a sodium atom?​

Answers

Sodium ion has obtained a stable electronic configuration by giving out one electron from the sodium atom. Therefore, sodium ion has one electron less than the sodium ion. In other words, the valence shell/ last shell of sodium atom has only one electron. But in sodium ion the last shell has 8 electrons.

Answer:

Atomic number of sodium is 11

Electronic configuration of a sodium atom :

1s² 2s² 2p⁶ 3s¹

Since sodium has one electron in its outermost shell, Therefore, sodium can easily donate it's one electron. As the result it becomes sodium cation with + 1 charge.

Electronic configuration of a sodium cation,[tex] \: \sf ({Na}^{+1}) [/tex]

1s² 2s² 2p⁶

In case of sodium cation, it has fully filled electronic configuration.

Cations - Atoms that carry postive charge are called cations. Cations are formed when an atom loses its electron.

For example : [tex]\sf {Na}^{+} [/tex]

Anions - Atoms that carry negative charge are called anions. Anions are formed when an atom gains a electron.

For example : [tex]\sf {Cl}^{-} [/tex]

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Which of the following graphs repMagnesium is the limiting reactant in this experiment. Calculate the theoretical yield of MgO for each trial.
· Trial 1:
· Trial 2:

Determine the percent yield of MgO for your experiment for each trial.
· Trial 1:
· Trial 2:
Determine the average percent yield of MgO for the two trials.
resents the function g (x) = x2(x + 1)(x – 2)?

Answers

The theoretical yield of MgO for Trial 1 is 0.348 g, and for Trial 2 is 0.307 g. The percent yield of MgO for Trial 1 is 58.0% and for Trial 2 is 159.2%. The average percent yield of MgO for the two trials is 108.6%.

To calculate the theoretical yield of MgO, we need to use the balanced chemical equation for the reaction between magnesium (Mg) and oxygen (O2) to form magnesium oxide (MgO):

2Mg + O₂ → 2MgO

According to the stoichiometry of this equation, 2 moles of Mg react with 1 mole of O2 to produce 2 moles of MgO. Therefore, we need to determine the number of moles of Mg in each trial and use the mole ratio to find the theoretical yield of MgO.

For Trial 1:

The mass of Mg used is: 26.682 g - 27.012 g = 0.330 g

The molar mass of Mg is 24.31 g/mol, so the number of moles of Mg is:

0.330 g / 24.31 g/mol = 0.0136 mol Mg

According to the balanced equation, 2 moles of Mg produce 2 moles of MgO, so the theoretical yield of MgO is:

0.0136 mol Mg x (2 mol MgO / 2 mol Mg) x (40.31 g MgO/mol) = 0.348 g MgO

For Trial 2:

The mass of Mg used is: 26.987 g - 26.695 g = 0.292 g

The number of moles of Mg is:

0.292 g / 24.31 g/mol = 0.0120 mol Mg

The theoretical yield of MgO is:

0.0120 mol Mg x (2 mol MgO / 2 mol Mg) x (40.31 g MgO/mol) = 0.307 g MgO

To calculate the percent yield of MgO, we need to use the following formula:

Percent yield = (actual yield / theoretical yield) x 100%

For Trial 1:

The actual yield of MgO is: 27.214 g - 27.012 g = 0.202 g MgO

The percent yield of MgO is:

(0.202 g / 0.348 g) x 100% = 58.0%

For Trial 2:

The actual yield of MgO is: 27.183 g - 26.695 g = 0.488 g MgO

The percent yield of MgO is:

(0.488 g / 0.307 g) x 100% = 159.2%

To calculate the average percent yield of MgO for the two trials, we add the percent yields and divide by 2:

Average percent yield = (58.0% + 159.2%) / 2 = 108.6%

Therefore, the theoretical yield of MgO for Trial 1 is 0.348 g, and for Trial 2 is 0.307 g. The percent yield of MgO for Trial 1 is 58.0% and for Trial 2 is 159.2%. The average percent yield of MgO for the two trials is 108.6%.

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Answers

Answer:

The Correct answer is option 3

Step by Syep Explanation:

4Fe+3O2---->rust

formula for rust----->Fe2O3

4Fe+3O2---->Fe2O3

Balancing the Chemical Equation

both the reactant and product side

we have that;

4Fe+3O2------->2FeO3

the equation is Chemically Balanced

therefore 4Fe+3O2------->2×rust

Answer:

2Fe₂O₃ (Option 3)

Explanation:

Given that,

4Fe + 3O2 → rust.

Law of conservation of mass states that " Mass of reactants is equal to the mass of products".

Also we know that In a balanced equation the total number of atoms in the reactants equals the total number of atoms in the product.

We are given with 4Fe + 3O₂ i.e the reactant.

First Let's calculate the number of atoms in the reactant.

No. of atoms in Fe = 4 No. of atoms in O = 3 × 2 = 6

Now, Let's find the product .

Also, We can see 2Fe₂O₃ (Product)

No. of atoms in Fe = 2 × 2 = 4 No. of atoms in O = 2 × 3 = 6.

4Fe + 3O₂ → 2Fe₂O₃

Number of atoms in the reactants = the total number of atoms in the product.

Therefore, 2Fe₂O₃ (Option 3) will the required answer .

Which
thermochemical
equation
corresponds to
the graph?

Answers

Answer: C

Explanation:

Answer: C

Explanation:

Question 8 of 21
Which nucleus completes the following equation?

Answers

The nucleus completing the following equation is option C: ₂₄⁵⁰Cr.

This reaction is a type of radioactive nuclei decay.

What is radioactive decay?

Radioactive decay is the process by which unstable atomic nuclei undergo spontaneous transformations in order to achieve a more stable state. This is accomplished by the emission of particles and/or electromagnetic radiation from the nucleus. The decay may occur by several mechanisms, including alpha decay, beta decay, gamma decay, and electron capture.

In alpha decay, the nucleus emits an alpha particle, which consists of two protons and two neutrons, resulting in a daughter nucleus that has two fewer protons and two fewer neutrons than the original nucleus.

In beta decay, a neutron in the nucleus is converted into a proton and an electron, and the electron is then emitted from the nucleus as a beta particle. This results in the daughter nucleus having one more proton and one fewer neutron than the original nucleus.

In gamma decay, the nucleus emits a gamma ray, which is a high-energy electromagnetic radiation, without changing the number of protons or neutrons in the nucleus.

In electron capture, an electron from the inner shell of the atom is captured by the nucleus, and a proton in the nucleus is converted into a neutron. This results in the daughter nucleus having one fewer proton and one more neutron than the original nucleus.

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Can someone please help me with chemistry?

Show steps! Thank you

Answers

a. The mass of Cr2O3 is 0.559 g Cr2O3 is the maximum amount of  Cr2O3 produced.

b.The limiting reactant is  Cr(NO3)3  because it produces less moles of Cr2O3 than Na2O.

c. The percent yield is 84%.

How do we calculate?

The balanced equation is shown below:

2 Cr(NO3)3 + 3 Na2O → Cr2O3 + 6 NaNO3

moles of Cr(NO3)3 = 1.75 g / 238.01 g/mol = 0.00735 mol

moles of Na2O = 1.75 g / 61.98 g/mol = 0.0282 mol

moles of Cr2O3 = (0.00735 mol Cr(NO3)3) × (1 mol Cr2O3 / 2 mol Cr(NO3)3) = 0.00368 mol Cr2O3 (theoretical yield)

mass of Cr2O3 = (0.00368 mol Cr2O3) × (151.99 g/mol) = 0.559 g Cr2O3

The percent yield can be calculated by dividing the actual yield by the theoretical yield and multiplying by 100%:

percent yield = (actual yield / theoretical yield) × 100%

percent yield = (0.455 g / 0.559 g) × 100% = 81.4%

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