how can you separate sand and water without filter paper​

Answers

Answer 1

Answer:

through Decantation

Explanation:

Decantation: Decantation is pouring out of upper clear layer of liquid into another container to separate two immiscible liquids or to separate different substances in a suspension mixture.

Therefore, we could use decantation once the sand particles settle down by gently pouring the water into another container. Once the water is transfered, we'll be left with sand in the bottom of the first container.

Hope that helps...


Related Questions

What is the molarity of a solution where 2.2 mol of KCl is dissolved to make 5.7 L of solution?

Answers

0.386M. Molarity is gotten by dividing no of moles by the volume (Litre or dm3)

Put the appropriate processes to their respective bins

Answers

Answer:

Remember

Endo = To EnterExo = To ExitThermic = Heat

A sparkler burning is an exothermic reaction

Sparkler burning is an exothermic reaction and so the sign of the ΔH must be negative (–∆H) indicating that heat was released.

Ice melting is an endothermic reaction (+H) because the ice absorbs (heat) energy, which causes a change to occur.

Acetone evaporating from skin is an endothermic reaction (+H). Because, molecules that are evaporating are absorbing heat. So, evaporation is called endothermic.

An electron in the n=7 level of the hydrogen atom relaxes to a lower energy level, emitting light of 93.1 nm.
What is the value of n for the level to which the electron relaxed?

Answers

answer:

nf=2

Explanation:

It is given that,

Initially, the electron is in n = 7 energy level. When it relaxes to a lower energy level, emitting light of 397 nm. We need to find the value of n for the level to which the electron relaxed. It can be calculate using the formula as :

a 21.0 kg rock rests on the edge of a cliff 32.0 m high. how much gravitational potential energy does the rock have

Answers

Explanation:

Formula for Potential energy=mgh mass* gravity*height

21kg × 10 ×32=6720joules

If a 21.0 kg rock rests on the edge of a cliff 32.0 m high, the gravitational potential energy gained by the rock would be 6585.6 Joules.

What is mechanical energy?

Mechanical energy is the combination of all the energy in motion represented by total kinetic energy and the total stored energy in the system which is represented by total potential energy.

As given in the problem a 21.0 kg rock rests on the edge of a cliff 32.0 m high, then we have to calculate the potential energy gained by the rock,

The potential energy of the rock = 21 × 9.8 × 32

                                                      = 6585.6 Joules.

Thus ,If a 21.0 kg rock rests on the edge of a cliff 32.0 m high, the gravitational potential energy gained by the rock would be 6585.6 Joules.

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A glass tube contains mercury. What would be the height of the column of mercury which would create pressure equal to 1.00 atm

Answers

Since 1.00 atm is equal to 760 mmHg, the height of the column of mercury which would create pressure equal to 1.00 atm is 760 mm or 76 cm

What are the units of pressure?

Pressure is defined as the force acting perpendicularly per unit area of a surface.

The units of pressure include;

millimetres of mercury, mmHgaatmospheres, atm,pascals, PaNewtons per square metre, N/m^2

1 atmosphere is equal to 760 mmHg.

Therefore, the height of the column of mercury which would create pressure equal to 1.00 atm is 760 mm or 76 cm

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Identify the type of energy conversion represented by each picture.
solar energy to light energy
electric energy to light energy
electric energy to heat energy
wind energy to electric energy

Answers

[tex]\qquad\qquad\huge\underline{{\sf Answer}}[/tex]

The given pictures show conversion of energy from one form to another.

#Picture 1

Electric energy to Heat energy

#Picture 2

Wind energy to electric energy

#Picture 3

Solar energy to light energy

#Picture 4

Electric energy to light energy

Calculate AHræn for the following reaction
2 AX (g) + 7 BY (g) →4AY (g) + 6 BX (g)
Use the following AHformation values for AX, BY, AY and BX
AX: AHformation = -80 kJ/mol
BY: AH formation = 57 kJ/mol
AY: AHformation = -379 kJ/mol
BX: AHformation = -251 kJ/mol

Answers

Answer:

60ax 70by 67ay ah251

Explanation:

A 0.15 M NaOH solution has a volume of 0.125 L but is then diluted to 0.15 L. What is the concentration of the new solution

Answers

Answer:

.125 M

Explanation:

.15 M/L   * .125 L = .01875 moles

now dilute to 150 cc  (by adding 25 cc)

.01875M / (150/1000) = .125M

Kelly's spring scale indicates that it takes 4.9 newtons of force to lift the mass directly.


With the lever, she plans to add masses to the right side until it is able to lift the 500-gram mass 10 cm.


Consider the location of the lever's fulcrum. When Kelly has added enough mass to the right side, she should expect the downward force exerted on the right side of the lever to be

A.

equal to 500 grams.

B.

less than 4.9 newtons.

C.

equal to 4.9 newtons.

D.

greater than 4.9 newtons.

Answers

Answer:

less than 4.9 newtons Explanation:


In your own words, define the following terms.
star

Answers

Answer:

A Sun that is hot and big and sparkling

Explanation:

A Star is a Sun which is tended to be true

Answer:

A star is a miniature version of a sun, which burns out over a course of time.

For the reaction H2O) =H% + OH", if x moles of H and y moles of OH are formed K. is y A. *?/(1 – x) C. 1/xy D. xy ​

Answers

Answer: Correct option is B)

The standard enthalpy change of formation of a compound is the enthalpy change which occurs when one mole of the compound is formed from its elements under standard conditions. The equation showing the standard enthalpy change of formation of water is

H
2
(g)+

2
1

​ O

2

​ (g)⟶H

2                                                                   ↑

​ O(l)                                           1 mole of water formed.

∴   Enthalpy of formation is −X2kJ/mol.

________________________________________________________

Explanation:I hope this helped

The cylinder of a car's engine has a volume of 0.6250 L when the piston is at the bottom of the cylinder. When the piston is at the top of the cylinder the volume is 0.0600 L. If the cylinder is filled with air at an atmospheric pressure of 765.1 mm Hg the piston is at the bottom, what is the pressure in units of kPa when the piston is at the top of the cylinder?

Answers

The new pressure in the cylinder of the car engine as the piston is moved to the top is 1062.55kPa

Boyle's law

Boyle's law states that "volume of a given quantity of gas is inversely proportional to its pressure  as long as temperature remains constant.

It is expressed as;

P₁V₁ = P₂V₂

Given the data in the question;

Initial volume V₁ = 0.6250LNew volume V₂ = 0.0600LInitial pressure P₁ = 765.1mmHg = 1.0067107atmNew pressure P₂ = ?

To determine the new pressure as the piston is at the top of the cylinder, we substitute our given values into the expression above.

P₁V₁ = P₂V₂

P₂ = P₁V₁ / V₂

P₂ = ( 1.0067107atm × 0.6250L ) / 0.0600L

P₂ = 0.629194188Latm / 0.0600L

P₂ = 10.4865698atm

P₂ = 1062.55kPa

Therefore, the new pressure in the cylinder of the car engine as the piston is moved to the top is 1062.55kPa

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Which technique can be used to remove air bubbles from a syringe? a) Hold the syringe downward, shake vigorously for 10 seconds, and expel the bubbles through the needle using the syringe plunger. Hold the syringe upright, provide a firm tap or flick to the b) barrel, and expel the bubbles through the needle using the syringe plunger. Hold the syringe upright, shake vigorously for 10 seconds, c) and expel the bubbles through the needle using the syringe plunger. Hold the syringe downward, provide a firm tap or flick to the d) barrel, and expel the bubbles through the needle using the syringe plunger.

Answers

Answer:

Point the syringe upright and tap firmly to move the bubbles to the top and expel by pushing the plunger

Explanation:

If you hold the syringe upside down the bubbles will end up at the bottom of the syringe by the plunger since they float up when tapped

Which statement is an opinion expressed in "Stick to Real Microscopes"?
A) Smartphone microscopes are not great scientific tools.
B) Many real microscopes cost between $150 and $300.
C) A fairly good real microscope can enlarge objects up to 2000 times their actual size.
D) It is quite inexpensive to turn a smartphone into a microscope.

Answers

Answer:it’s Smartphone microscopes are not great scientific tools.

Explanation:

The statement expressed in stick to real microscopes Smartphone microscopes are not great scientific tools.

What is scientific tools?

Getting to use all the great tools is one of the best parts of constructing something. Power saws, drills, and electric sanders are tools that builders employ to transform basic materials into original designs.

Scientists employ tools to achieve their goals, just like builders do. Researchers can do experiments, make observations, and take precise measurements with the aid of scientific gear.

In this session, we'll talk about some basic scientific instruments that you could find in the science lab at your school, as well as some more sophisticated instruments that biologists use to study the world around us.

Therefore, The statement expressed in stick to real microscopes Smartphone microscopes are not great scientific tools.

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8. Thermal Energy is?
A. Kinetic
B. Potential
c. Potential and Kinetic
D. Neither Potential and Kinetic

Answers

Thermal energy is the sum of the kinetic and potential energy of all the particles in an object. The figure shows that if either potential or kinetic energy increases, thermal energy increases.

hope it really helps...!!!

Why is it important for scientist to be objective when using the design process like the scientific method when doing there investigations?

Answers

Answer:

Scientists use the scientific method to make testable explanations and predictions about the world. A scientist asks a question and develops an experiment, or set of experiments, to answer that question. Engineers use the engineering design process to create solutions to problems.

What is ∆G° for a redox reaction where 6 moles of electrons are transferred and E° =-2.25 V? (F = 96,500 J/(V・mol))

Answers

A redox reaction with E° = -2.25 V involving the transference of 6 moles of electrons has a ΔG° of 9.38 × 10⁵ J.

What is the standard Gibbs free energy?

The standard Gibbs free energy (ΔG°) is a thermodynamical function that indicates the spontaneity of a reaction.

A redox reaction, in which 6 moles of electrons are transferred (n = 6 mol), has a standard cell potential (E°) of -2.25 V.

Knowing that the Faraday's constant is F = 96,500 J/V.mol, we can calculate the standard Gibbs free energy using the following expression.

ΔG° = - n × F × E°

ΔG° = - 6 mol × (96,500 J/V.mol) × (-2.25 V) = 9.38 × 10⁵ J

A redox reaction with E° = -2.25 V involving the transference of 6 moles of electrons has a ΔG° of 9.38 × 10⁵ J.

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plese help
Using the rules that you learned during the session, what is the answer to the following question?

55.78 * 23.7

Answers
A) 1,322
B) 1,320

explain:

Answers

The answer is A. The answer multiplied is 1321.986 but you round it up.

Hey guys i needed some help on this

Answers

Based on the bond energies given, the standard enthalpy of the reaction, ΔH°(rxn) is -296 kJ.

What is standard enthalpy change of a reaction?

The standard enthalpy change of a reaction is the energy changes involved when substances react under standard conditions to form products.

ΔH°(rxn) = sum of the bond energies of bonds being broken - sum of the bond energies of the bonds being formed.

The standard enthalpy of the reaction, ΔH°(rxn) is calculated as follows:

Sum of energy of bonds broken = 839 + (2 × 413) + (432 × 2) = 2529 kJ

Sum of energy of bonds formed = 347 + (6 × 413) = 2825 kJ

ΔH°(rxn) = (2529 - 2825) kJ

ΔH°(rxn) = -296 kJ

Therefore, the standard enthalpy of the reaction, ΔH°(rxn) is -296 kJ.

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Which unit is used to measure the distance between galaxies? Question 3 options: kilometers decades years light years

Answers

Answer:

light years

Explanation:

light year is the DISTANCE light travels in one year ...a very large distance

Answer:

light years

Explanation:

since distance between galaxy space ,objects .

A solution is made by adding 15 g of sodium chloride into 150 g of water. What is the mass percentage of this sodium chloride in this solution?

Answers

Answer:

[tex]\sf \fbox {mass \:percentage \: = 9.09 \%}[/tex]

Explanation:

Given:

Mass of solute = 15g

Mass of solvent (Water)= 150g

To find:

Mass percentage of sodium chloride=?

Solution:

Let's find out the mass of overall solution first,

Mass of solution= Mass of solute+ mass of solvent

Mass of solution = 15+150= 165 gram

Now we know that,

[tex] \sf \: mass \:percentage \: = \frac{Mass \: of \: solute}{Mass of solution} \times 100 \\ \sf \: mass \:percentage \: = \frac{15}{165} \times 100 \\ \sf \: mass \:percentage \: = \frac{1500}{165} \\ \sf \fbox {mass \:percentage \: = 9.09 \%}[/tex]

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Calculate the pH of the following aqueous solution:
0.35 M NaF (pKa for HF = 3.14)

I'm pretty sure I know how to calculate the pH by itself, but I am confused on how to get the equation. I'm not sure what HF has to do with this, other than it's an acid. I'm probably overthinking it because it's worded differently. Thanks in advance!​

Answers

The pH of an aqueous solution that has a concentration of 0.35 M NaF and pKa for HF = 3.14 is 3.6.

How to calculate pH?

The pH of a solution refers to the degree of acidity or alkalinity of the solution. It can be calculated using the Henderson-Hasselbalch Equation as follows:

pH = pka + log ([A-]/[HA])

Where;

A- = conjugate baseHA = weak acid

pH = pKa + log([F-]/[HF])

pH = 3.14 + log(1/0.35)

pH = 3.14 + 0.4559 = 3.595

Therefore, the pH of an aqueous solution that has a concentration of 0.35 M NaF and pKa for HF = 3.14 is 3.6.

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What is the equilibrium constant K at 25°C for an electrochemical cell when E° = +0.0140 V and n = 2?(F = 96,500 J/(V・mol), R = 8.314 J/(mol・K))

Answers

The equilibrium constant of the electriochmeical cell as shown is  2.976.

What is the equilibrium constant?

The equilibrium constant of a reaction shows the extent of the conversion of the reactants to products.

Now we know that;

ΔG = -nFE°cell

n = 2

F = 96,500 J/(V・mol)

E°cell = +0.0140 V

ΔG = -(2 *  96,500  * 0.0140)

ΔG = -2702 J

But;

ΔG = -RTlnK

lnK = -(ΔG/RT)

K = e^[-(ΔG/RT))

K = e^[-(( -2702)/8.314 * 298]

K = 2.976

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Consider the following reaction where Kc = 55.6 at 698 K.

H2(g) + I2(g) 2HI(g)

A reaction mixture was found to contain 2.29×10-2 moles of H2(g), 3.80×10-2 moles of I2(g) and 0.254 moles of HI(g), in a 1.00 liter container.

Is the reaction at equilibrium?
If not, what direction must it run in order to reach equilibrium?

The reaction quotient, Qc, equals
.

The reactionfill in the blank 2

A. must run in the forward direction to reach equilibrium.
B. must run in the reverse direction to reach equilibrium.
C. is at equilibrium.

Answers

Answer:

B

No the reaction is not at equilibrium

The reaction must run to the left (reactants) to reach equilibrium

Qc = 74.14

Explanation:

Qc = (0.254)^2 / ((2.29 x 10-2)(3.8 x 10-2))

Qc = 74.14

74.14 > 55.6

Qc > Kc


The rocks that result from these processes often have ribbonlike layers and may have shiny crystals, formed by_______
growing slowly over time, on their surface.



PLSSS HELPP ASAPP

Answers

Answer:

The rocks that result from these processes often have ribbonlike layers and may have shiny crystals, formed by Metamorphic Rock growing slowly over time, on their surface.

The rocks that result from these processes often have ribbonlike layers and may have shiny crystals, formed by Metamorphic rocks

growing slowly over time, on their surface.

Which of the following are true about photosynthesis and cellular respiration. (Select all that apply.)


The products of one process are the reactants of the other.


The relationship between them enables life to survive as we know it.


They both happen only in plants.


They both take place in human cells.

Answers

Answer:

2 and 4 are the best answers

Explanation:

Answer:

A and B

Explanation:

Took the k12 test.

Could someone please tell me the name of this branched alkane?

Answers

Answer:

2-Methylhexane

Explanation:

How many Si atoms are there in 1.00 g of silicon

Answers

Number of atoms in 1 g of silicon are 6.022 * 10^23

10. Boron has two naturally occurring isotopes, 10B with an atomic mass of 10.0129370amu and 11Bwith an atomic mass of 11.0093054amu. The atomic mass of boron is 10.81 (from the periodic table). The percent abundances of the boron isotopes are __________% 10Band __________% 11B.

Answers

Explanation:

allowing 20% discount on the market price of a watch the value of the watch will be rs 2376 when a VAT of 10% is added ,find it's market price

Consider the following generic chemical equation.
A+3B→C
What is the limiting reactant when each of the following amounts of A and B are allowed to react?
A. 1 mol A; 4 mol B
B. 2 mol A; 3 mol B
C. 0.5 mol A; 1.6 mol B
D. 24 mol A; 75 mol B

Answers

Answer:

[tex]\fbox{ A) A \: is \: limiting \: reactant }[/tex]

[tex]\fbox{ B) B \: is \: limiting \: reactant }[/tex]

[tex]\fbox{ C) A \: is \: limiting \: reactant }[/tex]

[tex]\fbox{ D) A \: is \: limiting \: reactant }[/tex]

Explanation:

Given equation:

[tex]A+3B \rightarrow \: C [/tex]

To find:

Limiting reactant for corresponding number of moles=?

Solution:

We know that the liming reactant is any atom, ion or molecule which is completely consumed during a reaction and other reactant is still left in reactant vessel.

For the given reaction A+3B→C

for every one mole of A three moles of B are required.

﹌﹌﹌﹌﹌﹌﹌﹌﹌﹌﹌﹌﹌﹌﹌﹌﹌﹌

in A) there is one mole of A and 4 mole of B,

if 1 mole of A will react with 3 moles of B, 1 mole of B will be still there in reaction, the reactant was completely consumed is A which is limiting reactant.

﹌﹌﹌﹌﹌﹌﹌﹌﹌﹌﹌﹌﹌﹌﹌﹌﹌﹌

in B) there is 2 mole of A and 3 mole of B,

if 1 mole of A will react with 3 moles of B, 1 mole of A will be still there in reaction, the reactant was completely consumed is B which is limiting reactant.

﹌﹌﹌﹌﹌﹌﹌﹌﹌﹌﹌﹌﹌﹌﹌﹌﹌﹌

in C) there is 0.5 mole of A and 1.6 mole of B

if one mole of A requires three moles of B to complete the reaction then,

0.5 moles of A will require 1.5 moles of B

if 0.5 mole of A will react with 1.6 moles of B, 0.1 mole of B will be still there in reaction, the reactant was completely consumed is A which is limiting reactant.

﹌﹌﹌﹌﹌﹌﹌﹌﹌﹌﹌﹌﹌﹌﹌﹌﹌﹌

in D) there is 24 mole of A and 72 mole of B

if one mole of A requires three moles of B to complete the reaction then,

24 moles of A will require 72 moles of B.

if 24 mole of A will react with 75 moles of B, 3 mole of B will be left over in reaction, the reactant was completely consumed is A which is limiting reactant.

﹌﹌﹌﹌﹌﹌﹌﹌﹌﹌﹌﹌﹌﹌﹌﹌﹌﹌

[tex]\fbox{ A) A \: is \: limiting \: reactant }[/tex]

[tex]\fbox{ B) B \: is \: limiting \: reactant }[/tex]

[tex]\fbox{ C) A \: is \: limiting \: reactant }[/tex]

[tex]\fbox{ D) A \: is \: limiting \: reactant }[/tex]

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